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1 Introduction to Bioinformatics 2 Introduction to Bioinformatics. LECTURE 5: Variation within and between species * Chapter 5: Are Neanderthals among.

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Presentation on theme: "1 Introduction to Bioinformatics 2 Introduction to Bioinformatics. LECTURE 5: Variation within and between species * Chapter 5: Are Neanderthals among."— Presentation transcript:

1

2 1 Introduction to Bioinformatics

3 2 Introduction to Bioinformatics. LECTURE 5: Variation within and between species * Chapter 5: Are Neanderthals among us?

4 3 Neandertal, Germany, 1856 Initial interpretations: * bear skull * pathological idiot * Old Dutchman...

5 4 Introduction to Bioinformatics LECTURE 5: INTER- AND INTRASPECIES VARIATION

6 5

7 6

8 7 5.1 Variation in DNA sequences * Even closely related individuals differ in genetic sequences * (point) mutations : copy error at certain location * Sexual reproduction – diploid genome

9 8 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES Diploid chromosomes

10 9 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES Mitosis: diploid reproduction

11 10 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES Meiosis: diploid (=double) → haploid (=single)

12 11 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES * typing error rate very good typist: 1 error / 1K typed letters * all our diploid cells constantly reproduce 7 billion letters * typical cell copying error rate is ~ 1 error /1 Gbp

13 12 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES GERM LINE Reverse time and follow your cells: Now you count ~ 10 13 cells One generation ago you had 2 cells ‘somewhere’ in your parents body Small T generations ago you had (2 T – multiple ancestors) cells Large T generations ago you counted #(fertile ancestors) cells Congratulations: you are 3.4 billion years old !!! Fast-forward time and follow your cells: Only a few cells in your reproductive organs have a chance to live on in the next generations The rest (including you) will die …

14 13 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES GERM LINE MUTATIONS This potentially immortal lineage of (germ) cells is called the GERM LINE All mutations that we have accumulated are en route on the germ line

15 14 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES * Polymorphism : multiple possibilities for a nucleotide: allelle * Single Nucleotide Polymorphism – SNP (“snip”) point mutation example: AAATAAA vs AAACAAA * Humans: SNP = 1/1500 bases = 0.067% * STR = Short Tandem Repeats (microsatelites) example: CACACACACACACACACA … * Transition - transversion

16 15 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES Purines – Pyrimidines

17 16 Introduction to Bioinformatics 5.1 VARIATION IN DNA SEQUENCES Transitions – Transversions

18 17 Introduction to Bioinformatics LECTURE 5: INTER- AND INTRASPECIES VARIATION 5.2 Mitochondrial DNA * mitochondriae are inherited only via the maternal line!!! * Very suitable for comparing evolution, not reshuffled

19 18 Introduction to Bioinformatics 5.2 MITOCHONDRIAL DNA H.sapiens mitochondrion

20 19 Introduction to Bioinformatics 5.2 MITOCHONDRIAL DNA EM photograph of H. Sapiens mtDNA

21 20 Introduction to Bioinformatics 5.2 MITOCHONDRIAL DNA

22 21 Introduction to Bioinformatics LECTURE 5: INTER- AND INTRASPECIES VARIATION 5.3 Variation between species * genetic variation accounts for morphological- physiological-behavioral variation * Genetic variation (c.q. distance) relates to phylogenetic relation (=relationship) * Necessity to measure distances between sequences: a metric

23 22 Introduction to Bioinformatics 5.3 VARIATION BETWEEN SPECIES Substitution rate * Mutations originate in single individuals * Mutations can become fixed in a population * Mutation rate: rate at which new mutations arise * Substitution rate: rate at which a species fixes new mutations * For neutral mutations

24 23 Introduction to Bioinformatics 5.3 VARIATION BETWEEN SPECIES Substitution rate and mutation rate * For neutral mutations * ρ = 2Nμ*1/(2N) = μ * ρ = K/(2T)

25 24 Introduction to Bioinformatics LECTURE 5: INTER- AND INTRASPECIES VARIATION 5.4 Estimating genetic distance * Substitutions are independent (?) * Substitutions are random * Multiple substitutions may occur * Back-mutations mutate a nucleotide back to an earlier value

26 25 Introduction to Bioinformatics 5.4 ESTIMATING GENETIC DISTANCE Multiple substitutions and Back-mutations conceal the real genetic distance GACTGATCCACCTCTGATCCTTTGGAACTGATCGT TTCTGATCCACCTCTGATCCTTTGGAACTGATCGT TTCTGATCCACCTCTGATCCATCGGAACTGATCGT GTCTGATCCACCTCTGATCCATTGGAACTGATCGT observed : 2 (= d) actual : 4 (= K)

27 26 Introduction to Bioinformatics 5.4 ESTIMATING GENETIC DISTANCE * Saturation: on average one substitution per site * Two random sequences of equal length will match for approximately ¼ of their sites * In saturation therefore the proportional genetic distance is ¼

28 27 Introduction to Bioinformatics 5.4 ESTIMATING GENETIC DISTANCE * True genetic distance (proportion): K * Observed proportion of differences: d * Due to back-mutations K ≥ d

29 28 Introduction to Bioinformatics 5.4 ESTIMATING GENETIC DISTANCE SEQUENCE EVOLUTION is a Markov process: a sequence at generation (= time) t depends only the sequence at generation t-1

30 29 Introduction to Bioinformatics 5.4 ESTIMATING GENETIC DISTANCE The Jukes-Cantor model Correction for multiple substitutions Substitution probability per site per second is α Substitution means there are 3 possible replacements (e.g. C → {A,G,T}) Non-substitution means there is 1 possibility (e.g. C → C)

31 30 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL Therefore, the one-step Markov process has the following transition matrix: M JC = ACGT A1-αα/3α/3α/3 Cα/31-αα/3α/3 Gα/3α/31-αα/3 Tα/3α/3α/31-α

32 31 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL After t generations the substitution probability is: M(t) = M JC t Eigen-values and eigen-vectors of M(t): λ 1 = 1, (multiplicity 1):v 1 = 1/4 (1 1 1 1) T λ 2..4 = 1- 4 α/ 3, (multiplicity 3): v 2 = 1/4 (-1 -1 1 1) T v 3 = 1/4 (-1 -1 -1 1) T v 4 = 1/4 (1 -1 1 -1) T

33 32 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL Spectral decomposition of M(t): M JC t = ∑ i λ i t v i v i T Define M(t) as: M JC t = Therefore, substitution probability s(t) per site after t generations is: s(t) = ¼ - ¼ (1 - 4 α/ 3 ) t r(t) s(t) s(t) s(t) s(t) r(t) s(t) s(t) s(t) s(t) r(t) s(t) s(t) s(t) s(t) r(t)

34 33 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL substitution probability s(t) per site after t generations: s(t) = ¼ - ¼ (1 - 4 α/ 3 ) t observed genetic distance d after t generations ≈ s(t) : d = ¼ - ¼ (1 - 4 α/ 3 ) t For small α :

35 34 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL For small α the observed genetic distance is: The actual genetic distance is (of course): K = αt So: This is the Jukes-Cantor formula : independent of α and t.

36 35 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL The Jukes-Cantor formula : For small d using ln(1+x) ≈ x : K ≈ d So: actual distance ≈ observed distance For saturation: d ↑ ¾ : K →∞ So: if observed distance corresponds to random sequence- distance then the actual distance becomes indeterminate

37 36 Jukes-Cantor

38 37 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL Variance in K If: K = f(d) then: So: Generation of a sequence of length n with substitution rate d is a binomial process: and therefore with variance: Var(d) = d(1-d)/n Because of the Jukes-Cantor formula:

39 38 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL Variance in K Variance: Var(d) = d(1-d)/n Jukes-Cantor: So:

40 39 Var(K)

41 40 Introduction to Bioinformatics 5.4 THE JUKES-CANTOR MODEL EXAMPLE 5.4 on page 90 * Create artificial data with n = 1000: generate K* mutations * Count d * With Jukes-Cantor relation reconstruct estimate K(d) * Plot K(d) – K*

42 41 Introduction to Bioinformatics 5.4 EXAMPLE 5.4 on page 90

43 42 Introduction to Bioinformatics 5.4 EXAMPLE 5.4 on page 90

44 43 Introduction to Bioinformatics 5.4 EXAMPLE 5.4 on page 90

45 44 Introduction to Bioinformatics 5.4 EXAMPLE 5.4 on page 90 (= FIG 5.3)

46 45 Introduction to Bioinformatics 5.4 ESTIMATING GENETIC DISTANCE The Kimura 2-parameter model Include substitution bias in correction factor Transition probability (G↔A and T↔C) per site per second is α Transversion probability (G↔T, G↔C, A↔T, and A↔C) per site per second is β

47 46 Introduction to Bioinformatics 5.4 THE KIMURA 2-PARAM MODEL The one-step Markov process substitution matrix now becomes: M K2P = ACGT A1-α-β β αβ Cβ 1-α-β β α Gαβ 1-α-ββ Tβ αβ 1-α-β

48 47 Introduction to Bioinformatics 5.4 THE KIMURA 2-PARAM MODEL After t generations the substitution probability is: M(t) = M K2P t Determine of M(t): eigen-values {λ i } and eigen-vectors {v i }

49 48 Introduction to Bioinformatics 5.4 THE KIMURA 2-PARAM MODEL Spectral decomposition of M(t): M K2P t = ∑ i λ i t v i v i T Determine fraction of transitions per site after t generations : P(t) Determine fraction of transitions per site after t generations : Q(t) Genetic distance: K ≈ - ½ ln(1-2P-Q) – ¼ ln(1 – 2Q) Fraction of substitutions d = P + Q → Jukes-Cantor

50 49 Introduction to Bioinformatics 5.4 ESTIMATING GENETIC DISTANCE Other models for nucleotide evolution * Different types of transitions/transversions * Pairwise substitutions GTR (= General Time Reversible) model * Amino-acid substitutions matrices * …

51 50 Introduction to Bioinformatics 5.4 ESTIMATING GENETIC DISTANCE Other models for nucleotide evolution DEFICIT: all above models assume symmetric substitution probs; prob(A→T) = prob(T→A) Now strong evidence that this assumption is not true Challenge: incorporate this in a self-consistent model

52 51 Introduction to Bioinformatics LECTURE 5: INTER- AND INTRASPECIES VARIATION 5.5 CASE STUDY: Neanderthals * mtDNA of 206 H. sapiens from different regions * Fragments of mtDNA of 2 H. neanderthaliensis, including the original 1856 specimen. * all 208 samples from GenBank * A homologous sequence of 800 bp of the HVR could be found in all 208 specimen.

53 52 Introduction to Bioinformatics 5.5 CASE STUDY: Neanderthals * Pairwise genetic difference – corrected with Jukes-Cantor formula * d(i,j) is JC-corrected genetic difference between pair (i,j); * d T = d * MDS (Multi Dimensional Scaling): translate distance table d to a nD-map X, here 2D-map

54 53 Introduction to Bioinformatics 5.5 CASE STUDY: Neanderthals distance map d(i,j)

55 54 Introduction to Bioinformatics 5.5 CASE STUDY: Neanderthals MDS H. sapiens H. neanderthaliensis well-separated

56 55 Introduction to Bioinformatics 5.5 CASE STUDY: Neanderthals phylogentic tree

57 56 END of LECTURE 5

58 57 Introduction to Bioinformatics LECTURE 5: INTER- AND INTRASPECIES VARIATION

59 58


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