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Inverse Variation 13-7 Warm Up Problem of the Day Lesson Presentation
Course 3 Warm Up Problem of the Day Lesson Presentation
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Inverse Variation 13-7 Warm Up
Course 3 13-7 Inverse Variation Warm Up Find f(–4), f(0), and f(3) for each quadratic function. 1. f(x) = x2 + 4 2. f(x) = x2 3. f(x) = 2x2 – x + 3 20, 4, 13 4, 0, 9 4 1 4 39, 3, 18
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Inverse Variation 13-7 Problem of the Day
Course 3 13-7 Inverse Variation Problem of the Day Use the digits 1–8 to fill in 3 pairs of values in the table of a direct variation function. Use each digit exactly once. The 2 and 3 have already been used. 8 56 1 4 7
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Course 3 13-7 Inverse Variation Learn to recognize inverse variation by graphing tables of data.
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Insert Lesson Title Here
Course 3 13-7 Inverse Variation Insert Lesson Title Here Vocabulary inverse variation
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Inverse Variation INVERSE VARIATION 13-7 Words Numbers Algebra
Course 3 13-7 Inverse Variation INVERSE VARIATION Words Numbers Algebra An inverse variation is a relationship in which one variable quantity increases as another variable quantity decreases. The product of the variables is a constant. k x y = 120 x y = xy = 120 xy = k
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Additional Example 1A: Identify Inverse Variation
Course 3 13-7 Inverse Variation Additional Example 1A: Identify Inverse Variation Determine whether the relationship is an inverse variation. The table shows how 24 cookies can be divided equally among different numbers of students. Number of Students 2 3 4 6 8 Number of Cookies 12 2(12) = 24; 3(8) = 24; 4(6) = 24; 6(4) = 24; 8(3) = 24 xy = 24 The product is always the same. The relationship is an inverse variation: y = . 24 x
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Inverse Variation 13-7 Helpful Hint
Course 3 13-7 Inverse Variation To determine if a relationship is an inverse variation, check if the product of x and y is always the same number. Helpful Hint
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Additional Example 1B: Identify Inverse Variation
Course 3 13-7 Inverse Variation Additional Example 1B: Identify Inverse Variation Determine whether each relationship is an inverse variation. The table shows the number of cookies that have been baked at different times. Number of Students 12 24 36 48 60 Time (min) 15 30 45 75 The product is not always the same. 12(15) = 180; 24(30) = 720 The relationship is not an inverse variation.
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Inverse Variation 13-7 Check It Out: Example 1A
Course 3 13-7 Inverse Variation Check It Out: Example 1A Determine whether the relationship is an inverse variation. x 30 20 15 12 10 y 2 3 4 5 6 30(2) = 60; 20(3) = 60; 15(4) = 60; 12(5) = 60; 10(6) = 60 xy = 60 The product is always the same. The relationship is an inverse variation: y = 60 x
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Inverse Variation 13-7 Check It Out: Example 1B
Course 3 13-7 Inverse Variation Check It Out: Example 1B Determine whether the relationship is an inverse variation. x 2 4 8 1 y 6 The product is not always the same. 2(4) = 8; 2(6) = 12 The relationship is not an inverse variation.
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Additional Example 2A: Graphing Inverse Variations
Course 3 13-7 Inverse Variation Additional Example 2A: Graphing Inverse Variations Create a table. Then graph the inverse variation function. f(x) = 4 x x y –4 –2 –1 1 2 4 –1 –2 –4 – 12 –8 12 8 4 2 1
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Additional Example 2B: Graphing Inverse Variations
Course 3 13-7 Inverse Variation Additional Example 2B: Graphing Inverse Variations Create a table. Then graph the inverse variation function. f(x) = x y –3 –2 –1 1 2 3 –1 x 1 3 1 2 1 – 12 2 12 –2 –1 1 2 – 1 3 –
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Inverse Variation 13-7 Check It Out: Example 2A
Course 3 13-7 Inverse Variation Check It Out: Example 2A Create a table. Then graph the inverse variation function. f(x) = – 4 x x y –4 –2 –1 1 2 4 1 2 4 – 12 8 12 –8 –4 –2 –1
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Inverse Variation 13-7 Check It Out: Example 2B
Course 3 13-7 Inverse Variation Check It Out: Example 2B Create a table. Then graph the inverse variation function. f(x) = 8 x x y –8 –4 –2 –1 1 2 4 8 –1 –2 –4 –8 8 4 2 1
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Volume of Gas by Pressure on Gas
Course 3 13-7 Inverse Variation Additional Example 3: Application As the pressure on the gas in a balloon changes, the volume of the gas changes. Find the inverse variation function and use it to find the resulting volume when the pressure is 30 lb/in2. Volume of Gas by Pressure on Gas Pressure (lb/in2) 5 10 15 20 Volume (in3) 300 150 100 75 You can see from the table that xy = 5(300) = 1500, so y = 1500 x If the pressure on the gas is 30 lb/in2, then the volume of the gas will be y = 1500 ÷ 30 = 50 in3.
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Number of Students by Cost per Student
Course 3 13-7 Inverse Variation Check It Out: Example 3 An eighth grade class is renting a bus for a field trip. The more students participating, the less each student will have to pay. Find the inverse variation function, and use it to find the amount of money each student will have to pay if 50 students participate. Number of Students by Cost per Student Students 10 20 25 40 Cost per student 8 5 You can see from the table that xy = 10(20) = 200, so y = 200 x If 50 students go on the field trip, the price per student will be y = 200 50 = $4.
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Insert Lesson Title Here
Course 3 13-7 Inverse Variation Insert Lesson Title Here Lesson Quiz: Part I Tell whether each relationship is an inverse variation. 1. 2. yes no
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Insert Lesson Title Here
Course 3 13-7 Inverse Variation Insert Lesson Title Here Lesson Quiz: Part II 1 4x 3. Graph the inverse variation function f(x) =
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