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Kenneth M. Klemow, Ph.D. Wilkes University Prepared for BIO/EES 105 Energy in our World III. Room heating and biological dimensions
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Indoor environments often more comfortable than outdoor. ◦ Stay dry ◦ Regulate light ◦ Regulate temperature People prefer temperatures between 65-75 o F ◦ When T<65, we heat ◦ When T>75, we cool Indoor environments often more comfortable than outdoor. ◦ Stay dry ◦ Regulate light ◦ Regulate temperature People prefer temperatures between 65-75 o F ◦ When T<65, we heat ◦ When T>75, we cool
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When cold we add heat via radiators, fireplaces, space heaters Heat generators warm the air via radiant energy If air carried away, need to warm the new air. ◦ Energy needed = 0.018 BTU / ft 3 / o F When cold we add heat via radiators, fireplaces, space heaters Heat generators warm the air via radiant energy If air carried away, need to warm the new air. ◦ Energy needed = 0.018 BTU / ft 3 / o F
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Imagine you come upon a small, uninhabited, single-roomed cabin in the winter ◦ Height = 10’ ◦ Width = 20’ ◦ Length = 20’ It’s 15 o F outside, you want to heat it to 65 o F. How many BTUs will it take? Imagine you come upon a small, uninhabited, single-roomed cabin in the winter ◦ Height = 10’ ◦ Width = 20’ ◦ Length = 20’ It’s 15 o F outside, you want to heat it to 65 o F. How many BTUs will it take?
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If energy costs $30.00 / million BTUs, how much will initially heating the cabin cost?
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Heat losses due to conduction through the walls. Heat losses due to infiltration of cold air. Heat losses due to conduction through the walls. Heat losses due to infiltration of cold air.
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Building has four walls, a ceiling, and a floor ◦ Heat will be lost through each ◦ Go back to formula Q/t = (k x A x T) k = thermal conductivity of wall / floor / ceiling = thickness For building material, we don’t consider thermal conductivity, per se. Instead we express as thermal resistance (R value), where R = /k. ◦ Units = ft 2 -hr- o F/Btu Building has four walls, a ceiling, and a floor ◦ Heat will be lost through each ◦ Go back to formula Q/t = (k x A x T) k = thermal conductivity of wall / floor / ceiling = thickness For building material, we don’t consider thermal conductivity, per se. Instead we express as thermal resistance (R value), where R = /k. ◦ Units = ft 2 -hr- o F/Btu
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MaterialThicknessR value Plywood0.5”0.62 Fiberglass insulation 3.5”10.9 Hardwood floor 0.75”0.68 Asphalt shingle ----0.21 Wood siding0.50.81
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Remember R = /k ◦ So 1/R = k/ Remember Q/t = (k x A x T) ◦ So Q/t = k/ (A x T) ◦ And then 1/R (A x T) ◦ And then Q = 1/R (A x T x t) Remember R = /k ◦ So 1/R = k/ Remember Q/t = (k x A x T) ◦ So Q/t = k/ (A x T) ◦ And then 1/R (A x T) ◦ And then Q = 1/R (A x T x t) Q = 1/R (A x T x t) http://www.kfiam640.com/
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How much energy (in BTU) is lost through a wall measuring 20’ x 10’ in an hour. Assume: ◦ Wall covered by 0.5” plywood ◦ It’s 65 o F inside and 15 o F outside How much energy is lost over the course of 24 hours? How much energy (in BTU) is lost through a wall measuring 20’ x 10’ in an hour. Assume: ◦ Wall covered by 0.5” plywood ◦ It’s 65 o F inside and 15 o F outside How much energy is lost over the course of 24 hours?
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How much energy (in BTU) is lost from the entire house by conduction in an hour? ◦ Hint 1: Calculate loss through the four walls ◦ Hint 2: Calculate loss through the ceiling ◦ Hint 3: Calculate loss through the floor ◦ Hint 4: Add together Then calculate loss from the house in a 24 hour day. How much energy (in BTU) is lost from the entire house by conduction in an hour? ◦ Hint 1: Calculate loss through the four walls ◦ Hint 2: Calculate loss through the ceiling ◦ Hint 3: Calculate loss through the floor ◦ Hint 4: Add together Then calculate loss from the house in a 24 hour day.
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What is daily cost to heat house if energy = $30.00 / million BTUs? What would be the monthly cost? What is daily cost to heat house if energy = $30.00 / million BTUs? What would be the monthly cost?
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Go back to case of wall. How much heat was lost in an hour when wall was 0.5” plywood? Now suppose that your wall was composed of 3.5” of fiberglass insulation. ◦ Hint 1: Find R value for 3.5” of fiberglass ◦ Hint 2: Recalculate based on that value. ◦ Express the difference here____________ If wall was 0.5” plywood AND 3.5” insulation, add the two R values together. ◦ Then recalculate Go back to case of wall. How much heat was lost in an hour when wall was 0.5” plywood? Now suppose that your wall was composed of 3.5” of fiberglass insulation. ◦ Hint 1: Find R value for 3.5” of fiberglass ◦ Hint 2: Recalculate based on that value. ◦ Express the difference here____________ If wall was 0.5” plywood AND 3.5” insulation, add the two R values together. ◦ Then recalculate
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What would be hourly loss if all four walls were covered by 3.5” insulation? What would be hourly loss if ceiling was covered by asphalt shingle above plywood? What would be hourly loss if floor covered by 0.75” hardwood floor? Next calculate over course of a day Next calculate over course of a month What would be hourly loss if all four walls were covered by 3.5” insulation? What would be hourly loss if ceiling was covered by asphalt shingle above plywood? What would be hourly loss if floor covered by 0.75” hardwood floor? Next calculate over course of a day Next calculate over course of a month
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Premise ◦ Houses leak warm air, and allow cold air to enter ◦ That air needs to be warmed up. ◦ Formula for calculating this: Premise ◦ Houses leak warm air, and allow cold air to enter ◦ That air needs to be warmed up. ◦ Formula for calculating this: Q infil = 0.018 x V x K T x t
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What would be energy loss in an hour, if all of the air is exchanged over the course of an hour? How much energy would be lost over the course of 24 hours? How much energy would be lost if the house leaked air at 1/10 the rate? What would be energy loss in an hour, if all of the air is exchanged over the course of an hour? How much energy would be lost over the course of 24 hours? How much energy would be lost if the house leaked air at 1/10 the rate?
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Basis for home energy audit!
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Renewable vs nonrenewable Traditional vs new energy Commercialized vs non-commercialized Centralized vs distributed generation On-grid vs off-grid Renewable vs nonrenewable Traditional vs new energy Commercialized vs non-commercialized Centralized vs distributed generation On-grid vs off-grid
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Primary energy is the energy as it is available in the natural environment, i.e. the primary source of energy. Secondary energy is the energy ready for transport or transmission. Final energy is the energy which the consumer buys or receives. Useful energy is the energy which is an input in an end-use application. Primary energy is the energy as it is available in the natural environment, i.e. the primary source of energy. Secondary energy is the energy ready for transport or transmission. Final energy is the energy which the consumer buys or receives. Useful energy is the energy which is an input in an end-use application.
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energytechnologyexamples Primary coal, wood, hydro, dung, oil Conversion power plant, kiln, refinery, digester Secondary refined oil, electricity, biogas Transport/ transmission trucks, pipes, wires Final diesel oil, charcoal, electricity, biogas Conversion motors, heaters, stoves Useful shaft power, heat
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CO 2 H2OH2O C 6 H 12 O 6 Carbon reduction Energy Carbon oxidation
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Energy Stored Energy consumed Energy Respired
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Energy lost at each step (usually 90%)
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