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Dr J Frost (jfrost@tiffin.kingston.sch.uk)
Year 7 Negative Numbers Dr J Frost Objectives: Add, subtract, multiply and divide negative numbers, as well as raise a negative number to a power. Last modified: 18th July 2015
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For Teacher Use: Recommended lesson structure:
Lesson 1: Adding, subtracting negative numbers. Lesson 2: Multiplying, dividing and mixed questions.
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Visualising negatives with a number line
For any addition/subtraction of numbers, you should ALWAYS visualise a number line. How would we visualise the following? Click > Click > 3β7=βπ β6+10=π Click > Click > β7+5=βπ β3β4=βπ Bro Tip: Notice that the answer is always either the sum of the two numbers (ignoring sign) or the difference.
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Test Your Understanding
Copy and complete the following. 6β11=βπ 3β10=βπ β1β5=βπ β10+11=π β5+1=βπ β13+6=βπ β4β25=βππ β25+4=βππ [JMC 2014 Q7] What is 2014β4102? ππππβππππ=ππππ β΄ππππβππππ=βππππ a ? b ? c ? d ? e ? f ? g ? h ? N ?
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What is the answer. How could we show it?
Adding/subtracting negative numbers 9 + β3= ? What is the answer. How could we show it? 9+2=ππ 9+1=ππ 9+0=π 9+ β1 =π 9+ β2 =π 9+ β3 =π ? ? ?
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What is the answer. How could we show it?
Adding/subtracting negative numbers 5 β β2= ? What is the answer. How could we show it? 5 β 2=π 5 β 1=π 5 β 0=π 5 β β1 =π 5 β β2 =π 5 β β3 =π ? ? ? ! +β β β A plus and a minus become a minus ββ β Two minuses become a plus.
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βTwo minuses make a plus!β
Common Misunderstanding: βTwo minuses make a plus!β β4β10=14 What did they do wrong? Two minuses only become a plus when theyβre next to each other. If we think about a number line can see the above doesnβt make sense. ? Quickfire Questions: Check Your Understanding: β5 =π 7 β β5 =ππ β β5 =βππ β7 β β5 =βπ =ππ 7 β =π β =βπ β7 β =βππ =ππ 4 β =βπ β =π β4 β =βππ β =βπ 4 β β10 =ππ β β10 =βππ β4 β β10 =π ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
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Exercise 1 Find two numbers which have a sum of -2 and a difference of Solution: 3 and -5 [JMC 2010 Q1] What is β2010 β β(β2010) ? Solution: 2010 [JMC 2013 Q6] What is the value of 1β1 β1 β 1β 1β1 ? Solution: -2 [JMO 2007 A1] What is the value of β β ? Solution: 1 [IMC 2001 Q1] Between which of the following pairs of numbers is there the greatest difference? A -3, 8 B -5, C 1, D 4, E -6, -15 Solution: A [SMC 2009 Q3] What is the value of β β β Solution: 5 [Kangaroo Grey 2004 Q5] What is the value of the expression 1β2 β 3β4 β 5β6 ββ¦β 99β Solution: 48 1 Calculate the following. β6+15=π 7β15=βπ 4β β7 =ππ 9+ β10 =βπ β18+7=βππ β5β β2 =βπ β20β β13 =βπ β1β β1 =π β6+ β8 =βππ β2β(β6)=π 5β(β20)=ππ 3+ β24 β4=βππ 1β6β β4 =βπ β 6+ β7 +8=βπ Fill in the missing value. β3+ β = β=10 7ββ=β β=17 8+β= β=β2 β2ββ=β β=6 β3ββ= β=β13 β10+β=β β=β20 3 a ? ? b ? 4 c ? d ? e ? ? f ? 5 g ? ? h ? i ? j ? 6 ? k ? l ? m ? 7 n ? ? 2 a ? 8 ? ? b c ? d ? N e ? f ? ?
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9Γ β3 = ? Multiplying Negative Numbers
What is the answer? Could we show it in a similar way to how we showed 9+ β3 =6? 9+2=ππ 9+1=ππ 9+0=π 9+ β1 =π 9+ β2 =π 9+ β3 =π 9Γ2=ππ 9Γ1=π 9Γ0=π 9Γ β1 =βπ 9Γ β2 =βππ 9Γ β3 =βππ ? ? ?
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β2 Γ β3 = ? Multiplying Negative Numbers
What is the answer? Could we show how to get it by starting with 2Γ β3 =β6? 2Γ(β3)=π 1Γ(β3)=π 0Γ(β3)=π (β1)Γ β3 =βπ (β2)Γ β3 =βππ ? ? ! πππ Γπππ=πππ πππΓπππ =πππ πππΓπππ=πππ Same applies to division.
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Quickfire Examples 4Γ β1 =βπ β3 Γ7=βππ β5 Γ β4 =ππ β8 Γ·2=βπ β21 Γ· β7 =π 9Γ· β3 =βπ β5 2 =ππ β2 3 =βπ β10β2 2 =πππ ? ? ? ? ? ? ? ? ?
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(Use the front of your diary for blue)
Use your diary coloured cards to vote for the correct answer in each question. (Use the front of your diary for blue) RED ORANGE GREEN BLUE
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Calculate: βπββπ 4 β4 12 β12
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Calculate: βππ Γπ β5 β50 50 β2
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Calculate: βππΓ·βπ 24 β10 β6 6
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Calculate: βπ+ππ βπβπ 2 β2 10 β10
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Calculate: βπΓ βπ π β18 β27 27 18
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Calculate: βπππΓ· βπββπ π β25 25 12.5 50
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Exercise 2 Calculate the following: β3Γ β2 =π β12Γ·4=βπ β9 2 =ππ 4Γβ13=βππ 16Γ·β2=βπ β30 Γ· β6 =π β8Γ3=βππ Determine the missing number: 8Γβ=β32 β=βπ β6Γβ=β18 β=π β8Γ·β=β2 β=π β2 2 Γβ=32 β=π β4 2 Γ· β2 2 =π β3 2 Γβ7=βππ 50Γ· β5 2 =π 1ββ1 Γ 2ββ2 =π β3 3 Γ· β3 2 =βπ Find two numbers which have the specified sum and product. Sum =β7 Product =12 ο -3, -4 Sum =1 Product =β12 ο 4, -3 Sum =β3 Product =β10 ο 2, -5 Sum =5 Product =β24 ο 8, -3 Sum =β11 Product =30 ο -5, -6 Sum =β1 Product =β30 ο 5, -6 Calculate the following: β7+3 β11ββ7 =π β3ββ7 2 Γ3=ππ β =π β2Γ3 3 β β3ββ2 3 =βπππ β4ββ6 (β2ββ3) β 3ββ7 5+ β10 =π 1 3 a ? b ? c ? a ? ? d b ? e ? c ? f ? d ? g ? ? e ? f 2 a ? 4 b ? ? a c ? d ? b ? 3 c ? ? a ? d b ? ? e c ? d ? e ?
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