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1 ACID- BASE EQUILIBRIA ACID- BASE EQUILIBRIA ACID- BASE EQUILIBRIA ACID- BASE EQUILIBRIA
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LEWIS ACIDS & BASES ACID = ELECTRON PAIR ACCEPTOR BASE = ELECTRON PAIR DONOR MUST HAVE AN UNSHARED PAIR OF ELECTRONS TO DONATE TO THE COVALENT BOND BETWEEN THE ACID AND BASE H + + NH 3 NH 4 1+ H + + H N H H : H N H H + Al 3+ + 6 H 2 O Al(H 2 O) 6 H 2 O + SO 3 H 2 SO 4 BF 3 + NH 3 BF 3 - NH 3
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BRONSTED - LOWRYBRONSTED ACIDS AND BASES SPECIAL CASE OF THE LEWIS ACID-BASE THEORY ACID IS A PROTON DONOR H+H+ BASE IS A PROTON ACCEPTOR MUST HAVE UNSHARED PAIR OF ELECTRONS O + NH 3 o C H3CH3C O O H o C H3CH3C O o - + THAT IS, MUST BE A LEWIS BASE ACID - BASE REACTION NEUTRALIZATION PROTON BOUND TO A VERY ELECTRONEGATIVE ATOM NOT AN ACID PROTON
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ACID: ARRHENIUS: PRODUCES H 1+ IN WATER BASE: ARRHENIUS: PRODUCES OH 1- IN WATER BRONSTED: PROTON DONOR BRONSTED: PROTON ACCEPTOR LEWIS: HAS EMPTY ORBITAL LEWIS: HAS e - PAIR AVAILABLE TO SHARE + SALT + WATER NEUTRALIZATION DIFFERENCE: BRONSTED ACID HAS A PROTON!
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NAMING ACIDS BINARY: UNLESS DISSOLVED IN WATER -- COVALENT HBr HYDROGENHYDROBROMIDEBROMIC HYDROBROMICACID HF HI HYDROFLUORIC ACID HYDROIODIC ACID POLYATOMIC ANIONS -ITE = OUS OR -ATE = IC EXCEPTING S OR P CO 3 2- CARBONATE ION H 2 CO 3 IC ACID SO 4 2- = SULFATE ION H 2 SO 4 = SULFURIC ACID SO 3 2- = SULFITE ION H 2 SO 3 = SULFUROUS ACID
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ACID BASE ACID CONJUGATE BRONSTED ACID-BASE CONJUGATE PAIRS HCOOH (aq) + H 2 O (l) HCOO 1- (aq) + H 3 O 1+ (aq ) HOBr (aq) + H 2 O (l) OBr 1- (aq) + H 3 O 1+ (aq ) CONJUGATE CONJUGATE PAIRS DIFFER BY A SINGLE PROTON!!! O + NH 3 o C H3CH3C O O H o C H3CH3C O o - +
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CH 3 COOH (aq) + NH 3 (aq) CH 3 COO 1- (aq) + (aq) a IF K >> 1, DISSOCIATION IS EXTENSIVE REACTION IS EXTENSIVE IF K << 1, DISSOCIATION IS NOT EXTENSIVE THE LARGER THE VALUE OF K, THE MORE EXTENSIVE IS THE REACTION
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H 2 S (aq) + H 2 O (l) HS 1- (aq) + H 3 O 1+ (aq) K = [HS 1- ] [H 3 O 1+ ] [ H 2 S] a K b = 1 X 10 -14 / K a THE LARGER THE VALUE OF K, THE STRONGER IS THE ACID OR THE BASE FOR ACID: THE MORE H 3 O 1+ ION IS PRODUCED FROM ACID - BASE CHART: HIGH K a + HIGH K b = EXTENSIVE REACTION RESULT: K>1 IF PRODUCT IS THE WEAKER ACID OR BASE OF THE CONJUGATE PAIR
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ACID-BASE STRENGTH BINARY HA STRENGTH OF THE HA BOND ELECTRONEGATIVITY OF A OXOACID (OXYANION) X - O - H OXIDATION STATE OF X ELECTRONEGATIVITY OF X USUALLY: STRONGER BOND = WEAKER ACID RESULT: K>1 IF PRODUCT IS THE WEAKER ACID OR BASE OF THE CONJUGATE PAIR
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H 2 O (l) + H 3 0 1+ WEAK ACID: K a < K a FOR H 3 O 1+ K a << 1 STRONG ACIDS: HX WHERE X = Cl, Br, I HNO 3, HClO 4, H 2 SO 4 WEAK BASE: K b < K a FOR H 3 O 1+ K b << 1 STRONG BASE:SOLUBLE METAL HYDROXIDE
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H 2 O (l) + H 2 O (l) H 3 O 1+ (aq) + OH 1- (aq) K = K w = [H 3 O 1+ ][OH 1- ]= 1.0 x 10 -14 AT 25 o C [H 3 O 1+ ] > [OH 1- ] ACIDIC SOLUTION [H 3 0 1+ ] = [OH 1- ] NEUTRAL SOLUTION [H 3 O 1+ ] < [OH 1- ] BASIC SOLUTION [H 3 O 1+ ] = [OH 1- ] = 1.0x10 -7 M pH = -log [H 3 O 1+ ] <7 = 7 >7 pK = -logK a -log[1.0x10 -7 ] pK a + pK b = 14pH + pOH = 14K a x K b = 1.0 x 10 -14
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024 6 7 8 10 12 14 141210 8 7 6 42 0 pOH pH Scales to determine Acidity or Alkalinity
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0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 NEUTRAL ACIDIC BASIC GASTRIC JUICE, 0.1 M HCl ORANGE JUICE COKE, VINEGAR WINE TOMATO, BEER BLACK COFFEE RAIN SALIVAURINE HUMAN MILK BLOOD, TEARS SEAWATER, EGG WHITE BILE BAKING SODA BORAX NAIR HOUSEHOLD AMMONIA DRAIN CLEANER, 0.1 M NaOH
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14 WHAT IS THE pH of: A. SOLUTION WHERE [H 3 O 1+ ] = 3.6x10 -6 M B. 0.25 M HCl C. SOLUTION WHERE [OH 1- ] = 2.5x10 -3 M WHAT IS THE [OH 1- ] CONC. OF A pH = 4.5 SOLUTION? pH =-log[H 3 O 1+ ] K w = [H 3 O 1+ ][OH 1- ] = 1.0 x 10 -14 A. pH = - LOG[3.6x10 -6 ]= 5.4(AN ACIDIC SOLUTION) B. pH = -LOG[0.25] = 0.60 C.[H 3 O 1+ ] [2.5x10 -3 ] = 1.0x10 -14 = 4.0x10 -12 pH = -LOG[4.0x10 -12 ] = 11.4 (A BASIC SOLUTION) [3.2x10 -5 ][OH 1- ] = 1.0 x 10 -14 [H 3 O 1+ ] = 10 -pH = 10 -4.5 = 3.2x10 -5 = 3.1x10 -10 M
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[H + ]pH[OH - ]pOH Acid, Base or Neutral 10 -9 10 -4 8 9 10 -7 6 5
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Titration Sample problem What volume of 1.0 M HCl is needed to neutralize 30.0 mL of 2.5 M NaOH?
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Try These: What is the molarity of 5.0 mL of acid used to neutralize 10.0 mL of 2.5 M base? What volume of 1.0 M base is needed to neutralize 20.0 mL of 2.3 M acid?
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