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Student Name (Chinese Characters): 黃彥銘 Student ID Number: 9631033 Student Name (Chinese Characters): 林韋君 Student ID Number: 9631010 Student Name (Chinese.

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Presentation on theme: "Student Name (Chinese Characters): 黃彥銘 Student ID Number: 9631033 Student Name (Chinese Characters): 林韋君 Student ID Number: 9631010 Student Name (Chinese."— Presentation transcript:

1 Student Name (Chinese Characters): 黃彥銘 Student ID Number: 9631033 Student Name (Chinese Characters): 林韋君 Student ID Number: 9631010 Student Name (Chinese Characters): 李春霈 Student ID Number: 9631011 Student Name (Chinese Characters): 郭曉蓉 Student ID Number: 9631013 Student Name (Chinese Characters): 張欣怡 Student ID Number: 9631052

2 Introduction  Introduction  Problem  Conference Item  Hypotheses  Methodologies-Excel 、 Minitab  Data analysis  Conclusion Outline

3 Introduction  Xiang-Si bean curd pudding store is located in Dorm- Female-2 restaurant in NCTU  It provides different kinds of drinks and sweets such as bean curd pudding, shaved ice and sweet soup Introduction

4  One of the workers, named aunt Chen-Jun, in the store is so nice and is voted to be the most famous person in NCTU  The reporter in TTV even came to do an interview with her and promoted this store on TV Introduction

5  Although the store already had been promoted on TV news, the sales amount of the store just keeps in a “good” level, not in an “excellent” level. Problem

6  We want to try to use our “Point Credit Card” to see if it can stimulate consumers and make them buy product from the store.  we probe into the principal factors of the stamps whether influence the customer purchasing behavior or not. Conference Item

7 The amount of cash to get one point affects consumer’s behavior. The amount of cash to get one point affects consumer’s behavior. Among the three alternatives : ”twenty dollars”, ”twenty-five dollars”, and” thirty dollars”, we suppose that twenty-five dollars is the highest limit for a consumer to get one point. The period of activity does affects consumer’s behavior. Hypotheses

8 The period of activity does affects consumer’s behavior. Among the three alternatives : ”two weeks”, ” one month”, and” two months”, we suppose that one month is the shortest limit that consumers could accept for the activity. The amount of points to get the banana boat affects consumer’s behavior.

9 The amount of points to get the banana boat affects consumer’s behavior. Among the three alternatives : ”ten points”, ”fifteen points”, and” twenty points”, we suppose that twenty points are the highest limit for consumers to attend the activity. The characteristic that banana boat is just sent for consumers finishing the points credit card and not for sale affects consumer’s behavior. Hypotheses

10  First step-we input the collecting data to the Microsoft Excel.  Second step-we use Excel to calculate the individual percentage of the four factors that we have assumed in the beginning and the amount of the survey candidates’ agreement or disagreement. After inputting those data, we will have some pie charts. Methodologies- Excel

11  Third step-we can make use of the pie charts to do the statistic analyses by comparing between the four factors and we will find out which factor influences customers’ behavior most and the relationship among the factors. Methodologies- Excel

12  First step-we choose the “Stat” on the tool bar and select “Basic Statistics”, “2 proportions”, and “Summarized data”.  Second step-under the “Summarized data”, we fill out the relating data in “First sample” and “Second sample”. Methodologies- Minitab

13  Third step-we The “Option” sub dialog box gives us a chance to specify the confidence level (95.0), test proportion (0.05), alternative hypothesis (greater than), and whether Minitab should use a pooled estimate of p for the test.  Fourth step-we will get the analyses and we can conclude from the confidence interval and p-value from the data. Methodologies- Minitab

14 The amount of cash to get one point affects consumer’s behavior. Hypothesis 1

15 Test and CI for One Proportion: x1 Event = 1 Variable X N Sample p 95% CI x1 36 50 0.720000 (0.575095, 0.837689) In Hypothesis 1, we suppose that the amount of cash to get one point affects consumer’s behavior. Then, we suppose that H 0 : P 0.5. If the confidence interval is over 0.5, we can reject H 0. Therefore, we have the sufficient evidence to conclude that the Hypothesis 1 is true. Hypothesis 1

16 The amount of cash to get one point affects consumer’s behavior. Among the three alternatives : ”twenty dollars”, ”twenty-five dollars”, and” thirty dollars”, we suppose that twenty-five dollars is the highest limit for a consumer to get one point. Hypothesis 2

17 Test and CI for Two Proportions: C2 (two weeks), C3 (one month) Event = 1 Variable X N Sample p C2 6 36 0.166667 C3 27 36 0.750000 Difference = p (C2) - p (C3) Estimate for difference: -0.583333 95% CI for difference: (-0.769956, -0.396711) Test for difference = 0 (vs not = 0): Z = -6.13 P-Value = 0.000 Fisher's exact test: P-Value = 0.000 Hypothesis 2

18 Test and CI for Two Proportions: C2 (two weeks), C4 (two months) Event = 1 Variable X N Sample p C2 6 36 0.166667 C4 3 36 0.083333 Difference = p (C2) - p (C4) Estimate for difference: 0.0833333 95% CI for difference: (-0.0682308, 0.234897) Test for difference = 0 (vs not = 0): Z = 1.08 P-Value = 0.281 Fisher's exact test: P-Value = 0.478 Hypothesis 2

19 Test and CI for Two Proportions: C3 (one month), C4 (two months) Event = 1 Variable X N Sample p C3 27 36 0.750000 C4 3 36 0.083333 Difference = p (C3) - p (C4) Estimate for difference: 0.666667 95% CI for difference: (0.498861, 0.834473) Test for difference = 0 (vs not = 0): Z = 7.79 P-Value = 0.000 Fisher's exact test: P-Value = 0.000 Hypothesis 2

20 Test and CI for Two Proportions: C2 (two weeks), C3 (one month) Event = 1 Variable X N Sample p C2 6 36 0.166667 C3 27 36 0.750000 Difference = p (C2) - p (C3) Estimate for difference: -0.583333 95% CI for difference: (-0.769956, -0.396711) Test for difference = 0 (vs not = 0): Z = -6.13 P-Value = 0.000 Fisher's exact test: P-Value = 0.000 Hypothesis 2

21  In Hypothesis 2, we suppose that one month is the shortest limit that consumers could accept for the activity. Then we use statistics analysis to compare them in groups. From the result, we find out p-value=0, which means there are significant differences among them. Then, we can choose the one with biggest probability. By using the method mentioned before, we find out that “one month” is the one with the biggest probability. Therefore, we can conclude that “one month” is the shortest limit that consumers could accept for the activity. Hypothesis 2

22 The period of activity does affects consumer’s behavior. Hypothesis 3

23  Test and CI for One Proportion: x2  Event = 1  Variable X N Sample p 95% CI  x2 44 50 0.880000 (0.756899, 0.954665)  In Hypothesis 3, we suppose that the period of activity does affect consumer’s behavior. Then, we suppose that H 0 : P 0.5. If the confidence interval is over 0.5, we can reject H 0. Therefore, we have the sufficient evidence to conclude that the Hypothesis 3 is true. Hypothesis 3

24 The period of activity does affects consumer’s behavior. Among the three alternatives : ”two weeks”, ” one month”, and” two months”, we suppose that one month is the shortest limit that consumers could accept for the activity. Hypothesis 4

25 Test and CI for Two Proportions: 10points, 15points Event = 1 Variable X N Sample p 10 points 26 43 0.604651 15 points 8 43 0.186047 Difference = p (10 points) - p (15 points) Estimate for difference: 0.418605 95% CI for difference: (0.231832, 0.605378) Test for difference = 0 (vs not = 0): Z = 4.39 P-Value = 0.000 Fisher's exact test: P-Value = 0.000 Hypothesis 4

26 Test and CI for Two Proportions: 10 points, 20 points Event = 1 Variable X N Sample p 10 points 26 43 0.604651 20 points 9 43 0.209302 Difference = p (10 points) - p (20 points) Estimate for difference: 0.395349 95% CI for difference: (0.205243, 0.585455) Test for difference = 0 (vs not = 0): Z = 4.08 P-Value = 0.000 Fisher's exact test: P-Value = 0.000 Hypothesis 4

27 Test and CI for Two Proportions: 15 points, 20 points Event = 1 Variable X N Sample p 15 points 8 43 0.186047 20 points 9 43 0.209302 Difference = p (15 points) - p (20 points) Estimate for difference: -0.0232558 95% CI for difference: (-0.191521, 0.145009) Test for difference = 0 (vs not = 0): Z = -0.27 P-Value = 0.786 Fisher's exact test: P-Value = 1.000 Hypothesis 4

28 In Hypothesis 4, we suppose that “twenty points” is the highest limit for consumers to attend the activity. Then we use statistics analysis to compare them in groups. From the result, we find out p-value=0, which means there are significant differences among them. Then, we can choose the one with biggest probability. By using the method mentioned before, we find out that “ten points” is the one with the biggest probability. Therefore, we can conclude that” ten points” is the highest limit that consumers could accept for the activity. Hypothesis 4

29 The amount of points to get the banana boat affects consumer’s behavior. Hypothesis 5

30 Test and CI for One Proportion: x3 Event = 1 Variable X N Sample p 95% CI x3 42 50 0.840000 (0.708874, 0.928299) In Hypothesis 5, we suppose that the amount of cash to get one point affects consumer’s behavior. Then, we suppose that H 0 : P 0.5. If the confidence interval is over 0.5, we can reject H 0. Therefore, we have the sufficient evidence to conclude that the Hypothesis 5 is true. Hypothesis 5

31 The amount of points to get the banana boat affects consumer’s behavior. Among the three alternatives : ”ten points”, ”fifteen points”, and” twenty points”, we suppose that twenty points are the highest limit for consumers to attend the activity. Hypothesis 6

32 Test and CI for Two Proportions: 20NTD, 25 NTD Event = 1 Variable X N Sample p 20 NTD 8 42 0.190476 25 NTD 13 42 0.309524 Difference = p (20 NTD) - p (25 NTD) Estimate for difference: -0.119048 95% CI for difference: (-0.302489, 0.0643934) Test for difference = 0 (vs not = 0): Z = -1.27 P-Value = 0.203 Fisher's exact test: P-Value = 0.314 Hypothesis 6

33 Test and CI for Two Proportions: 20 NTD, 30 NTD Event = 1 Variable X N Sample p 20 NTD 8 42 0.190476 30 NTD 20 42 0.476190 Difference = p (20 NTD) - p (30 NTD) Estimate for difference: -0.285714 95% CI for difference: (-0.477853, -0.0935759) Test for difference = 0 (vs not = 0): Z = -2.91 P-Value = 0.004 Fisher's exact test: P-Value = 0.010 Hypothesis 6

34 Test and CI for Two Proportions: 25 NTD, 30 NTD Event = 1 Variable X N Sample p 25 NTD 13 42 0.309524 30 NTD 20 42 0.476190 Difference = p (25 NTD) - p (30 NTD) Estimate for difference: -0.166667 95% CI for difference: (-0.372486, 0.0391522) Test for difference = 0 (vs not = 0): Z = -1.59 P-Value = 0.112 Fisher's exact test: P-Value = 0.180 Hypothesis 6

35  In Hypothesis 6, we suppose that “twenty-five dollars” is the highest limit for a consumer to get one point. Then we use statistics analysis to compare them in groups. From the result, we find out p-value=0, which means there are significant differences among them. Then, we can choose the one with biggest probability. By using the method mentioned before, we find out that “thirty dollars” is the one with the biggest probability. However, we also find out that there is no significant difference between “twenty-five dollars” and “thirty dollars”. Therefore, we have no enough evidence to conclude that “twenty-five dollars” is the highest limit that consumers could accept for the activity. Hypothesis 6

36 The characteristic that banana boat is just sent for consumers finishing the points credit card and not for sale affects consumer’s behavior. Hypothesis 7

37 Test and CI for One Proportion: x4 Event = 1 Variable X N Sample p 95% CI x4 31 50 0.620000 (0.471749, 0.753499) In Hypothesis 7, we suppose that the amount of cash to get one point affects consumer’s behavior. Then, we suppose that H 0 : P 0.5. If the confidence interval is over 0.5, we can reject H 0. However, we find out that the confidence interval is not over 0.5 completely. Therefore, we have no sufficient evidence to conclude that the Hypothesis 7 is true. Hypothesis 7

38 “Point Credit Card” can stimulate consumers to consume and increase the store’s turnover. We find out that the amount of cash to get one point, the amount of points to get the banana ship, and the amount of cash to get one point affect consumer’s behavior. However, the characteristic that banana ship is just sent for consumers finishing the point credit card and not for sale does not affect consumer’s behavior. Conclusion


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