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1 Lec. 2 Faraday’s Laws Lec. 2 Faraday’s Laws Industrial Electrolytic Processes “Electrolysis”

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Presentation on theme: "1 Lec. 2 Faraday’s Laws Lec. 2 Faraday’s Laws Industrial Electrolytic Processes “Electrolysis”"— Presentation transcript:

1 1 Lec. 2 Faraday’s Laws Lec. 2 Faraday’s Laws Industrial Electrolytic Processes “Electrolysis”

2 2 What you should learn What is electrolysis? Faraday's laws of electrolysisFaraday's laws of electrolysis Industrial Applications of electrolytic processIndustrial Applications of electrolytic process

3 3 It is used industrially in a number of ways: 1.Electroplatig. 2.The preparation of gases, notably chlorine. 3.Water decomposition. 4.The extraction of metals, notably aluminum, magnesium, and sodium. 5.The refining of metals, such as copper and zinc.

4 2. Electrolysis of Molten Salts and Production of Cl2 4

5 +- battery Na (l) Cathode Anode Molten NaCl Na + Cl - Na + Na + + e -  Na 2Cl -  Cl 2 + 2e - Cl 2 (g) escapes Observe the reactions at the electrodes NaCl (l) (-) Cl - (+)

6 Molten NaCl Electrolytic Cell cathode half-cell (-) REDUCTION Na + + e -  Na anode half-cell (+) OXIDATION 2Cl -  Cl 2 + 2e - overall cell reaction 2Na + + 2Cl -  2Na + Cl 2 X 2

7 7 Electrolysis of Diluted NaCl

8 battery +- power source e-e- e-e- NaCl (aq) (-)(+) cathode different half-cell Aqueous NaCl anod ee 2Cl -  Cl 2 + 2e - Na + Cl - H2OH2O What could be reduced at the cathode?

9 Aqueous NaCl Electrolytic Cell possible cathode half-cells (-) REDUCTION Na + + e -  Na 2H 2 0 + 2e -  H 2 + 2OH - possible anode half-cells (+) OXIDATION2Cl -  Cl 2 + 2e - 2H 2 O  O 2 + 4H + + 4e - overall cell reaction 2Cl - + 2H 2 0  H 2 + Cl 2 + 2OH -

10 3. Water electrolysis 10

11 11 The Electrolysis of Water containing some sulfates 2 H 2 O + 2e -  H 2 (g) + 2 OH - cathode reaction 2H 2 O  O 2 (g) + 4H + + 4e - anode reaction Cell diagram Battery, a source of direct current e - flow Cathode Anode e - flow aqueous K 2 SO 4 O 2 gas H 2 gas + pole of battery- pole of battery

12 12 The Electrolysis ofwater

13 4. Extraction of Metals 13

14 carbon-lined steel vessel acts as cathode CO 2 bubbles Al (l) Al 2 O 3 (l) Draw off Al (l) - + Cathode: Al +3 + 3e -  Al (l) Anode: 2 O -2 + C (s)  CO 2 (g) + 4e - from power source Al +3 O -2 Al +3 O -2 graphite anodes  e- e- e- e- 

15 The Hall Process Cathode: Al +3 + 3e -  Al (l) Anode: 2 O -2 + C (s)  CO 2 (g) + 4e - 4 Al +3 + 6 O -2 + 3 C (s)  4 Al (l) + 3 CO 2 (g) x 4 x 3 The graphite anode is consumed in the process.


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