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AP Calculus Ms. Battaglia
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Solve the differential equation
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In many applications, the rate of change of a variable y is proportional to the value of y. If y is a function of time t, the proportion can be written as follows. Rate of change of y is proportional to y. If y is a differentiable function of t such that y > 0 and y’ = ky for some constant k, then y = Ce kt. C is the initial value of y, and k is the proportionality constant. Exponential growth occurs when k > 0, and exponential decay occurs when k < 0.
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The rate of change of y is proportional to y. When x=0, y=6, and when x=4, y=15. What is the value of y when x=8?
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IsotopeHalf-Life (in years) Initial Quantity Amount After 1,000 Years Amount After 10,000 Years 226 Ra 159920 g 226 Ra 15991.5 g 226 Ra 15990.1 g 14 C 57153 g
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Initial Investment Annual RateTime to Double Amount After 10 Years $40006% $18,0005.5% $7507¾ yr $500$1292.85
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Find the principal P that must be invested at rate r, compounded monthly, so that $1,000,000 will be available for retirement in t years. r = 7.5% and t = 20
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Find the time necessary for $1000 to double if it is invested at a rate of 7% compounded (a) annually (b) monthly (c) daily and (d) continuously.
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AB: Read 6.2 Page 420 #1-12, 21, 23, 25-28 BC: Read 6.2 Page 420 #7-14, 21, 25-28, 33, 34, 57, 58, 73, 75-78
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