1. Homework 2 SOLUTIONS 100V C 2 5uF C 1 3uF C 3 7.5uF SINCE CAPS ARE IN SERIES C T CAN BE FOUND USING; THE CHARGE STORED IN EACH CAP IS THE SAME 100V C T 1.5uF 1. Given 3 capacitors in series. Find Ct, Vc 1, Vc2, Vc3, Qt HINT: Qt =Q1 =Q2 =Q3, Q is the charge on each capacitor

2. EACH CAPACITOR COULD ALSO BEEN FOUND USING: SO C1 WOULD BE; 2.Homework 2 SOLUTIONS C 1 10uFC2 20uFC3 50uF FOR EACH CAP:

3. 2. GIVEN 3 CAPACITORS IN PARALLEL: FIND C T C 1 10uF C2 20uFC3 50uF FOR A PARALLEL CIRCUIT CAPCITANCE IS ADDITIVE, SO C T 80uF Homework 2 SOLUTIONS

4. R1R1 R2R2 R3R3 R4R4 R5 R6R6 R9R9 R8R8 R7R7 RTRT R 1 = 15Ω R 2 = 35Ω R 3 = 50Ω R 4 = 40Ω R 5 = 30Ω R 6 = 25Ω R 7 = 10Ω R 8 = 300Ω R 9 = 60Ω CONST 150 Homework 2 3. FIND R T FOR THIS CIRCUIT R1R1 R2R2 R6R6 R7R7 RTRT R 9 60Ω R 3,4,5 120Ω 10Ω 25Ω 300Ω 15Ω 35Ω STEP 1:FIND SERIES COMBINATION OF R3 +R4+R5 STEP 2: FIND R EQ FOR THE TWO RESISTORS IN PARALLEL R8R8

5. R1R1 R2R2 R eq R6R6 R8R8 R7R7 RTRT 40Ω 25Ω35Ω 10Ω15Ω 300Ω AGAIN 3 RESISTORS IN SERIES CONST 150 Homework 2 3. FIND R T FOR THIS CIRCUIT

6. R1R1 R8R8 R7R7 RTRT 10Ω 15Ω 300Ω R eq2 100Ω R1R1 R7R7 RTRT 10Ω 15Ω R eq 75Ω AGAIN 3 RESISTORS IN SERIES CONST 150 Homework 2 3. FIND R T FOR THIS CIRCUIT