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POLYNOMIALS by: Ms. P
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Today’s Objectives: Review Classify a polynomial by it’s degree. Review complete a square for a quadratic equation and solve by completing the square
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Degree of a Polynomial The degree of a polynomial is calculated by finding the largest exponent in the polynomial. (Learned in previous lesson on Writing Polynomials in Standard Form)
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Degree of a Polynomial (Each degree has a special “name”) 9
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9 No variable
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degree
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degree
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degree
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1 4 th degree
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1 4 th degreeQuartic
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1 4 th degreeQuartic 2x 5 + 7x 3
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1 4 th degreeQuartic 2x 5 + 7x 3 5 th degree
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1 4 th degreeQuartic 2x 5 + 7x 3 5 th degreeQuintic
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1 4 th degreeQuartic 2x 5 + 7x 3 5 th degreeQuintic 5x n
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Degree of a Polynomial (Each degree has a special “name”) 9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1 4 th degreeQuartic 2x 5 + 7x 3 5 th degreeQuintic 5x n “nth” degree
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9 No variableConstant 8x 1 st degreeLinear 7x 2 + 3x 2 nd degreeQuadratic 6x 3 – 2x 3 rd degreeCubic 3x 4 + 5x – 1 4 th degreeQuartic 2x 5 + 7x 3 5 th degreeQuintic 5x n “nth” degree Degree of a Polynomial (Each degree has a special “name”)
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Let’s practice classifying polynomials by “degree”. POLYNOMIAL 1.3z 4 + 5z 3 – 7 2.15a + 25 3.185 4.2c 10 – 7c 6 + 4c 3 - 9 5.2f 3 – 7f 2 + 1 6.15y 2 7.9g 4 – 3g + 5 8.10r 5 –7r 9.16n 7 + 6n 4 – 3n 2 DEGREE NAME 1.Quartic 2.Linear 3.Constant 4.Tenth degree 5.Cubic 6.Quadratic 7.Quartic 8.Quintic 9.Seventh degree The degree name becomes the “first name” of the polynomial.
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- Completing the Square Objective: To complete a square for a quadratic equation and solve by completing the square
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Steps to complete the square 1.) You will get an expression that looks like this: AX²+ BX 2.) Our goal is to make a square such that we have (a + b)² = a² +2ab + b² 3.) We take ½ of the X coefficient (Divide the number in front of the X by 2) 4.) Then square that number
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To Complete the Square x 2 + 6x Take half of the coefficient of ‘x’ Square it and add it 3 9 x 2 + 6x + 9 = (x + 3) 2
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Complete the square, and show what the perfect square is:
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To solve by completing the square If a quadratic equation does not factor we can solve it by two different methods 1.) Completing the Square (today’s lesson) 2.) Quadratic Formula (Next week’s lesson)
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Steps to solve by completing the square 1.) If the quadratic does not factor, move the constant to the other side of the equation Ex: x²-4x -7 =0 x²-4x=7 2.) Work with the x²+ x side of the equation and complete the square by taking ½ of the coefficient of x and squaring Ex. x² -4x 4/2= 2²=4 3.) Add the number you got to complete the square to both sides of the equation Ex: x² -4x +4 = 7 +4 4.)Simplify your trinomial square Ex: (x-2)² =11 5.)Take the square root of both sides of the equation Ex: x-2 =±√11 6.) Solve for x Ex: x=2±√11
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Solve by Completing the Square +9
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Solve by Completing the Square +121
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Solve by Completing the Square +1
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Solve by Completing the Square +25
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Solve by Completing the Square +16
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Solve by Completing the Square +9
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The coefficient of x 2 must be “1”
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Do you remember : How is the highest (maximum) or lowest point (minimum) of a quadratic function found?
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Using the completing the square form for quadratics:
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