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Chemical Equations and Chemical Reactions

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Presentation on theme: "Chemical Equations and Chemical Reactions"— Presentation transcript:

1 Chemical Equations and Chemical Reactions

2 Writing A Chemical Equation
The general format for chemical equations is: a + b  c + d The substances on the left side of the equation (a and b in this case) are called the reactant(s).

3 The + sign means “reacts with”.
The  means “produces or yields”. The substance(s) on the right side of the equation (c and d in this case) are called the product(s).

4 Lets work with the statement Hydrogen gas reacts with oxygen gas to form liquid water.

5 Word Equation: hydrogen + oxygen  water Skeleton Equation: H2(g)+ O2(g)  H2O(l) Balanced Equation: ___H2(g)+ ___O2(g)  ___H2O(l) 2H2(g)+ O2(g)  2H2O(l)

6 Why must we balance equations?
The Law of Conservation of Mass states that the total mass of reactants is always equal to the total mass of the products. (Lavoisier’s law) Antoine-Laurent Lavoisier experimenting to determine the composition of water, French engraving, 19th century.

7 Why must we balance equations?
Dalton’s atomic theory states that atoms can not be created or destroyed. Compounds are formed when atoms of different elements combine in fixed proportions. John Dalton, F.R.S., engraved by Worthington after an 1814 painting by William Allen, published 25 June 1823 in Manchester and London. Note the charts with Dalton's atomic symbols lying on the table. Fisher Collection, Chemical Heritage Foundation.

8 To balance equations numbers called coefficients are put before the formulas. This changes the number of molecules. You cannot add or change subscripts (small numbers). You do not write coefficients of 1 (one). Sometimes you need to know the state of the chemicals that are involved in a chemical reaction.

9 State Abbreviation solid liquid gas aqueous solution

10 State Abbreviation solid (s) liquid gas aqueous solution

11 State Abbreviation solid (s) liquid (l) gas aqueous solution

12 State Abbreviation solid (s) liquid (l) gas (g) aqueous solution

13 State Abbreviation solid (s) liquid (l) gas (g) aqueous solution (aq)

14 Rules For Writing Balanced Chemical Equations
Final Balanced Chemical Equation 2H2(g) + O2(g)  2H2O(l) Rules For Writing Balanced Chemical Equations This requires a lot of practice and patience. These rules will not apply in all equations. 1. Write the skeleton equation.

15 Look for a polyatomic ion that appears once on each side of the equation. Balance these first.
Pick single elements that appears on each side. Choose coefficients to balance this element. The terms you balanced in the previous step have to remain balanced. Repeat for any other elements.

16 4. Check for any term you have not yet looked at
4. Check for any term you have not yet looked at. Adjust the coefficient of the term so that the numbers of the elements appearing in that term are balanced across the whole equation. If you have any fraction coefficients clear them by multiplying. Also, make sure you have the smallest possible coefficients by reducing. 5. Check the equation!

17 Example 1 Word Equation: Skeletal Equation: Na + H2O  NaOH + H2(g)
sodium + water  sodium hydroxide + hydrogen gas Skeletal Equation: Na + H2O  NaOH + H2(g) Balanced Equation: ___Na + ___H2O  ___NaOH +___H2(g) 2Na + 2H2O  2NaOH + H2(g)

18 Example 2 Balanced Chemical Equation 2H2O__ 2Na__ +  2NaOH__ + H2___
2H2O(l) + 2 Na(s)  2NaOH(aq) + H2(g) Verification Reactants Products 2 Na atoms 4 H atoms 2 O atoms

19 Example 2 Word Equation: Skeletal Equation:
copper + silver nitrate  copper(II) nitrate + silver Skeletal Equation: ___ + ______  ______ + ___ Cu + AgNO3  Cu(NO3)2 + Ag

20 Example 2… Balanced Equation: __Cu +__ AgNO3  __Cu(NO3)2 + __Ag
Balanced Chemical Equation: Cu__ + 2AgNO3__  Cu(NO3)2__ + 2Ag__ Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s)

21 Reactants Products Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s)
Verification Reactants Products

22 Reactants Products 1 Cu atom
Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s) Verification Reactants Products 1 Cu atom

23 Reactants Products 1 Cu atom
Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s) Verification Reactants Products 1 Cu atom

24 Reactants Products 1 Cu atom 2 Ag atoms
Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s) Verification Reactants Products 1 Cu atom 2 Ag atoms

25 Reactants Products 1 Cu atom 2 Ag atoms
Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s) Verification Reactants Products 1 Cu atom 2 Ag atoms

26 Reactants Products 1 Cu atom 2 Ag atoms 2 NO3- ions
Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s) Verification Reactants Products 1 Cu atom 2 Ag atoms 2 NO3- ions

27 Reactants Products 1 Cu atom 2 Ag atoms 2 NO3- ions
Cu(s) + 2AgNO3(aq)  Cu(NO3)2(aq) + 2Ag(s) Verification Reactants Products 1 Cu atom 2 Ag atoms 2 NO3- ions

28 Example 3 Word Equation:
calcium nitrate + sodium hydroxide  calcium hydroxide + sodium nitrate Skeletal Equation: Ca(NO3)2 + NaOH  Ca(OH)2 + NaNO3 Balanced Equation: __Ca(NO3)2 + __NaOH  __Ca(OH)2 + _NaNO3 Ca(NO3)2 + 2NaOH  Ca(OH)2 + 2NaNO3

29 Balanced Chemical Equation
Ca(NO3)2__ + 2NaOH__  Ca(OH)2__ + NaNO3__ Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + NaNO3(aq)

30 Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq)
Reactants Products

31 Reactants Products 1 Ca atom
Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq) Reactants Products 1 Ca atom

32 Reactants Products 1 Ca atom
Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq) Reactants Products 1 Ca atom

33 Reactants Products 1 Ca atom 2 NO3- ions
Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq) Reactants Products 1 Ca atom 2 NO3- ions

34 Reactants Products 1 Ca atom 2 NO3- ions
Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq) Reactants Products 1 Ca atom 2 NO3- ions

35 Reactants Products 1 Ca atom 2 NO3- ions 2 Na atoms
Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq) Reactants Products 1 Ca atom 2 NO3- ions 2 Na atoms

36 Reactants Products 1 Ca atom 2 NO3- ions 2 Na atoms
Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq) Reactants Products 1 Ca atom 2 NO3- ions 2 Na atoms

37 Reactants Products 1 Ca atom 2 NO3- ions 2 Na atoms 2 OH- ions
Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq) Reactants Products 1 Ca atom 2 NO3- ions 2 Na atoms 2 OH- ions

38 Reactants Products 1 Ca atom 2 NO3- ions 2 Na atoms 2 OH- ions
Ca(NO3)2(aq) + 2NaOH(aq)  Ca(OH)2(s) + 2NaNO3(aq) Reactants Products 1 Ca atom 2 NO3- ions 2 Na atoms 2 OH- ions

39 Homework p. 174 # 1 to 6


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