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TTS 171 : PART 1: 2002 ANNEX E PRESENTER WINSTON THOMAS ELECTRICALINSPECTOR 1 ELECTRICAL INSPECTOR 1
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MAXIMUM CONDUCTORS IN CONDUIT AND BOXES Objective Simple guide Calculation
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Cont’d. Maximum number of cables Conduits Boxes
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CONDUITS Electrical Metallic Tubing or E.M.T Steel heavy gauge conduit PVC conduit
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Surroundings Ambient temperature Level of mechanical protection APPLICATION
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CAPACITIES For the maximum capacities Reference to Annex E Relevant table
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TABLES IN ANNEX E Four tables Maximum PVC insulated non sheathed cables Space factor of 40 %
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Cont’d. Two 90 0 bends Additional bends Cables reduced
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USE OF TABLES Calculate number of cables for circuit Choose cable size in column Use maximum number of cables column
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Cont’d. Choose value equal to or greater than number of cables Go to corresponding column for conduit size
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TABLE E 2a Covers maximum capacities Steel conduit and E.M.T PVC insulated non-sheathed single core cables
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Cont’d. Same cross-sectional area Imperial, AWG or MCM and Metric sizes
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Example A 115/230V single phase a.c circuit requiring 16mm 2 single core cables is to be run in an E.M.T conduit. To determine conduit size.
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Calculate Number of cables. (3) Cable size column. (16mm 2 ) Maximum number cables column. (4) Corresponding conduit size of 27 mm or (1 in).
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Table E 2b Covers maximum capacities. Steel heavy gauge conduits. PVC insulated cables of same cross-sectional area.
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Example Using three 16mm 2 cables as in the previous example. Follow same steps. Conduit size approximately the same.(25mm)
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Table E 2c Covers maximum capacities. PVC conduits PVC insulated cables of same cross-sectional area
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Example Same circuit to be run in PVC conduit. A grounding conductor is now required. Number of cables. ( 4 )
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Cont’d Maximum number of cables column. (5) Conduit size - 32mm
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Table E1 New addition to code. Covers maximum capacities. All types of conduits.
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Cont’d PVC insulated cables of different cross-sectional areas Conduit factor Conductor factor.
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Four 2.5mm 2, four 4.0mm 2 and two 6.0mm 2 cables, are to be drawn into a conduit. Total conductor factor = Sum of cable conductor factors. Example
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Cont’d. Conduit factor shall be equal to or greater than total conductor factor.
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4 x 4.0mm 2 factor = 4 x 39 = 156 2 x 6.0mm 2 factor = 2 x 50 = 100 Total 376 Conduit factor - 486 Conduit 27mm ( 1 in. ) 4 x 2.5mm 2 factor = 4 x 30 = 120
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CAPACITIES OF BOXES Table E 3 New addition to code. Maximum capacities. Outlet and junction boxes
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Sixteen 4.0mm 2 cables to be spliced in a box. Determine size of box. First go to column for 4.0mm cables. Example
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Cont’d. Then to row where value is equal to or greater than sixteen. Then to box in corresponding row. (4 11/16 x 2 1/8)
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THE END
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