Download presentation
Presentation is loading. Please wait.
Published byChester Tucker Modified over 9 years ago
1
EXAMPLE 4 Use an infinite series as a model Pendulums A pendulum that is released to swing freely travels 18 inches on the first swing. On each successive swing, the pendulum travels 80% of the distance of the previous swing. What is the total distance the pendulum swings?
2
EXAMPLE 4 Use an infinite series as a model The total distance traveled by the pendulum is: d = 18 + 18(0.8) + 18(0.8) 2 + 18(0.8) 3 + · · · a1a1 1 – r = = 90 18 1 – 0.8 = Write formula for sum. Substitute 18 for a 1 and 0.8 for r. Simplify. The pendulum travels a total distance of 90 inches, or 7.5 feet. ANSWER SOLUTION
3
EXAMPLE 5 Write a repeating decimal as a fraction Write 0.242424... as a fraction in lowest terms. 0.242424... = 24(0.01) + 24(0.01) 2 + 24(0.01) 3 + · · · a1a1 1 – r = 24(0.01) 1 – 0.01 = 0.24 0.99 = 24 99 = 8 33 = Write formula for sum. Substitute 24(0.01) for a 1 and 0.01 for r. Simplify. Write as a quotient of integers. Reduce fraction to lowest terms. The repeating decimal 0.242424... is 8 33 as a fraction. ANSWER
4
GUIDED PRACTICE for Examples 4 and 5 5. WHAT IF? In Example 4, suppose the pendulum travels 10 inches on its first swing. What is the total distance the pendulum swings? SOLUTION The total distance traveled by the pendulum is: d = 10 + 10(0.8) + 10(0.8) 2 + 10(0.8) 3 + · · · a1a1 1 – r = 10 1 – 0.8 = = 10 0.2 = 50 inches
5
GUIDED PRACTICE for Examples 4 and 5 Write the repeating decimal as a fraction in lowest terms. 6. 0.555... SOLUTION 0.555... = 55(0.01) + 55(0.01) 2 + 55(0.01) 3 + · · · a1a1 1 – r = 55(0.01) 1 – 0.01 = 0.55 0.99 = 5 9 =
6
GUIDED PRACTICE for Examples 4 and 5 Write the repeating decimal as a fraction in lowest terms. 7. 0.727272... SOLUTION 0.727272... = 72(0.01) + 72(0.01) 2 + 72(0.01) 3 + · · · a1a1 1 – r = 0.72 0.99 = 72(0.01) 1 – 0.01 = = 72 99 8 11 =
7
GUIDED PRACTICE for Examples 4 and 5 Write the repeating decimal as a fraction in lowest terms. 8. 0.131313... SOLUTION 0.131313... = 13(0.01) + 13(0.01) 2 + 13(0.01) 3 + · · · a1a1 1 – r = 0.13 0.99 = 13(0.01) 1 – 0.01 = = 13 99
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.