1. 6.6 : General Form of the Equation for a Linear Relation
Linear Functions
6.6 : General Form of the Equation
for a Linear Relation

2. Today’s Objectives
Relate linear relations expressed in: slope-intercept form, general form, and slope-point form to their graphs, including:
Express a linear relation in different forms, and compare graphs
Rewrite a linear relation in either slope-intercept or general form
Graph, with or without technology, a linear relation in slope-intercept, general, or slope-point form
Identify equivalent linear relations from a set of linear relations
Match a set of linear relations to their graphs

3. Equations of a Linear Function
We can make an equation that describes a line’s location on a graph. This is called a linear equation. There are three forms of linear equation that we will be looking at:
Standard Form: Ax + By + C = 0, where A, B, and C are integers.
Slope y-intercept form: y = mx + b, where m is the slope, and b is the y-intercept.
Slope-point form: y – y1 = m(x – x1), where m is the slope, and the line passes through a point located at (x1, y1)

4. General form (or standard form)
Another form for the equation of a linear function is general form, or standard form:
𝑨𝒙 + 𝑩𝒚 + 𝑪 = 𝟎
In certain situations you will be asked to change the equation from slope y-intercept form into general form, and vice versa.
When converting the equation into standard form, we must remember that A, B, and C, MUST be integers, which means all fractions need to be removed. We also need to remember to move all terms to the same side of the equation to make it equal to zero.

5. Example
Write the following in general form: y – 1 = 2/3(x + 2) Multiply both sides by 3: 3(y – 1) = 2(x+2) Expand: 3y – 3 = 2x + 4 Make equation = 0 3y – 2x – 7 = 0 Collect Like Terms Arrange in proper order -2x + 3y – 7 = 0

6. Example
Write the following in general form: y + 2 = 3/5(x - 4) Multiply both sides by 5 5y + 10 = 3(x – 4) Remove the brackets 5y + 10 = 3x – 12 Collect all terms on one side of the equation 5y = 3x – 12 – 10 0 = 3x – 5y - 22

7. What does the graph look like?
A=0 Ax + By + C = 0 By + C = 0 y = -C/B Since –C/B is a constant, the graph will be a horizontal line B=0 Ax + By + C = 0 Ax + C = 0 x = -C/A Since –C/A is a constant, the graph will be a vertical line

8. Example
Graph the line 2x – 5y – 10 = 0 Determine the x-intercept Determine the y-intercept Let y=0 and solve for x Let x=0 and solve for y 2x – 5(0) – 10 = 0 2(0) – 5y – 10 = 0 2x – 10 = 0 -5y – 10 = 0 2x = 10 -5y = 10 x = 5 y = -2 (5,0) (0,-2) Plot the points and draw a line through them.

9. Example
Determine the slope of 2x – 5y – 10 = 0 Rewrite the equation in slope-interval form: 2x – 5y – 10 = 0 solve for y -5y = -2x + 10 y = -2x y = -2x/ /-5 y = 2/5x – 2 m = 2/5

10. Example
Determine the slope of -3x – 2y – 16 = 0 Rewrite the equation in slope-interval form: -3x – 2y – 16 = 0 solve for y -2y = 3x + 16 y = 3x y = 3x/ /-2 y = -3/2x – 8 m = -3/2