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Final Exam Key Concepts
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Vertical Angles Find the value of “x”. 68 = 2x + 32 36 = 2x 18 = x
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Segments and Lengths In the diagram, and S is the midpoint of QR = 4, and ST = 5. Find the following values. RS = PR = PQ = 5 P Q R S T 10 6
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Parallel Lines Find the missing values. 70o 70o 110o
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Straight Line is 180o Find the difference between the larger angle and the smaller angle. 3x + (4x + 19) = 180 7x + 19 = 180 7x =161 x =23 3(23) = 69 and 4(23) + 19 = 111 111 – 69 = 42
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Angles of Triangle = 180o 1x + 2x + 3x = 180 6x = 180 x = 30
The angles of a triangle are in the ratio of 1:2:3. Find the measure of each angle. 1x + 2x + 3x = 180 6x = 180 x = 30 30o, 60o, 90o
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Exterior Angle Theorem
Find the missing value. 35o + 25o = 60o 60o
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Angles and Sides of a Triangle
Remember, largest angle is OPPOSITE of longest side…. And smallest angle is OPPOSITE of smallest side.
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TRIANGLE INEQUALITY THEOREM
The sum of the lengths of any two sides of a triangle is greater than the length of the third side. Is it possible for a triangle to have the following lengths? 3, 6, 8 6 + 3 = 9 > 8 YES
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Three Theorems about Triangles
If c2 = a2 + b2, then the triangle is a right triangle. If c2 < a2 + b2, then the triangle is an acute triangle. If c2 > a2 + b2, then the triangle is an obtuse triangle. 12
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RIGHT TRIANGLES
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Special Right Triangles
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Pythagorean Theorem = x2 = x2 85 = x2
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Pythagorean Triples 3, 4, 5 5, 12, 13 8, 15, 17 7, 24, 25
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Quadrilaterals
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Quadrilaterals Complete the worksheet.
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5 Ways to Prove Parallelograms
Both pairs of opposite sides are parallel Both pairs of opposite sides are congruent Both pairs of opposite angles are congruent One pair of opposite sides congruent and parallel Diagonals bisect each other.
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SUM of the INTERIOR Measures of Any Polygon
(n – 2)180o (8-2)180o = 1080o (4-2)180o = 360o
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Sum of the measures of the EXTERIOR angles of any polygon
h + o + r + s + e = 360o c + r + a + p = 360o
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A polygon that is both equilateral and equiangular.
REGULAR POLYGON A polygon that is both equilateral and equiangular.
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Areas
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Circles
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Angles in a Circle 80o 50o 50o 30o
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Lengths in a Circle 12(9) = 18x 108 = 18x 6 = x
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Lengths in a Circle 3(8) = 2(12) 24 = 24
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Lengths in a Circle 122 = x(x+12+x) 144 = 2x2 + 12x x = 8
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SAT Formulas
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