1. 2.1 - 1 Copyright © 2013, 2009, 2005 Pearson Education, Inc. 1 2 Graphs and Functions Copyright © 2013, 2009, 2005 Pearson Education, Inc.

2. 2 2.1 Rectangular Coordinates and Graphs Ordered Pairs The Rectangular Coordinate System The Distance Formula The Midpoint formula Graphing Equations in Two Variables

3. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 3 Ordered Pairs An ordered pair consists of two components, written inside parentheses.

4. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 4 Example 1 WRITING ORDERED PAIRS Category Amount Spent food$6443 housing$17,109 transportation$8604 health care$2976 apparel and services $1801 entertainment$2835 Use the table to write ordered pairs to express the relationship between each category and the amount spent on it.

5. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 5 Example 1 WRITING ORDERED PAIRS Solution (a) housing Use the data in the second row: (housing, $17,109). Category Amount Spent food$6443 housing$17,109 transportation$8604 health care$2976 apparel and services $1801 entertainment$2835

6. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 6 Example 1 WRITING ORDERED PAIRS Solution (b) entertainment Use the data in the last row: (entertainment, $2835). Category Amount Spent food$6443 housing$17,109 transportation$8604 health care$2976 apparel and services $1801 entertainment$2835

7. 2.1 - 7 Copyright © 2013, 2009, 2005 Pearson Education, Inc. 7 The Rectangular Coordinate System Quadrant I Quadrant II Quadrant III Quadrant IV 0 x-axis y-axis a b P(a, b)

8. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 8 The Distance Formula Using the coordinates of ordered pairs, we can find the distance between any two points in a plane. P(– 4, 3) Q(8, 3) R(8, – 2) Horizontal side of the triangle has length Definition of distance x y

9. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 9 The Distance Formula P(– 4, 3) Q(8, 3) R(8, – 2) Vertical side of the triangle has length x y

10. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 10 The Distance Formula P(– 4, 3) Q(8, 3) R(8, – 2) By the Pythagorean theorem, the length of the remaining side of the triangle is x y

11. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 11 The Distance Formula P(– 4, 3) Q(8, 3) R(8, – 2) So the distance between (– 4, 3) and (8, – 2) is 13. x y

12. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 12 The Distance Formula To obtain a general formula for the distance between two points in a coordinate plane, let P(x 1, y 1 ) and R(x 2, y 2 ) be any two distinct points in a plane. Complete a triangle by locating point Q with coordinates (x 2, y 1 ). The Pythagorean theorem gives the distance between P and R. P(x 1, y 1 ) Q(x 2, y 1 ) R(x 2, y 2 ) x y

13. 2.1 - 13 Copyright © 2013, 2009, 2005 Pearson Education, Inc. 13 Distance Formula Suppose that P(x 1, y 1 ) and R(x 2, y 2 ) are two points in a coordinate plane. The distance between P and R, written d(P, R) is given by

14. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 14 Example 2 USING THE DISTANCE FORMULA Solution Find the distance between P(– 8, 4) and Q(3, – 2.) Be careful when subtracting a negative number.

15. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 15 Using the Distance Formula If the sides a, b, and c of a triangle satisfy a 2 + b 2 = c 2, then the triangle is a right triangle with legs having lengths a and b and hypotenuse having length c.

16. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 16 Example 3 APPLYING THE DISTANCE FORMULA Are points M(– 2, 5), N(12, 3), and Q(10, – 11) the vertices of a right triangle? Solution A triangle with the three given points as vertices is a right triangle if the square of the length of the longest side equals the sum of the squares of the lengths of the other two sides.

17. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 17 Example 3 APPLYING THE DISTANCE FORMULA

18. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 18 Example 3 APPLYING THE DISTANCE FORMULA

19. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 19 Example 3 APPLYING THE DISTANCE FORMULA

20. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 20 Example 3 The longest side, of length 20 units, is chosen as the possible hypotenuse. Since is true, the triangle is a right triangle with hypotenuse joining M and Q. APPLYING THE DISTANCE FORMULA

21. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 21 Collinear Points We can tell if three points are collinear, that is, if they lie on a straight line, using a similar procedure. Three points are collinear if the sum of the distances between two pairs of points is equal to the distance between the remaining pair of points.

22. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 22 Example 4 APPLYING THE DISTANCE FORMULA Are the points P(– 1, 5), Q(2, – 4), and R(4, – 10) collinear? Solution

23. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 23 Example 4 APPLYING THE DISTANCE FORMULA Are the points P(– 1, 5), Q(2, – 4), and R(4, – 10) collinear? Solution

24. 2.1 - 24 Copyright © 2013, 2009, 2005 Pearson Education, Inc. 24 Midpoint Formula The midpoint M of the line segment with endpoints P(x 1, y 1 ) and Q(x 2, y 2 ) has the following coordinates.

25. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 25 Example 5 USING THE MIDPOINT FORMULA Use the midpoint formula to do each of the following. Solution (a) Find the coordinates of the midpoint M of the segment with endpoints (8, – 4) and (– 6,1). Substitute in the midpoint formula.

26. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 26 Example 5 USING THE MIDPOINT FORMULA Use the midpoint formula to do each of the following. (b) Find the coordinates of the other endpoint Q of a segment with one endpoint P(– 6, 12) and midpoint M(8, – 2). Let (x, y) represent the coordinates of Q. Use the midpoint formula twice. Solution

27. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 27 Example 5 USING THE MIDPOINT FORMULA x-value of Px-value of M Substitute carefully. x-value of Py-value of M The coordinates of endpoint Q are (22, – 16).

28. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 28 Example 6 APPLYING THE MIDPOINT FORMULA The following figure depicts how a graph might indicate the increase in the revenue generated by fast-food restaurants in the United States from $69.8 billion in 1990 to $164.8 billion in 2010. Use the midpoint formula and the two given points to estimate the revenue from fast- food restaurants in 2000, and compare it to the actual figure of $107.1 billion.

29. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 29 Example 6 APPLYING THE MIDPOINT FORMULA

30. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 30 Example 6 APPLYING THE MIDPOINT FORMULA Solution The year 2000 lies halfway between 1990 and 2010, so we must find the coordinates of the midpoint of the segment that has endpoints (1990, 69.8) and (2010, 164.8). Thus, our estimate is $117.3 billion, which is greater than the actual figure of $107.1 billion.

31. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 31 Example 7 FINDING ORDERED-PAIR SOLUTIONS OF EQUATIONS For each equation, find at least three ordered pairs that are solutions Solution Choose any real number for x or y and substitute in the equation to get the corresponding value of the other variable. (a)

32. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 32 Example 7 FINDING ORDERED-PAIR SOLUTIONS OF EQUATIONS Solution (a) Let x = – 2. Multiply. Let y = 3. Add 1. Divide by 4. This gives the ordered pairs (– 2, – 9) and (1, 3). Verify that the ordered pair (0, –1) is also a solution.

33. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 33 Example 7 FINDING ORDERED-PAIR SOLUTIONS OF EQUATIONS Solution (b) Given equation Let x = 1. Square each side. One ordered pair is (1, 2). Verify that the ordered pairs (0, 1) and (2, 5) are also solutions of the equation. Add 1.

34. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 34 Example 7 FINDING ORDERED-PAIR SOLUTIONS OF EQUATIONS Solution (c) A table provides an organized method for determining ordered pairs. Five ordered pairs are (–2, 0), (–1, –3), (0, –4), (1, –3), and (2, 0). xy – 2– 20 – 1– 1– 3– 3 0– 4– 4 1– 3– 3 20

35. 2.1 - 35 Copyright © 2013, 2009, 2005 Pearson Education, Inc. 35 Graphing an Equation by Point Plotting Step 1 Find the intercepts. Step 2 Find as many additional ordered pairs as needed. Step 3 Plot the ordered pairs from Steps 1 and 2. Step 4 Join the points from Step 3 with a smooth line or curve.

36. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 36 Step 1 Let y = 0 to find the x-intercept, and let x = 0 to find the y-intercept. Example 8 GRAPHING EQUATIONS (a) Graph the equation Solution These intercepts lead to the ordered pairs

37. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 37 Step 2 We find some other ordered pairs (also found in Example 7(a)). Example 8 GRAPHING EQUATIONS (a) Graph the equation Solution Let x = – 2. Multiply. Let y = 3. Add 1. Divide by 4. This gives the ordered pairs (– 2, – 9) and (1, 3).

38. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 38 Step 3 Plot the four ordered pairs from Steps 1 and 2. Example 8 GRAPHING EQUATIONS (a) Graph the equation Solution Step 4 Join the points with a straight line.

39. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 39 Example 8 GRAPHING EQUATIONS (b) Graph the equation Solution Plot the ordered pairs found in Example 7b, and then join the points with a smooth curve. To confirm the direction the curve will take as x increases, we find another solution, (3, 10).

40. Copyright © 2013, 2009, 2005 Pearson Education, Inc. 40 Example 8 GRAPHING EQUATIONS (c) Graph the equation Solution Plot the points and join them with a smooth curve. xy – 2– 20 – 1– 1– 3– 3 0– 4– 4 1– 3– 3 20 This curve is called a parabola.