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Applications of Differentiation Curve Sketching
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Why do we need this? The analysis of graphs involves looking at “interesting” points and intervals and at horizontal and vertical asymptotes. We use calculus techniques to help us find all of the important aspects of the graph of a function so that we don’t have to plot a large number of points. Curve Sketching
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Graphing Skills AKA skills you will have when this chapter has ended Domain and Range Symmetry x and y intercepts Asymptotes Extrema Inflection Points Curve Sketching
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4 Extrema on an Interval Extrema of a Function ● Relative Extrema and Critical Numbers ● Finding Extrema on a Closed Interval Curve Sketching
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Global Extrema Example Curve Sketching
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Lets look at the following function: How many horizontal tangent lines does this curve have? What is the slope of a horizontal tangent? Curve Sketching
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Finding Horizontal Tangents Differentiate: Set the derivative equal to zero (slope =0): Solve for x: This is the x coordinate where you have a horizontal tangent on your graph. Curve Sketching
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Finding Horizontal Tangents Differentiate: Set the derivative equal to zero (slope =0): Solve for x: This is the x coordinate where you have a horizontal tangent on your graph. Curve Sketching
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Finding Horizontal Tangents Differentiate: Set the derivative equal to zero (slope =0): Solve for x: This is the x coordinate where you have a horizontal tangent on your graph. Curve Sketching
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Vertical Tangents Keep in mind where the derivative is defined: When x = 0 we have slope that is undefined This is where we have a vertical tangent line. This counts as a critical number as well and should be considered as such. Curve Sketching
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Definition of Extrema Let f be defined on an interval I containing c. 1.f(c) is the maximum of f on I if f(c) > f(x) for all x on I. 2.f(c) is the minimum of f on I if f(c) < f(x) for all x on I. The maximum and minimum of a function on an interval are the extreme values, or extrema, of the function on the interval. The maximum and minimum of a function on an interval are also called the absolute maximum and absolute minimum on the interval, respectfully. Curve Sketching
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Definition of a Critical Number Critical numbers are numbers you check to locate any extrema. Let f be defined at c. If f ‘(c) = 0 or if f is undefined at c, then c is a critical number Curve Sketching
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Finding Extrema on a Closed Interval Step 1: find the critical numbers of f in (a,b) Step 2: Evaluate f at each critical number in (a,b) Step 3: Evaluate f at each endpoint of [a,b] Step4: The least of the values is the minimum, the greatest is the maximum. Curve Sketching
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Theorem: Relative Extrema Occur only at Critical Numbers If f has a relative minimum or relative maximum at x = c, then c is a critical number of f. These are also known as locations of horizontal tangents Curve Sketching
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Critical Numbers Let f be defined at c. if f’(c)=0 or if f is not differentiable at c, then c is a critical number of f. Relative extrema (max or min) occur only at a critical number. Curve Sketching
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Relative Extrema Curve Sketching
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Additional Extrema on a Closed Interval-examples: Curve Sketching
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Locate the Absolute Extrema
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19 Finding Extrema on a Closed Interval Left Endpoint Critical Number Right Endpoint f(-1)=7f(0)=0f(1)=-1 Minimum f(2)=16 Maximum Find the extrema: Differentiate the function: Find all values where the derivative is zero or UND: Given endpoints, consider them too!!! Curve Sketching
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Homework for 3.1 Page 169-171#1-46 #61-64 are physics problems #65-70 are good thinking problems Curve Sketching
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First Derivative Test (Ch.3 S.3) Finding the critical numbers: C is called a critical number for f if f’(c)=0 (horizontal tangent line) or f’(c) does not exist Curve Sketching
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Increasing or Decreasing functions A function f is called increasing on a given interval (open or closed) if for x 1 any and x 2 in the interval, such that x 2 > x 1, f(x 2 )>f(x 1 ) A function f is called decreasing on a given interval (open or closed) if for x 1 any and x 2 in the interval, such that x 2 > x 1, f(x 2 )<f(x 1 ) Curve Sketching
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Maximums, Minimums, Increasing, Decreasing Let the graph represent some function f. 1 2 3 1 1 2 2 2 3 a bdefc Curve Sketching
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Copyright © Houghton Mifflin Company. All rights reserved. 3-24 Definitions of Increasing and Decreasing Functions and Figure 3.15
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Copyright © Houghton Mifflin Company. All rights reserved. 3-25 Theorem 3.6 The First Derivative Test
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Finding Intervals Where the Function is Increasing/Decreasing Curve Sketching
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Finding Intervals Where the Function is Increasing/Decreasing Curve Sketching
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Finding Intervals Where the Function is Increasing/Decreasing Curve Sketching
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Increasing and Decreasing Example Curve Sketching
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LOCAL (RELATIVE) EXTREME VALUES If x = c is not at an endpoint, then f (c) is a local (relative) maximum value for f(x) if f(c) > or = f(x) for all x-values in a small open interval around x = c. If x = c is not at an endpoint, then f (c) is a local (relative) minimum value for f(x) if f(c) < or = f(x) for all x-values in a small open interval around x = c. Curve Sketching
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Finding local extrema Curve Sketching
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Local Extrema Example See text for additional examples Curve Sketching
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Homework for 3.3 pg. 186 #9-38, 43-50, 65-84 (good for AP) Curve Sketching
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3.4 Concavity and the Second Derivative Test Second Derivative Test
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Copyright © Houghton Mifflin Company. All rights reserved. 3-35 Definition of Concavity and Figure 3.24
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The graph of f is called concave up on a given interval if for any two points on the interval, the graph of f lies below the chord that connects these points. Concavity
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The graph of f is called concave down on a given interval if for any two points on the interval, the graph of f lies above the chord that connects these points.
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Copyright © Houghton Mifflin Company. All rights reserved. 3-38 Theorem 3.7 Test for Concavity
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Copyright © Houghton Mifflin Company. All rights reserved. 3-39 Definition of Point of Inflection and Figure 3.28
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Copyright © Houghton Mifflin Company. All rights reserved. 3-40 Theorem 3.8 Points of Inflection
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Copyright © Houghton Mifflin Company. All rights reserved. 3-41 Theorem 3.9 Second Derivative Test and Figure 3.31
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Second Derivative Test Finding the points of inflection: C is called a point of interest for f if f’’(c)=0 or f’(c) does not exist. NOTE: The fact that f’’(x) = 0 alone does not mean that the graph of f has an inflection point at x. We must find the points where the concavity changes.
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Points of Inflection A point of inflection is a point where the concavity of the graph changes from concave up to down or vice-versa.
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Concavity and the Second Derivative Test Curve Sketching
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Homework for 3.4 P. 195 #1-52, 61-68 (good for AP prep) Curve Sketching
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Limits at Infinity (3.5) Curve Sketching
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What happens at x = 1? What happens near x = 1? As x approaches 1, g increases without bound, or g approaches infinity. As x increases without bound, g approaches 0. As x approaches infinity g approaches 0. asymptotes
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xx-11/(x-1)^2 0.9-0.1100.00 0.91-0.09123.46 0.92-0.08156.25 0.93-0.07204.08 0.94-0.06277.78 0.95-0.05400.00 0.96-0.04625.00 0.97-0.031,111.11 0.98-0.022,500.00 0.99-0.0110,000.00 10Undefined 1.010.0110,000.00 1.020.022,500.00 1.030.031,111.11 1.040.04625.00 1.050.05400.00 1.060.06277.78 1.070.07204.08 1.080.08156.25 1.090.09123.46 1.100.1100.00 vertical asymptotes
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xx-11/(x-1)^2 10Undefined 211 540.25 1090.01234567901234570 50490.00041649312786339 100990.00010203040506071 5004990.00000401604812832 1,0009990.00000100200300401 10,00099990.00000001000200030 100,000999990.00000000010000200 1,000,0009999990.00000000000100000 10,000,00099999990.00000000000001000 100,000,000999999990.00000000000000010 horizontal asymptotes
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AKA Limits at infinity We know that And we know that So we can expand on this… horizontal asymptotes
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Theorem: If r is a positive rational number and c is any real number, then Furthermore, if is defined when x<0, then horizontal asymptotes
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Theorem: The line y=L is a horizontal asymptote of the graph of f if or Limits at Infinity
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Examples: Finding a limit at infinity Limits at Infinity
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Finding a limit at infinity Direct substitution yields indeterminate form! Now we need to do algebra to evaluate the limit: Divide each term by x: Simplify: Evaluate (keep in mind each 1/x 0) Limits at Infinity
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A comparison (AKA the shortcut!) Direct substitution yields infinity/infinity! Do algebra: Notice a pattern????? Limits at Infinity
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A comparison (AKA the shortcut!) Direct substitution yields infinity/infinity! Do algebra: Bottom HeavyBalanced Top Heavy Limits at Infinity
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Limits with 2 horizontal asymptotes
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Homework Page 205 #2-38E Curve Sketching
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Curve Sketching 3.6 The following slides combine all of our new graphing and analysis skills with our precalculus skills
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Example: Curve Sketching
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Asymptotes: Polynomial functions do not have asymptotes. a) Vertical: No vertical asymptotes because f(x) is continuous for all x. b) Horizontal: No horizontal asymptotes because f(x) is unbounded as x goes to positive or negative infinity. Curve Sketching
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Intercepts: a) y-intercepts: f(0)=1 y-intercept: (0,1) b) x-intercepts: difficult to find – use TI-89 Curve Sketching
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Critical numbers: a) Take the first derivative: b) Set it equal to zero: c) Solve for x: x=1, x=3 Curve Sketching
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Critical Points: a)Critical numbers x=1 and x=3 b) Find corresponding values of y: c) Critical points: (1,5) and (3,1) Curve Sketching
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Increasing/Decreasing: a) Take the first derivative: b) Set it equal to zero: c) Solve for x: x=1, x=3 Curve Sketching
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d) Where is f(x)undefined? Nowhere e) Sign analysis: Plot the numbers found above on a number line. Choose test values for each interval created and evaluate the first derivative: Increasing/Decreasing:
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Extrema f’(x) changes from positive to negative at x=1 and from negative to positive at x=3 so and are local extrema of f(x). Note: Values of corresponding to local extrema of must: Be critical values of the first derivative – values at which equals zero or is undefined, Lie in the domain of the function, and Be values at which the sign of the first derivative changes. Curve Sketching
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f(x) is increasing before x=1 and decreasing after x=1. So (1,5) is a maximum. f(x) is decreasing before x=3 and increasing after x=3. So (3,1) is a minimum. First Derivative Test Curve Sketching
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SECOND DERIVATIVE TEST Alternate method to find relative max/min: a) Take the second derivative: b) Substitute x-coordinates of extrema: (negative local max) (positive local min) c) Label your point(s): local max: (1,5) local min: (3,1) Curve Sketching
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Concave Up/Down Curve Sketching
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Inflection Points Curve Sketching
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Create a table of the values obtained: Curve Sketching x0123 f(x) f’(x) f’’(x)
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Curve Sketching
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Graphing Functions
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Domain and Range Domain : evaluate where the function is defined and undefined, values of discontinuity (under radicals, holes, etc.), nondifferentiability (sharp turns, vertical tangent lines and points of discontinuity). Range : evaluate the values of y after graphing. Look for minimum and maximum values and discontinuities vertically.
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Domain and Range
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Finding the Range of a Function We will look at this AFTER we graph the equation using calculus, you can graph it on the calculator now if you like. Curve Sketching
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Symmetry About the y-axis: Replace x with –x and you get the same equation after you work the algebra About the x-axis: Replace y with –y and you get the same equation after you work the algebra About the origin: Replace x with –x and y with –y and get the same equation after you work the algebra Curve Sketching
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Graphing Functions Do we have symmetry about the y-axis? replace x with –x and we get: Are these equivalent equations? NO! So we do not have symmetry about the y-axis. Curve Sketching
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Graphing Functions Do we have symmetry about the x-axis? replace y with –y and we get: Are these equivalent equations? NO! So we do not have symmetry about the x-axis. Curve Sketching
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Graphing Functions Do we have symmetry about the origin? replace x with –x and y with –y and we get: Are these equivalent equations? NO! So we do not have symmetry about the origin. Curve Sketching
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x and y-intercepts x-intercepts: Set top of the fraction equal to 0 in the original equation and solve for x values. y-intercepts: Substitute 0 in for x and solve for y values.
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x-intercepts Replace y with 0 and we get ??? so do we cross the x- axis?
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y-intercepts Replace x with 0 and we get y = -2 so we cross the y-axis at (0,-2) Curve Sketching
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Horizontal Asymptotes The line y=L is called a horizontal asymptote for f if the limit as x approaches infinity from both the left and/or right is equal to L In other words, find the original equation as x approaches positive or negative infinity. Limits at Infinity Curve Sketching
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Horizontal Asymptotes As x goes to infinity what happens to our equation? It goes to infinity as well. So we have no horizontal asymptotes Curve Sketching
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Vertical Asymptotes The line x=c is called a vertical asymptote for f at x=c if the limit goes to positive or negative infinity as x approaches c from the positive and/or negative side. This is the complicated way of saying set the denominator (if there is one) to zero and find the x values. Infinite Limits Curve Sketching
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Vertical Asymptotes We set the denominator to equal zero and find that we have an asymptote at x = 2 Curve Sketching
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Slant Asymptotes Given a function that consists of a composition of functions: If there are no common factors in the numerator and denominator, perform long division. The NONfractional part gives you the equation of the slant asymptotes. Curve Sketching
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Graphing Functions Performing long division: we get a non- fractional part of the answer of y = x for our slanted asymptote Curve Sketching
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First Derivative Test Take the derivative of the function, set it equal to 0 and find the corresponding values of x. These are our CRITICAL POINTS (Potential extrema)
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Graphing Functions Take the second derivative Set it equal to 0 Solve for x This is our potential point of inflection
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Graphing Functions Here we compile all of the information to enable us to give a pretty accurate graph WITHOUT technology
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Organize the Information xf(x)f’(x)f’’(x)Conclusion -∞<x<0+-Increasing, concave down X=0-20-Relative Max 0<x<2--Decreasing, concave down X=2Undef Vertical asymptote 2<x<4-+Decreasing, concave up X=460+Relative min 4<x<∞++Increasing, concave up
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Homework: Page 215 #1-45, (67-71 are good thinking problems) Curve Sketching
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