1. Solubility curves

2. Class data Write down the data & answer questions on bottom of the sheet MassTempMassTemp 3030 1035 1540 204587 255093 MassTempMassTemp 303069 10283576 1540 83 20524587 25605093

4. Results of lab: solubility of KClO 3 Unsaturated Saturated 3a i) 7 iii) unsaturated ii) 14 iii) 24 - 25 3bi) 30°C ii) 3°C iii) 48°C 4i) saturated ii) unsaturated KNO 3 Supersaturated 4 i) 4 ii) 4iii)

5. Saturation and solubility curves In this experiment we expressed concentration in units of g solute / g H 2 O Putting concentrations in g solute / g solution would be tedious and impractical See Fig 2 on pg. 316 Notice that there are solubility curves for many different substances Q - Why do temperatures range from 0-100°C A - Water is a liquid at these temperatures Solubility curves tell us how much solid will dissolve at a given temperature They also allow certain calculations…

6. Calculations using solubility curves Using fig 2 (pg. 316) 5. 100 g H 2 O is saturated with KClO 3 at 100°C. How much KClO 3 will come out of solution if the temperature is decreased to 48°C? How much would precipitate under the same circumstances if 350 g water were used 6. 57 g - 18 g = 39 g (57 g - 18 g) x 3.5 = 137 g (85 g - 21 g) x 1.5 = (64 g) x 1.5 = 96 g For more lessons, visit www.chalkbored.com www.chalkbored.com