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May 1, 2013 AGENDA: 1 – Bell Ringer & Part. Log 2 – Review HW 3 – Demo: Boyle’s Law 4 - CN: Charles’ Law 5 – Practice Problems 6 – Demo: Charles’ Law 7 – Work Time Today’s Goal: Students will be able to calculate using Charles’ Law. Homework 1. Charles’ Law 2. Work from Week 32 is due by Friday. 3. Make up Week 32 Quiz by Friday.
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Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 5 minutes!
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4 MINUTES REMAINING…
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Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 4 minutes!
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3 MINUTES REMAINING…
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Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 3 minutes!
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2 MINUTES REMAINING…
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Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 2 minutes!
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1minute Remaining…
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Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 1 minute!!!
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30 Seconds Remaining…
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Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 30 seconds!!!
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BELL- RINGER TIME IS UP!
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May 1, 2013 AGENDA: 1 – Bell Ringer & Part. Log 2 – Review HW 3 – Demo: Boyle’s Law 4 - CN: Charles’ Law 5 – Practice Problems 6 – Demo: Charles’ Law 7 – Work Time Today’s Goal: Students will be able to calculate using Charles’ Law. Homework 1. Charles’ Law 2. Work from Week 32 is due by Friday. 3. Make up Week 32 Quiz by Friday.
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Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. REVIEW
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REVIEW HOMEWORK Kinetic Molecular Theory and Boyle’s Law
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Demonstrations of Boyle’s Law Stay Puft Marshmallow Man in a vacuum… http://www.youtube.com/watch?v=27yqJ9vJ5kQ http://www.youtube.com/watch?v=27yqJ9vJ5kQ What happens to lungs when diving underwater? Underwater demo: http://www.youtube.com/watch?v=t8wFIMbMJvs Lab explanation demo: http://www.youtube.com/watch?v=hXnkJNk45Ek Discussion: How do your lungs work?
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Topic: Charles’ Law Date: 5/1/2013 Charles’ Law = For a given amount of gas at a constant pressure, the VOLUME of the gas is directly related to TEMPERATURE. So if: T ↑ = V ↑ T ↓ = V ↓ T α V 1.Compare 2.Formulate 3.Support Temperature Volume Constant Pressure
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Topic: Charles’ Law Date: 5/1/2013 Variables & Units: V = Volume (mL, L) T = Temperature (K = Kelvin) You must convert ° C to K before you calculate further! To convert degrees Celsius to Kelvin: Temp. in K = ° C + 273 Example: What is 25 ° C in K temp.? Temp. in K = 25 ° C + 273 Temp. in K = 298 K 1.Compare 2.Formulate 3.Support
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Topic: Charles’ Law Date: 5/1/2013 Equation: 1.Compare 2.Formulate 3.Support V 1 = V 2 T 1 T 2 V 1 T 2 = V 2 T 1 Notice subscripts are different on each side! Notice subscripts are different on each side!
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Practice Problem A balloon is at RT (25 ° C). The volume of the balloon is 2.0L. The balloon is then taken outside to a temperature of -5 ° C. What is the new volume of the balloon? 3 rd Calculate: V 1 T 2 = V 2 T 1 (2)(268)=(V 2 )(298) 536 = V 2 (298) 298 298 V 2 = 536/298 V 2 = 1.8L 2 nd Determine Variables: V 1 = T 1 = V 2 = T 2 = 1 st Predict: If T ↓, then V ↓. 25 ° C 2.0L -5 ° C ? = x +273=298K +273=268K Convert to K!
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Demonstrations of Charles’ Law Balloon fun with liquid nitrogen… http://www.youtube.com/watch?v=ZgTTUuJZAFs http://www.youtube.com/watch?v=ZgTTUuJZAFs Balloon fun with boiling water… http://www.youtube.com/watch?v=GcCmalmLTiU http://www.youtube.com/watch?v=GcCmalmLTiU Discussion: How do hot air balloons work?
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