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1.) If there are initially 100 fruit flies in a sample, and the number of fruit flies decreases by one-half each hour, How many fruit flies will be present after 5 hours? Do Now 4 - 26 - 2012 2.) Sara bought 4 fish. Every month the number of fish she has doubles. After 6 months she will have how many fish.
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Do Now 4 - 27 - 2012 Simplify. 1.) 2.) 3.) Evaluate using this formula when P is 1219, r is 0.12, and t is 5.
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Do Now 4 - 30 - 2012 half-lives 1.) How many half-lives would it take to have a 700 gram sample of uranium reduce to under 3 grams of uranium ? double 2.) If there are initially 10 bacteria in a culture, and the number of bacteria double each hour, find the number of bacteria after 24 hours.
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Do Now 5 - 4 - 2012 When a person takes a dosage of I milligrams of a medicine, the amount A ( in milligrams) of medication remaining in the person’s bloodstream after t hours can be modeled by the equation. Using the formula, Find the amount of medication remaining in a person’s bloodstream if the dosage was 500 mg and 2.5 hours has lapsed.
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Compound Interest You want to have $ 20,000 in your account after 18 years. Find the amount your initial deposit should be if the account pays 4.5% annual interest compounded monthly. Do Now 5 - 4 - 2012 Identify: A = P = r = n = t =
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Compound Interest You want to have $ 20,000 in your account after 18 years. Find the amount your initial deposit should be if the account pays 4.5% annual interest compounded monthly. Do Now 5 - 4 - 2012 A = 20,000 P = ? r =.045 n = 12 t = 18
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Do Now 5 - 8 - 2012 In the equation, which of the following is true? a) There is a Growth Rate? b) There is a Decay Rate? c) The Decay Rate is 75% ? d) The Decay Rate is 25% ? e) The Decay Factor is.25 ? f) The Decay Factor is (1 -.75) ? g) The initial amount is 350? h) The time period is 10 ? I) “ y ” is the final amount? j)This is an Exponential ….Growth ….Decay
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Do Now 5 - 9 - 2012 continuously 1.) If you invested $ 2,000 at a rate of 0.6 % compounded continuously, find the balance in the account after 5 years, use the formula 2. ) Simplify the Expression $ 2,060.91
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Compounded Interest ex) Compounded daily Compounded monthly Compounded quarterly Compounded Interest ex) Compounded daily Compounded monthly Compounded quarterly Continuously Compounded Interest Exponential Growth Exponential Decay Do Now 5 - 10 - 2012
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Do Now 5 - 11 - 2012 1.) RE-Write in Exponential form 2.) RE-Write in Logarithmic form 3.) Evaluate 4.) Graph
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p. 478 What you should learn: Graph Graph and use Exponential Growth functions. Write an Exponential Growth model that describes the situation. 7.1 Graph Exponential Growth Functions A2.5.2 Ch 7.1 Exponential Growth
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Exponential Function f(x) = b x b where the base b is a positive number other than one. Graph f(x) = 2 x Notice the end behavior As x → ∞ f(x) → ∞ As x → -∞ f(x) → 0 y = 0 is an asymptote
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What is an Asymptote? A line that a graph approaches as you move away from the origin The graph gets closer and closer to the line y = 0 ……. But NEVER reaches it y = 0 2 raised to any power Will NEVER be zero!!
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Example 1 Graph Plot (0, ½) and (1, 3/2) Then, from left to right, draw a curve that begins just above the x- axis, passes thru the 2 points, and moves up to the right What do you think the Asymptote is? y = 0
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Example 2 Graph y = - (3/2) x Plot (0, -1) and (1, -1.5) Connect with a curve Mark asymptote D = ?? All reals R = ??? All reals < 0 y = 0
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Example 3 Graph y = 3·2 x-1 - 4 Lightly sketch y = 3·2 x Passes thru (0,3) & (1,6) h = 1, k = -4 Move your 2 points to the right 1 and down 4 AND your asymptote k units (4 units down in this case)
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Now…you try one! Graph y = 2·3 x-2 +1 State the Domain and Range! D = all reals R = all reals >1 y=1 Example 4
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When a real-life quantity increases by a fixed percent each year, the amount y of the quantity after t years can be modeled by the equation where a - Initial principal r – percent increase expressed as a decimal t – number of years y – amount in account after t years Notice Notice that the quantity (1 + r) is called the Growth Factor
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Example The amount of money, A, accrued at the end of n years when a certain amount, P, is invested at a compound annual rate, r, is given by If a person invests $310 in an account that pays 8% interest compounded annually, find the approximant balance after 5 years. A = $455.49
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Compound Interest Consider an initial principal P deposited in an account that pays interest at an annual rate, r, compounded n times per year. P - Initial principal r – annual rate expressed as a decimal n – compounded n times a year t – number of years A – amount in account after t years
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Compound Interest example You deposit $1000 in an account that pays 8% annual interest. Find the balance after 1 year if the interest is compounded with the given frequency. a) annually b) quarterly c) daily A=1000(1+.08/1) 1x1 = 1000(1.08) 1 ≈ $1080 A=1000(1+.08/4) 4x1 =1000(1.02) 4 ≈ $1082.43 A=1000(1+.08/365) 365x1 ≈1000(1.000219) 365 ≈ $1083.28
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Ch 7.2 Exponential Decay p. 486 What you should learn: Goal1 Goal2 Graph Graph and use Exponential Decay functions. Write an Exponential Decay model that describes the situation. 7.2 Graph Exponential decay Functions A2.5.2
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7.2 Exponential Decay P. 486 Discovery Education – Example 3: Exponential Decay-Bloodstream
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Exponential Decay Has the same form as growth functions f(x) = a(b) x Where a > 0 BUT: fraction 0 < b < 1 (a fraction between 0 & 1)
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Recognizing growth and decay functions State whether f(x) is an exponential growth or DECAY function f(x) = 5(2/3) x b = 2/3, 0 < b < 1 it is a decay function. f(x) = 8(3/2) x b = 3/2, b > 1 it is a growth function. f(x) = 10(3) -x rewrite as f(x)= 10(1/3) x so it is decay
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Recall from 7.1: The graph of y= ab x Passes thru the point (0,a) (the y intercept is a) The x-axis is the asymptote of the graph a tells you up or down D is all reals (the Domain) R is y>0 if a>0 and y<0 if a<0 (the Range)
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Graph: y = 3(1/4) x Plot (0,3) and (1,3/4) Draw & label asymptote Connect the dots using the asymptote Domain = all reals Range = reals>0 y=0
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Graph y = -5(2/3) x Plot (0,-5) and (1,- 10/3) Draw & label asymptote Connect the dots using the asymptote y=0 Domain : all reals Range : y < 0
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Now remember: To graph a general Exponential Function: y = a b x-h + k Sketch y = a b x h= ??? k= ??? Move your 2 points h units left or right …and k units up or down Then sketch the graph with the 2 new points.
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Example graph y=-3(1/2) x+2 +1 Lightly sketch y=- 3·(1/2) x Passes thru (0,-3) & (1,-3/2) h=-2, k=1 Move your 2 points to the left 2 and up 1 AND your asymptote k units (1 unit up in this case)
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y=1 Domain : all reals Range : y<1
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Using Exponential Decay Models When a real life quantity decreases by fixed percent each year (or other time period), the amount y of the quantity after t years can be modeled by: y = a(1-r) t arWhere a is the initial amount and r is the percent decrease expressed as a decimal. The quantity 1-r is called the decay factor Discovery Ed - Using functions to Gauge Filter EffFilter
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Ex: Buying a car! You buy a new car for $24,000. The value y of this car decreases by 16% each year. Write an exponential decay model for the value of the car. Use the model to estimate the value after 2 years. Graph the model. Use the graph to estimate when the car will have a value of $12,000.
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Let t be the number of years since you bought the car. The model is: y = a(1-r) t = 24,000(1-.16) t = 24,000(.84) t Note:.84 is the decay factor When t = 2 the value is y=24,000(.84) 2 ≈ $16,934
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Now Graph The car will have a value of $12,000 in 4 years!!!
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7.3 Use Functions Involving e p. 492 What you should learn: Goal1 Goal2 Will study functions involving the Natural base e Simplify and Evaluate expressions involving e 7.3 Use Functions Involving e A3.2.2 Goal3 Graph functions with e
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The Natural base e Much of the history of mathematics is marked by the discovery of special types of numbers like counting numbers, zero, negative numbers, Л, and imaginary numbers. 7.3 Use Functions Involving e
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Natural Base e Like Л and ‘ i ’, ‘ e ’ denotes a number. Called The Euler Number after Leonhard Euler (1707-1783) It can be defined by: e= 1 + 1 + 1 + 1 + 1 + 1 +… 0! 1! 2! 3! 4! 5! = 1 + 1 + ½ + 1/6 + 1/24 + 1/120+... ≈ 2.718281828459…. 7.3 Use Functions Involving e
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The number e is irrational – its’ decimal representation does not terminate or follow a repeating pattern. The previous sequence of e can also be represented: As n gets larger ( n →∞), (1+1/ n ) n gets closer and closer to 2.71828….. Which is the value of e. 7.3 Use Functions Involving e
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Examples e 3 · e 4 e7e7 10e 3 5e 2 2e 3-2 2e2e (3e -4x ) 2 9e (-4x)2 9e -8x 9 e 8x 7.3 Use Functions Involving e
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More Examples! 24e 8 8e 5 3e33e3 (2e -5x ) -2 2 -2 e 10x e 10x 4 7.3 Use Functions Involving e
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Using a calculator Evaluate e 2 using a graphing calculator Locate the e x button you need to use the second button 7.389 7.3 Use Functions Involving e
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Evaluate e -.06 with a calculator 7.3 Use Functions Involving e
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Graphing f(x) = a e rx is a natural base exponential function If a > 0 & r > 0 it is a growth function If a > 0 & r < 0 it is a decay function 7.3 Use Functions Involving e
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Graphing examples Graph y = e x Remember the rules for graphing exponential functions! The graph goes thru (0,a) and (1,e) (0,1) (1,2.7) 7.3 Use Functions Involving e
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Graphing cont. Graph y = e -x (0,1) (1,.368) 7.3 Use Functions Involving e
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Graphing Example Graph y = 2 e 0.75 x State the Domain & Range Because a=2 is positive and r=0.75, the function is exponential growth. Plot (0,2)&(1,4.23) and draw the curve. (0,2) (1,4.23) 7.3 Use Functions Involving e
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Using e in real life. In 8.1 we learned the formula for compounding interest n times a year. In that equation, as n approaches infinity, the compound interest formula approaches the formula for continuously compounded interest: A = Pe rt 7.3 Use Functions Involving e
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Example of Continuously compounded interest You deposit $1000.00 into an account that pays 8% annual interest compounded continuously. What is the balance after 1 year? 7.3 Use Functions Involving e P = 1000, r =.08, and t = 1 A = Pe rt = 1000e.08*1 ≈ $1083.29
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7.4 Logarithms p. 499 What you should learn: Goal1 Goal2 Evaluate logarithms Graph logarithmic functions 7.4 Evaluate Logarithms and Graph Logarithmic Functions A3.2.2 mathbook
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Evaluating Log Expressions We know 2 2 = 4 and 2 3 = 8 But for what value of y does 2 y = 6 ? Because 2 2 < 6 < 2 3 you would expect the answer to be between 2 & 3. To answer this question exactly, mathematicians defined logarithms.
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Definition of Logarithm to base a Let a & x be positive numbers & a ≠ 1. The logarithm of x with base a is denoted by log a x and is defined: log a x = y iff a y = x This expression is read “log base a of x” The function f(x) = log a x is the logarithmic function with base a.
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The definition tells you that the equations log a x = y and a y = x are equivilant. Rewriting forms: To evaluate log 3 9 = x ask yourself… “Self… 3 to what power is 9?” 3 2 = 9 so…… log 3 9 = 2
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Log form Exp. form log 2 16 = 4 log 10 10 = 1 log 3 1 = 0 log 10.1 = -1 log 2 6 ≈ 2.585 2 4 = 16 10 1 = 10 3 0 = 1 10 -1 =.1 2 2.585 = 6
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Evaluate without a calculator log 3 81 = Log 5 125 = Log 4 256 = Log 2 (1/32) = 3 x = 81 5 x = 125 4 x = 256 2 x = (1/32) 4 3 4 -5
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Evaluating logarithms now you try some! Log 4 16 = Log 5 1 = Log 4 2 = Log 3 (-1) = (Think of the graph of y=3 x ) 2 0 ½ ( because 4 1/2 = 2) undefined
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You should learn the following general forms!!! Log a 1 = 0 because a 0 = 1 Log a a = 1 because a 1 = a Log a a x = x because a x = a x
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Natural logarithms log e x = ln x ln means log base e
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Common logarithms log 10 x = log x Understood base 10 if nothing is there.
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Common logs and natural logs with a calculator log 10 button ln button
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g(x) = log b x is the inverse of f(x) = b x f(g(x)) = x and g(f(x)) = x Exponential and log functions are inverses and “undo” each other
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So: g(f(x)) = log b b x = x f(g(x)) = b log b x = x 10 log2 = Log 3 9 x = 10 logx = Log 5 125 x = 2 Log 3 (3 2 ) x =Log 3 3 2x =2x x 3x
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Finding Inverses Find the inverse of: y = log 3 x By definition of logarithm, the inverse is y=3 x OR write it in exponential form and switch the x & y! 3 y = x 3 x = y
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Finding Inverses cont. Find the inverse of : Y = ln (x +1) X = ln (y + 1) Switch the x & y e x = y + 1 Write in exp form e x – 1 = y solve for y
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