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Year 7 Negative Numbers Dr J Frost

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Presentation on theme: "Year 7 Negative Numbers Dr J Frost"β€” Presentation transcript:

1 Dr J Frost (jfrost@tiffin.kingston.sch.uk)
Year 7 Negative Numbers Dr J Frost Objectives: Add, subtract, multiply and divide negative numbers, as well as raise a negative number to a power. Last modified: 18th July 2015

2 For Teacher Use: Recommended lesson structure:
Lesson 1: Adding, subtracting negative numbers. Lesson 2: Multiplying, dividing and mixed questions.

3 Visualising negatives with a number line
For any addition/subtraction of numbers, you should ALWAYS visualise a number line. How would we visualise the following? Click > Click > 3βˆ’7=βˆ’πŸ’ βˆ’6+10=πŸ’ Click > Click > βˆ’7+5=βˆ’πŸ βˆ’3βˆ’4=βˆ’πŸ• Bro Tip: Notice that the answer is always either the sum of the two numbers (ignoring sign) or the difference.

4 Test Your Understanding
Copy and complete the following. 6βˆ’11=βˆ’πŸ“ 3βˆ’10=βˆ’πŸ• βˆ’1βˆ’5=βˆ’πŸ” βˆ’10+11=𝟏 βˆ’5+1=βˆ’πŸ’ βˆ’13+6=βˆ’πŸ• βˆ’4βˆ’25=βˆ’πŸπŸ— βˆ’25+4=βˆ’πŸπŸ [JMC 2014 Q7] What is 2014βˆ’4102? πŸ’πŸπŸŽπŸβˆ’πŸπŸŽπŸπŸ’=πŸπŸŽπŸ–πŸ– βˆ΄πŸπŸŽπŸπŸ’βˆ’πŸ’πŸπŸŽπŸ=βˆ’πŸπŸŽπŸ–πŸ– a ? b ? c ? d ? e ? f ? g ? h ? N ?

5 What is the answer. How could we show it?
Adding/subtracting negative numbers 9 + βˆ’3= ? What is the answer. How could we show it? 9+2=𝟏𝟏 9+1=𝟏𝟎 9+0=πŸ— 9+ βˆ’1 =πŸ– 9+ βˆ’2 =πŸ• 9+ βˆ’3 =πŸ” ? ? ?

6 What is the answer. How could we show it?
Adding/subtracting negative numbers 5 βˆ’ βˆ’2= ? What is the answer. How could we show it? 5 βˆ’ 2=πŸ‘ 5 βˆ’ 1=πŸ’ 5 βˆ’ 0=πŸ“ 5 βˆ’ βˆ’1 =πŸ” 5 βˆ’ βˆ’2 =πŸ• 5 βˆ’ βˆ’3 =πŸ– ? ? ? ! +βˆ’ β‡’ βˆ’ A plus and a minus become a minus βˆ’βˆ’ β‡’ Two minuses become a plus.

7 β€œTwo minuses make a plus!”
Common Misunderstanding: β€œTwo minuses make a plus!” βˆ’4βˆ’10=14 What did they do wrong? Two minuses only become a plus when they’re next to each other. If we think about a number line can see the above doesn’t make sense. ? Quickfire Questions: Check Your Understanding: βˆ’5 =𝟐 7 βˆ’ βˆ’5 =𝟏𝟐 βˆ’ βˆ’5 =βˆ’πŸπŸ βˆ’7 βˆ’ βˆ’5 =βˆ’πŸ =𝟏𝟐 7 βˆ’ =𝟐 βˆ’ =βˆ’πŸ βˆ’7 βˆ’ =βˆ’πŸπŸ =πŸπŸ’ 4 βˆ’ =βˆ’πŸ” βˆ’ =πŸ” βˆ’4 βˆ’ =βˆ’πŸπŸ’ βˆ’ =βˆ’πŸ” 4 βˆ’ βˆ’10 =πŸπŸ’ βˆ’ βˆ’10 =βˆ’πŸπŸ’ βˆ’4 βˆ’ βˆ’10 =πŸ” ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?

8 Exercise 1 Find two numbers which have a sum of -2 and a difference of Solution: 3 and -5 [JMC 2010 Q1] What is βˆ’2010 βˆ’ βˆ’(βˆ’2010) ? Solution: 2010 [JMC 2013 Q6] What is the value of 1βˆ’1 βˆ’1 βˆ’ 1βˆ’ 1βˆ’1 ? Solution: -2 [JMO 2007 A1] What is the value of βˆ’ βˆ’ ? Solution: 1 [IMC 2001 Q1] Between which of the following pairs of numbers is there the greatest difference? A -3, 8 B -5, C 1, D 4, E -6, -15 Solution: A [SMC 2009 Q3] What is the value of βˆ’ βˆ’ βˆ’ Solution: 5 [Kangaroo Grey 2004 Q5] What is the value of the expression 1βˆ’2 βˆ’ 3βˆ’4 βˆ’ 5βˆ’6 βˆ’β€¦βˆ’ 99βˆ’ Solution: 48 1 Calculate the following. βˆ’6+15=πŸ— 7βˆ’15=βˆ’πŸ– 4βˆ’ βˆ’7 =𝟏𝟏 9+ βˆ’10 =βˆ’πŸ βˆ’18+7=βˆ’πŸπŸ βˆ’5βˆ’ βˆ’2 =βˆ’πŸ‘ βˆ’20βˆ’ βˆ’13 =βˆ’πŸ• βˆ’1βˆ’ βˆ’1 =𝟎 βˆ’6+ βˆ’8 =βˆ’πŸπŸ’ βˆ’2βˆ’(βˆ’6)=πŸ’ 5βˆ’(βˆ’20)=πŸπŸ“ 3+ βˆ’24 βˆ’4=βˆ’πŸπŸ“ 1βˆ’6βˆ’ βˆ’4 =βˆ’πŸ βˆ’ 6+ βˆ’7 +8=βˆ’πŸ“ Fill in the missing value. βˆ’3+ ∎ = ∎=10 7βˆ’βˆŽ=βˆ’ ∎=17 8+∎= ∎=βˆ’2 βˆ’2βˆ’βˆŽ=βˆ’ ∎=6 βˆ’3βˆ’βˆŽ= ∎=βˆ’13 βˆ’10+∎=βˆ’ ∎=βˆ’20 3 a ? ? b ? 4 c ? d ? e ? ? f ? 5 g ? ? h ? i ? j ? 6 ? k ? l ? m ? 7 n ? ? 2 a ? 8 ? ? b c ? d ? N e ? f ? ?

9 9Γ— βˆ’3 = ? Multiplying Negative Numbers
What is the answer? Could we show it in a similar way to how we showed 9+ βˆ’3 =6? 9+2=𝟏𝟏 9+1=𝟏𝟎 9+0=πŸ— 9+ βˆ’1 =πŸ– 9+ βˆ’2 =πŸ• 9+ βˆ’3 =πŸ” 9Γ—2=πŸπŸ– 9Γ—1=πŸ— 9Γ—0=𝟎 9Γ— βˆ’1 =βˆ’πŸ— 9Γ— βˆ’2 =βˆ’πŸπŸ– 9Γ— βˆ’3 =βˆ’πŸπŸ• ? ? ?

10 βˆ’2 Γ— βˆ’3 = ? Multiplying Negative Numbers
What is the answer? Could we show how to get it by starting with 2Γ— βˆ’3 =βˆ’6? 2Γ—(βˆ’3)=πŸ” 1Γ—(βˆ’3)=πŸ‘ 0Γ—(βˆ’3)=𝟎 (βˆ’1)Γ— βˆ’3 =βˆ’πŸ— (βˆ’2)Γ— βˆ’3 =βˆ’πŸπŸ– ? ? ! π‘π‘œπ‘ Γ—π‘›π‘’π‘”=𝑛𝑒𝑔 π‘›π‘’π‘”Γ—π‘π‘œπ‘ =𝑛𝑒𝑔 𝑛𝑒𝑔×𝑛𝑒𝑔=π‘π‘œπ‘  Same applies to division.

11 Quickfire Examples 4Γ— βˆ’1 =βˆ’πŸ’ βˆ’3 Γ—7=βˆ’πŸπŸ βˆ’5 Γ— βˆ’4 =𝟐𝟎 βˆ’8 Γ·2=βˆ’πŸ’ βˆ’21 Γ· βˆ’7 =πŸ‘ 9Γ· βˆ’3 =βˆ’πŸ‘ βˆ’5 2 =πŸπŸ“ βˆ’2 3 =βˆ’πŸ– βˆ’10βˆ’2 2 =πŸπŸ’πŸ’ ? ? ? ? ? ? ? ? ?

12 (Use the front of your diary for blue)
Use your diary coloured cards to vote for the correct answer in each question. (Use the front of your diary for blue) RED ORANGE GREEN BLUE

13 Calculate: βˆ’πŸ’βˆ’βˆ’πŸ– 4 βˆ’4 12 βˆ’12

14 Calculate: βˆ’πŸπŸŽ Γ—πŸ“ βˆ’5 βˆ’50 50 βˆ’2

15 Calculate: βˆ’πŸπŸΓ·βˆ’πŸ 24 βˆ’10 βˆ’6 6

16 Calculate: βˆ’πŸ‘+πŸπŸ‘ βˆ’πŸ‘βˆ’πŸ 2 βˆ’2 10 βˆ’10

17 Calculate: βˆ’πŸ‘Γ— βˆ’πŸ‘ 𝟐 βˆ’18 βˆ’27 27 18

18 Calculate: βˆ’πŸπŸŽπŸŽΓ· βˆ’πŸ“βˆ’βˆ’πŸ‘ 𝟐 βˆ’25 25 12.5 50

19 Exercise 2 Calculate the following: βˆ’3Γ— βˆ’2 =πŸ” βˆ’12Γ·4=βˆ’πŸ‘ βˆ’9 2 =πŸ–πŸ 4Γ—βˆ’13=βˆ’πŸ“πŸ 16Γ·βˆ’2=βˆ’πŸ– βˆ’30 Γ· βˆ’6 =πŸ“ βˆ’8Γ—3=βˆ’πŸπŸ’ Determine the missing number: 8Γ—βˆŽ=βˆ’32 ∎=βˆ’πŸ’ βˆ’6Γ—βˆŽ=βˆ’18 ∎=πŸ‘ βˆ’8÷∎=βˆ’2 ∎=πŸ’ βˆ’2 2 Γ—βˆŽ=32 ∎=πŸ– βˆ’4 2 Γ· βˆ’2 2 =πŸ’ βˆ’3 2 Γ—βˆ’7=βˆ’πŸ”πŸ‘ 50Γ· βˆ’5 2 =𝟐 1βˆ’βˆ’1 Γ— 2βˆ’βˆ’2 =πŸ– βˆ’3 3 Γ· βˆ’3 2 =βˆ’πŸ‘ Find two numbers which have the specified sum and product. Sum =βˆ’7 Product =12 οƒ  -3, -4 Sum =1 Product =βˆ’12 οƒ  4, -3 Sum =βˆ’3 Product =βˆ’10 οƒ  2, -5 Sum =5 Product =βˆ’24 οƒ  8, -3 Sum =βˆ’11 Product =30 οƒ  -5, -6 Sum =βˆ’1 Product =βˆ’30 οƒ  5, -6 Calculate the following: βˆ’7+3 βˆ’11βˆ’βˆ’7 =𝟏 βˆ’3βˆ’βˆ’7 2 Γ—3=πŸ’πŸ– βˆ’ =𝟏 βˆ’2Γ—3 3 βˆ’ βˆ’3βˆ’βˆ’2 3 =βˆ’πŸπŸπŸ“ βˆ’4βˆ’βˆ’6 (βˆ’2βˆ’βˆ’3) βˆ’ 3βˆ’βˆ’7 5+ βˆ’10 =πŸ’ 1 3 a ? b ? c ? a ? ? d b ? e ? c ? f ? d ? g ? ? e ? f 2 a ? 4 b ? ? a c ? d ? b ? 3 c ? ? a ? d b ? ? e c ? d ? e ?


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