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Polar Coordinates
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Differences: Polar vs. Rectangular
(0,0) is called the pole Coordinates are in form (r, θ) (0,0) is called the origin Coordinates are in form (x,y)
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How to Graph Polar Coordinates
Given: (3, л/3)
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Answer- STEP ONE Look at r and move that number of circles out
Move 3 units out (highlighted in red)
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Answer- STEP TWO Look at θ- this tells you the direction/angle of the line Place a point where the r is on that angle. In this case, the angle is л/3
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Answer: STEP THREE Draw a line from the origin through the point
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Converting Coordinates
Remember: The hypotenuse has a length of r. The sides are x and y. By using these properties, we get that: x = rcosθ y=rsinθ tanθ=y/x r2=x2+y2 3, л/3 r y x
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CONVERT: Polar to Rectangle: (3, л/3)
x=3cos (л/3) x=3cos(60) y=3sin(л/3) x=3sin(60) New coordinates are (1.5, 2.6) ***x = rcosθ ***y=rsinθ tanθ=y/x r2=x2+y2
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CONVERT: Rectangular to Polar: (1, 1)
Find Angle: tanθ= y/x tanθ= 1 tan-1(1)= л/4 Find r by using the equation r2=x2+y2 r2=12+12 r= √2 New Coordinates are (√2, л/4) (You could also find r by recognizing this is a right triangle)
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Finding points of intersection
Third point does not show up. On r = 1, point is (1, π) On r = 1-2 cos θ, point is (-1, 0)
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TANGENTS TO POLAR CURVES
To find a tangent line to a polar curve r = f(θ), we regard θ as a parameter and write its parametric equations as: x = r cos θ = f (θ) cos θ y = r sin θ = f (θ) sin θ
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Slope of a polar curve Horizontal tangent where dy/dθ = 0 and dx/dθ≠0
Where x = r cos θ = f(θ) cos θ And y = r sin θ = f(θ) sin θ Horizontal tangent where dy/dθ = 0 and dx/dθ≠0 Vertical tangent where dx/dθ = 0 and dy/dθ≠0
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TANGENTS TO POLAR CURVES
We locate horizontal tangents by finding the points where dy/dθ = 0 (provided that dx/dθ ≠ 0). Likewise, we locate vertical tangents at the points where dx/dθ = 0 (provided that dy/dθ ≠ 0).
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TANGENTS TO POLAR CURVES
For the cardioid r = 1 + sin θ Find the points on the cardioid where the tangent line is horizontal or vertical.
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TANGENTS TO POLAR CURVES
Observe that:
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TANGENTS TO POLAR CURVES
Using Equation 3 with r = 1 + sin θ, we have:
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TANGENTS TO POLAR CURVES
Hence, there are horizontal tangents at the points (2, π/2), (½, 7π/6), (½, 11π/6) and vertical tangents at (3/2, π/6), (3/2, 5π/6) When θ = 3π/2, both dy/dθ and dx/dθ are 0. So, we must be careful.
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Figure 11.32
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Length of a Curve in Polar Coordinates
Find the length of the arc for r = 2 – 2cosθ sin2A =(1-cos2A)/2 2 sin2A =1-cos2A 2 sin2 (1/2θ) =1-cosθ
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Area of region
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Find Area of region inside smaller loop
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Area of a Surface
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SOURCES (LINKS AND NAMES)
1.aculty.essex.edu/~wang/221/Chap10_Sec3 2. Nate Long 3. Pearson
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