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1.3 – Use Midpoint and Distance Formulas & Segment Constructions
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Midpoint:Point in the middle of a segment A B M M is the midpoint of
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Segment bisector: Point, line, or segment that cuts a segment in half ABM pt. M bisects ABM C D bisects
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Perpendicular:Line that intersects at a right angle AB C D
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Perpendicular bisector: Perpendicular Line or segment that bisects a segment ABM C D
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Distance: Length between two points AB Measured in units
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17cm DF = 34cm 1. Line bisects the segment. Find the indicated length.
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GJ = 16 1212 in 1. Line bisects the segment. Find the indicated length.
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2. M is the midpoint of the segment. Find the indicated length. Find MF. 7x – 6 = 5x – 6 = -2x 3 = x MF =5(3) =15u
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2. M is the midpoint of the segment. Find the indicated length. Find LN. 11x – 21 = 8x + 15 3x – 21 = 15 3x = 36 x = 12 LN =11(12)-21 + 8(12)+15 = 132 – 21 + 96 +15 = 222u
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3. Find the midpoint and distance of AB, where A(2, 5) and B(2, -3). A B M M(2, 1)
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A B AB =8u8u 3. Find the midpoint and distance of AB, where A(2, 5) and B(2, -3).
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4. Find the midpoint and distance of AB, where A(-3, 4) and B(7, 4). A B M M(2, 4)
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A B AB = 10u 4. Find the midpoint and distance of AB, where A(-3, 4) and B(7, 4).
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5. Find the midpoint and distance of AB, where A(5, 8) and B(1, 2). A B M M(3, 5)
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A B 5. Find the midpoint and distance of AB, where A(5, 8) and B(1, 2). 4 6 4 2 + 6 2 = c 2 c 16 + 36 = c 2 52 = c 2 = c AB = u
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Midpoint Formula: Remember! Your answer should be an ordered pair!
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Distance Formula: Don’t forget your units!
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6. Find the midpoint and distance of AB, where A(-6, 2)and B(-2, -3). midpt AB =
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u (-2 – (-6)) 2 + (-3 – 2) 2 (4) 2 +(-5) 2 16 +25 6. Find the midpoint and distance of AB, where A(-6, 2)and B(-2, -3).
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7. Find the midpoint and distance of AB, where A(-1, 2)and B(3, 4). midpt AB =
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u (3 – (-1)) 2 + (4 – 2) 2 (4) 2 +(2) 2 16 +4 7. Find the midpoint and distance of AB, where A(-1, 2)and B(3, 4).
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The endpoints of two segments are given. Find each segment length. Tell whether the segments are congruent. P Q R S
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Not (-1 – 4) 2 + (6 – 3) 2 (-5) 2 + (3) 2 25 +9 (-2 – 2) 2 + (0 – (-3)) 2 (-4) 2 +(3) 2 16 +9
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HW Problem 1.319-222, 3-21 odd, 24, 33, 37, 43, 57-59 What does the red circle mean around the problem number? **Bring your protractor tomorrow! # 15 x + 15 = 4x – 45 15 = 3x – 45 60 = 3x 20 = x SU = 2(20+15) SU = 2(35) SU = 70u
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