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Kenneth M. Klemow, Ph.D. Wilkes University Prepared for BIO/EES 105 Energy in our World III. Room heating and biological dimensions.

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Presentation on theme: "Kenneth M. Klemow, Ph.D. Wilkes University Prepared for BIO/EES 105 Energy in our World III. Room heating and biological dimensions."— Presentation transcript:

1 Kenneth M. Klemow, Ph.D. Wilkes University Prepared for BIO/EES 105 Energy in our World III. Room heating and biological dimensions

2  Indoor environments often more comfortable than outdoor. ◦ Stay dry ◦ Regulate light ◦ Regulate temperature  People prefer temperatures between 65-75 o F ◦ When T<65, we heat ◦ When T>75, we cool  Indoor environments often more comfortable than outdoor. ◦ Stay dry ◦ Regulate light ◦ Regulate temperature  People prefer temperatures between 65-75 o F ◦ When T<65, we heat ◦ When T>75, we cool

3  When cold we add heat via radiators, fireplaces, space heaters  Heat generators warm the air via radiant energy  If air carried away, need to warm the new air. ◦ Energy needed = 0.018 BTU / ft 3 / o F  When cold we add heat via radiators, fireplaces, space heaters  Heat generators warm the air via radiant energy  If air carried away, need to warm the new air. ◦ Energy needed = 0.018 BTU / ft 3 / o F

4  Imagine you come upon a small, uninhabited, single-roomed cabin in the winter ◦ Height = 10’ ◦ Width = 20’ ◦ Length = 20’  It’s 15 o F outside, you want to heat it to 65 o F.  How many BTUs will it take?  Imagine you come upon a small, uninhabited, single-roomed cabin in the winter ◦ Height = 10’ ◦ Width = 20’ ◦ Length = 20’  It’s 15 o F outside, you want to heat it to 65 o F.  How many BTUs will it take?

5  If energy costs $30.00 / million BTUs, how much will initially heating the cabin cost?

6  Heat losses due to conduction through the walls.  Heat losses due to infiltration of cold air.  Heat losses due to conduction through the walls.  Heat losses due to infiltration of cold air.

7  Building has four walls, a ceiling, and a floor ◦ Heat will be lost through each ◦ Go back to formula Q/t = (k x A x  T)   k = thermal conductivity of wall / floor / ceiling   = thickness  For building material, we don’t consider thermal conductivity, per se.  Instead we express as thermal resistance (R value), where R =  /k. ◦ Units = ft 2 -hr- o F/Btu  Building has four walls, a ceiling, and a floor ◦ Heat will be lost through each ◦ Go back to formula Q/t = (k x A x  T)   k = thermal conductivity of wall / floor / ceiling   = thickness  For building material, we don’t consider thermal conductivity, per se.  Instead we express as thermal resistance (R value), where R =  /k. ◦ Units = ft 2 -hr- o F/Btu

8 MaterialThicknessR value Plywood0.5”0.62 Fiberglass insulation 3.5”10.9 Hardwood floor 0.75”0.68 Asphalt shingle ----0.21 Wood siding0.50.81

9  Remember R =  /k ◦ So 1/R = k/   Remember Q/t = (k x A x  T)  ◦ So Q/t = k/  (A x  T) ◦ And then 1/R (A x  T) ◦ And then Q = 1/R (A x  T x t)  Remember R =  /k ◦ So 1/R = k/   Remember Q/t = (k x A x  T)  ◦ So Q/t = k/  (A x  T) ◦ And then 1/R (A x  T) ◦ And then Q = 1/R (A x  T x t) Q = 1/R (A x  T x t) http://www.kfiam640.com/

10  How much energy (in BTU) is lost through a wall measuring 20’ x 10’ in an hour.  Assume: ◦ Wall covered by 0.5” plywood ◦ It’s 65 o F inside and 15 o F outside  How much energy is lost over the course of 24 hours?  How much energy (in BTU) is lost through a wall measuring 20’ x 10’ in an hour.  Assume: ◦ Wall covered by 0.5” plywood ◦ It’s 65 o F inside and 15 o F outside  How much energy is lost over the course of 24 hours?

11  How much energy (in BTU) is lost from the entire house by conduction in an hour? ◦ Hint 1: Calculate loss through the four walls ◦ Hint 2: Calculate loss through the ceiling ◦ Hint 3: Calculate loss through the floor ◦ Hint 4: Add together  Then calculate loss from the house in a 24 hour day.  How much energy (in BTU) is lost from the entire house by conduction in an hour? ◦ Hint 1: Calculate loss through the four walls ◦ Hint 2: Calculate loss through the ceiling ◦ Hint 3: Calculate loss through the floor ◦ Hint 4: Add together  Then calculate loss from the house in a 24 hour day.

12  What is daily cost to heat house if energy = $30.00 / million BTUs?  What would be the monthly cost?  What is daily cost to heat house if energy = $30.00 / million BTUs?  What would be the monthly cost?

13  Go back to case of wall. How much heat was lost in an hour when wall was 0.5” plywood?  Now suppose that your wall was composed of 3.5” of fiberglass insulation. ◦ Hint 1: Find R value for 3.5” of fiberglass ◦ Hint 2: Recalculate based on that value. ◦ Express the difference here____________  If wall was 0.5” plywood AND 3.5” insulation, add the two R values together. ◦ Then recalculate  Go back to case of wall. How much heat was lost in an hour when wall was 0.5” plywood?  Now suppose that your wall was composed of 3.5” of fiberglass insulation. ◦ Hint 1: Find R value for 3.5” of fiberglass ◦ Hint 2: Recalculate based on that value. ◦ Express the difference here____________  If wall was 0.5” plywood AND 3.5” insulation, add the two R values together. ◦ Then recalculate

14  What would be hourly loss if all four walls were covered by 3.5” insulation?  What would be hourly loss if ceiling was covered by asphalt shingle above plywood?  What would be hourly loss if floor covered by 0.75” hardwood floor?  Next calculate over course of a day  Next calculate over course of a month  What would be hourly loss if all four walls were covered by 3.5” insulation?  What would be hourly loss if ceiling was covered by asphalt shingle above plywood?  What would be hourly loss if floor covered by 0.75” hardwood floor?  Next calculate over course of a day  Next calculate over course of a month

15  Premise ◦ Houses leak warm air, and allow cold air to enter ◦ That air needs to be warmed up. ◦ Formula for calculating this:  Premise ◦ Houses leak warm air, and allow cold air to enter ◦ That air needs to be warmed up. ◦ Formula for calculating this: Q infil = 0.018 x V x K  T x t

16  What would be energy loss in an hour, if all of the air is exchanged over the course of an hour?  How much energy would be lost over the course of 24 hours?  How much energy would be lost if the house leaked air at 1/10 the rate?  What would be energy loss in an hour, if all of the air is exchanged over the course of an hour?  How much energy would be lost over the course of 24 hours?  How much energy would be lost if the house leaked air at 1/10 the rate?

17  Basis for home energy audit!

18  Renewable vs nonrenewable  Traditional vs new energy  Commercialized vs non-commercialized  Centralized vs distributed generation  On-grid vs off-grid  Renewable vs nonrenewable  Traditional vs new energy  Commercialized vs non-commercialized  Centralized vs distributed generation  On-grid vs off-grid

19  Primary energy is the energy as it is available in the natural environment, i.e. the primary source of energy.  Secondary energy is the energy ready for transport or transmission.  Final energy is the energy which the consumer buys or receives.  Useful energy is the energy which is an input in an end-use application.  Primary energy is the energy as it is available in the natural environment, i.e. the primary source of energy.  Secondary energy is the energy ready for transport or transmission.  Final energy is the energy which the consumer buys or receives.  Useful energy is the energy which is an input in an end-use application.

20 energytechnologyexamples Primary coal, wood, hydro, dung, oil Conversion power plant, kiln, refinery, digester Secondary refined oil, electricity, biogas Transport/ transmission trucks, pipes, wires Final diesel oil, charcoal, electricity, biogas Conversion motors, heaters, stoves Useful shaft power, heat

21 CO 2 H2OH2O C 6 H 12 O 6 Carbon reduction Energy Carbon oxidation

22 Energy Stored Energy consumed Energy Respired

23

24 Energy lost at each step (usually 90%)


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