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LECTURE ON INTERFERENCE, DIFFRACTION, POLARISATION
BY KAVITA MONGA (LECTURER-PHYSICS) GOVT POLYTECHNIC COLLEGE KHUNIMAJRA, MOHALI DATE- 14/2/2013
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TOPICS TO BE COVERED NATURE OF LIGHT ELECTROMAGNETIC SPECTRUM
INTERFERENCE DIFFRACTION POLARISATION DIFFERENCE BETWEEN INTERFERENCE & DIFFRACTION APPLICATIONS
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Light’s Nature Wave nature (electromagnetic wave)
Particle nature (bundles of energy called photons)
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Past- Separate Theories of Either Wave or Particle Nature
Corpuscular theory of Newton (1670) Light corpuscles have mass and travel at extremely high speeds in straight lines Huygens (1680) Wavelets-each point on a wavefront acts as a source for the next wavefront
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Proofs of Wave Nature Thomas Young's Double Slit Experiment (1807)
bright (constructive) and dark (destructive) fringes seen on screen Thin Film Interference Patterns Diffraction fringes seen within and around a small obstacle or through a narrow opening
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Proof of Particle Nature: The Photoelectric Effect
Albert Einstein 1905 Light energy is quantized Photon is a quantum or packet of energy
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The Photoelectric Effect
Heinrich Hertz first observed the photoelectric effect in 1887 Einstein explained it in 1905 and won the Nobel prize for this.
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Light as waves remember c=fλ
So far, light has been treated as if it travels in straight lines. To describe many optical phenomena, we have to treat light as waves. Just like waves in water, or sound waves, light waves can interact and form interference patterns. remember c=fλ 2
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The Electromagnetic Spectrum
What is the electromagnetic spectrum?
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The Electromagnetic Spectrum
The energy field created by electricity and magnetism can oscillate and it supports waves that move. These waves are called electromagnetic waves.
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The Electromagnetic Spectrum
Electromagnetic waves have both an electric part and a magnetic part and the two parts exchange energy back and forth. A 3-D view of an electromagnetic wave shows the electric and magnetic portions. The wavelength and amplitude of the waves are labeled λ and A, respectively.
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The Electromagnetic Spectrum
The higher the frequency of the light, the higher the energy of the wave. Since color is related to energy, there is also a direct relation between color, frequency, and wavelength.
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Speed of Light c = f l Wavelength (m) Speed of light 3 x 108 m/sec
Frequency (Hz)
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Calculate wavelength Calculate the wavelength in air of blue-green light that has a frequency of 600 × 1012 Hz. 1) You are asked for the wavelength. 2) You are given the frequency. 3) The speed of light is c = fλ. 4) λ = c ÷ f = (3 x 108 m/sec) ÷ (600 x 1012 Hz) = 5 x 10-7 m
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Waves of the electromagnetic spectrum
Visible light is a small part of the energy range of electromagnetic waves. The whole range is called the electromagnetic spectrum and visible light is in the middle of it.
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Waves of the electromagnetic spectrum
Radio waves are on the low-frequency end of the spectrum. Microwaves range in length from apprxi. 30 cm (about 12 inches) to about 1 mm. The infrared (or IR) region of the electromagnetic spectrum lies between microwaves and visible light.
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Waves of the electromagnetic spectrum
Ultraviolet radiation has a range of wavelengths from 400 down to about 10 nm. X-rays are high-frequency waves that have great penetrating power and are used extensively in medical and manufacturing applications. Gamma rays are generated in nuclear reactions.
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Interference, Diffraction, and Polarization
What are some ways light behaves like a wave?
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Interference, Diffraction, and Polarization
In 1807, Thomas Young ( ) did the most convincing experiment demonstrating that light is a wave. A beam of light fell on a pair of parallel, very thin slits in a piece of metal. After passing through the slits, the light fell on a screen. A pattern of alternating bright and dark bands formed is called an interference pattern.
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INTRODUCTION TO INTERFERENCE
When two or more sets of waves pass through the same medium, they will cross each other. These waves are not aware of the presence of each other. So the effects produced by one wave are independent of the effects due to the other. The behaviour of these two sets of waves is governed by a universal principle known as “ The Principle of Superposition” which states that the net displacement at a point where two different waves are incident in the vector sum of component displacement. Any wave motion in which the amplitudes of two waves combine will show Interference.
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INTRODUCTION TO INTERFERENCE
During interference, energy and displacement are redistributed. At some points, displacement and energy become maximum and at other points displacement and energy become minimum. This modification in the distribution of light energy got by the superposition of two or more waves is called interference. TYPES OF INTERFERENCE Constructive Interference Destructive Interference
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Water Waves A wave generator sends periodic water waves into a barrier with a small gap, as shown below. A new set of waves is observed emerging from the gap to the wall.
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Interference of Water Waves
An interference pattern is set up by water waves leaving two slits at the same instant.
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Interference in spherical waves
maximum of wave minimum of wave r1=r2 r1 r2 positive constructive interference negative constructive interference destructive interference if r2-r1=nλ then constructive interference occurs if r2-r1=(n+½)λ the destructive interference occurs
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light as waves it works the same as water and sound!
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Conditions for Interference
If two waves have a definite phase relationship then they are coherent. Otherwise, they are incoherent (ex: two light bulbs). For Interference: The sources must be coherent. The sources should be monochromatic.
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Interference Coherence and Monochromatic
No coherence between two light bulbs coherence - two or more waves that maintain a constant phase relation. Coherence time Coherence length Some later time or distance monochromatic - a wave that is composed of a single frequency. Heisenberg uncertainty relation.
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For Constructive Interference:
The waves must arrive to the point of study in phase. So their path difference must be integral multiples of the wavelength: DL= nl n=0,1,2,3,………
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interference destructive interference constructive interference
at any point in time one can construct the total amplitude by adding the individual components
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For destructive interference:
, the waves must arrive to the point of study out of phase. So the path difference must be an odd multiple of l/2: DL= n l m=1/2,3/2,5/2,….
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+ + = = λ λ λ λ demo: interference destructive interference
constructive interference waves ½λ out of phase waves in phase
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Two Waves Interfering
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Thomas Young’s Double Slit Interference Experiment
Showed an interference pattern Measured the wavelength of the light
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double slit experiment
•the light from the two sources is incoherent (fixed phase with respect to each other •in this case, there is no phase shift between the two sources •the two sources of light must have identical wave lengths
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Young’s Experiment In Young’s experiment, light from a monochromatic source falls on two slits, setting up an interference pattern analogous to that with water waves. Light source S1 S2
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The Superposition Principle
The resultant displacement of two simultaneous waves (blue and green) is the algebraic sum of the two displacements. The composite wave is shown in yellow. Constructive Interference Destructive Interference The superposition of two coherent light waves results in light and dark fringes on a screen.
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Young’s Interference Pattern
Constructive Bright fringe Destructive Dark fringe Constructive Bright fringe
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Conditions for Bright Fringes
Bright fringes occur when the difference in path Dp is an integral multiple of one wave length l. l l l p1 p2 p3 p4 Path difference Dp = 0, l , 2l, 3l, … Bright fringes: Dp = nl, n = 0, 1, 2, . . .
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Conditions for Dark Fringes
Dark fringes occur when the difference in path Dp is an odd multiple of one-half of a wave length l/2. l l p1 n = odd n = 1,3,5 … p2 p3 p3 Dark fringes:
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Analytical Methods for Fringes
x y d sin q s1 s2 d q p1 p2 Dp = p1 – p2 Dp = d sin q Path difference determines light and dark pattern. Bright fringes: d sin q = nl, n = 0, 1, 2, 3, . . . Dark fringes: d sin q = nl/2 , n = 1, 3, 5, . . .
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Analytical Methods (Cont.)
x y d sin q s1 s2 d q p1 p2 From geometry, we recall that: So that . . . Bright fringes: Dark fringes:
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The third dark fringe occurs when n = 5
Example 1: Two slits are 0.08 mm apart, and the screen is 2 m away. How far is the third dark fringe located from the central maximum if light of wavelength 600 nm is used? x y d sin q s1 s2 q n = 1, 3, 5 x = 2 m; d = 0.08 mm l = 600 nm; y = ? d sin q = 5(l/2) The third dark fringe occurs when n = 5 Dark fringes:
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Example 1 (Cont. ): Two slits are 0
Example 1 (Cont.): Two slits are 0.08 mm apart, and the screen is 2 m away. How far is the third dark fringe located from the central maximum if l = 600 nm? x = 2 m; d = 0.08 mm l = 600 nm; y = ? x y d sin q s1 s2 q n = 1, 3, 5 y = 3.75 cm
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Note The interference is different for light of different wavelengths
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θ=sin-1(mλ/d) =sin-1(3x600x10-9/0.01) =0.01030 b) Ym = m λL/d
Question Two narrow slits are illuminated by a laser with a wavelength of 600 nm. the distance between the two slits is 1 cm. a) At what angle from the beam axis does the 3rd order maximum occur? b) If a screen is put 5 meter away from the slits, what is the distance between the 0th order and 3rd order maximum? a) use dsinθ=mλ with m=3 θ=sin-1(mλ/d) =sin-1(3x600x10-9/0.01) = b) Ym = m λL/d m=0: y0=0 m=3: y3=3x600x10-9x5/0.01 =9x10-4 m =0.9 mm
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b) travel paths that differ by an odd number of half wavelengths
quiz (extra credit) Two beams of coherent light travel different paths arriving at point P. If constructive interference occurs at point P, the two beams must: a) travel paths that differ by a whole number of wavelengths b) travel paths that differ by an odd number of half wavelengths
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Diffraction Wave bends as it passes an obstacle.
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Diffraction of Light Diffraction is the ability of light waves to bend around obstacles placed in their path. Ocean Beach Fuzzy Shadow Light rays Water waves easily bend around obstacles, but light waves also bend, as evidenced by the lack of a sharp shadow on the wall.
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Diffraction Grating What is a diffraction grating?
What are the two types? A diffraction grating is a slide with a large number of slits. Usually expressed in the number of slits per mm. transmission and reflection gratings
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The Diffraction Grating
A diffraction grating consists of thousands of parallel slits etched on glass so that brighter and sharper patterns can be observed than with Young’s experiment. Equation is similar. d sin q q d d sin q = nl n = 1, 2, 3, …
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Diffraction gratings A diffraction grating is a precise array of tiny engraved lines, each of which allows light through. The spectrum produced is a mixture of many different wavelengths of light.
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How a Diffraction Grating Works
When you look at a diffracted light you see: the light straight ahead as if the grating were transparent. a "central bright spot". the interference of all other light waves from many different grooves produces a scattered pattern called a spectrum.
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Diffraction Grating
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Diffraction Grating Large number of equally spaced parallel slits.
Equations are same as for double slit interference but first calculate the d (slit separation) from the grating density, N. d=1/N , N slits per unit length dsinq=nl nl = dx L Constructive (brights) n=0,1,2,3,….. Destructive (darks) n=1/2, 3/2, 5/2,…..
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Spectrometer A spectrometer is a device that measures the wavelength of light. A diffraction grating can be used to make a spectrometer because the wavelength of the light at the first-order bright spot can be expressed in a mathematical relationship.
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The Grating Equation 6l 4l 2l 3l 2l The grating equation: l 1st order
d = slit width (spacing) l = wavelength of light q = angular deviation n = order of fringe 2nd order 2l 4l 6l
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A compact disk acts as a diffraction grating
A compact disk acts as a diffraction grating. The colors and intensity of the reflected light depend on the orientation of the disc relative to the eye.
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Diffraction through a Narrow Slit
Each part of the slit acts as a point source that interferes with the others. (Based on Huygens Principle)
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Pattern of Diffraction of Light through a Narrow Slit
x w L
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Diffraction from Narrow Slit
w sinq=n l l= n w y L w: is the width of the slit Destructive (dark fringes): n=0,1,2,3,….
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Diffraction for a Circular Opening
Circular diffraction D The diffraction of light passing through a circular opening produces circular interference fringes that often blur images. For optical instruments, the problem increases with larger diameters D.
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Example of Diffraction
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DIFFERENCE BETWEEN INTERFERENCE AND DIFFRACTION
In the interference phenomenon, the superposition is due to two separate wavefronts originating from two coherent sources while in the diffraction phenomenon the superposition is due to secondary wavelets originating from different parts of the same wavefront. In the interference, the regions of minimum intensity are perfectly dark while in the diffraction, they are not perfectly dark.
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DIFFERENCE BETWEEN INTERFERENCE AND DIFFRACTION
The width of the fringes in the interference phenomenon is normally equal and uniform while in diffraction, the width between the fringes is never equal. In the interference phenomenon, all the positions of maxima are of the same intensity, but in the diffraction phenomenon they are of varying intensity.
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Polarization Polarization is another wave property of light.
The fact that light shows polarization tells us that light is a transverse wave. Most of the light that you see is unpolarized. That does not mean the light has no polarization. Unpolarized light is actually an equal mixture of all polarizations. We call ordinary light unpolarized because no single polarization dominates the mixture.
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An easy way to think about polarization is to think about shaking a spring back and forth.
If the spring is shaken up and down it makes vertical polarization. If the spring is shaken back and forth it makes horizontal polarization. Waves move along the spring in its long direction. The oscillation of the wave (and its polarization) is transverse or perpendicular to the direction the wave travels.
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Polarization Polarization is a vector.
A wave with polarization at 45 degrees can be represented as the sum of two waves. Each of the component waves has smaller amplitude. Most of the light that you see is unpolarized. That does not mean the light has no polarization. Unpolarized light is actually an equal mixture of all polarizations. We call ordinary light unpolarized because no single polarization dominates the mixture.
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Polarization We saw that light is really an electromagnetic wave with electric and magnetic field vectors oscillating perpendicular to each other. In general, light is unpolarized, which means that the E-field vector (and thus the B-field vector as long as it is perpendicular to the E- field) could point in any direction E-vectors could point anywhere: unpolarized propagation into screen
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polarized light ¾ light can be linearly polarized, which means that the E- field only oscillated in one direction (and the B-field perpendicular to that) ¾ The intensity of light is proportional to the square of amplitude of the E-field. I~Emax2
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How to polarize? ¾ absorption ¾ reflection ¾ scattering
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polarization by absorption
certain material (such as polaroid used for sunglasses) only transmit light along a certain ‘transmission’ axis. because only a fraction of the light is transmitted after passing through a polarizer the intensity is reduced. ¾ If unpolarized light passes through a polarizer, the intensity is reduced by a factor of 2
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polarization by reflection
¾ If unpolarized light is reflected, n1 than the reflected light is partially polarized. ¾ if the angle between the reflected ray and the refracted ray is exactly 900 the reflected n2 light is completely polarized ¾ the above condition is met if for the angle of incidence the equation tanθ=n2/n1 ¾ the angle θ=tan-1(n2/n1) is called the Brewster angle ¾ the polarization of the reflected light is (mostly) parallel to the surface of reflection
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Polarization by scattering
¾ certain molecules tend to polarize light when struck by it since the electrons in the molecules act as little antennas that can only oscillate in a certain direction
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Polarization A polarizer is a material that selectively absorbs light depending on polarization. A polarizer re-emits a fraction of incident light polarized at an angle to the transmission axis. Most of the light that you see is unpolarized. That does not mean the light has no polarization. Unpolarized light is actually an equal mixture of all polarizations. We call ordinary light unpolarized because no single polarization dominates the mixture.
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Applications of Polarizers
Polarizing sunglasses are used to reduce the glare of reflected light The LCD (liquid crystal diode) screen on a laptop computer uses polarized light to make pictures.
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question vertical horizontal direction of polarization of reflected light Because of reflection from sunlight of the glass window, the curtain behind the glass is hard to see. If I would wear polaroid sunglasses that allow … polarized light through, I would be able to see the curtain much better. ¾ a) horizontally ¾ b) vertically
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sunglasses wearing sunglasses will help reducing glare (reflection) from flat surfaces (highway/water) without with sunglasses
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Interference From Single Slit
When monochromatic light strikes a single slit, diffraction from the edges produces an interference pattern as illustrated. Pattern Exaggerated Relative intensity The interference results from the fact that not all paths of light travel the same distance some arrive out of phase.
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Single Slit Interference Pattern
Each point inside slit acts as a source. a/2 a 1 2 4 3 5 For rays 1 and 3 and for 2 and 4: First dark fringe: For every ray there is another ray that differs by this path and therefore interferes destructively.
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Single Slit Interference Pattern
1 2 4 3 5 First dark fringe: Other dark fringes occur for integral multiples of this fraction l/a.
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Example - Monochromatic light shines on a single slit of width 0.45 mm. On a screen 1.5 m away, the first dark fringe is displaced 2 mm from the central maximum. What is the wavelength of the light? q x = 1.5 m y a = 0.35 mm l = ? l = 600 nm
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Resolution of Images Consider light through a pinhole. As two objects get closer the interference fringes overlap, making it difficult to distinguish separate images. d1 Clear image of each object d2 Separate images barely seen
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Resolution Limit Images are just resolved when central maximum of one pattern coincides with first dark fringe of the other pattern. d2 Resolution limit Resolution Limit Separate images
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Resolving Power of Instruments
The resolving power of an instrument is a measure of its ability to produce well-defined separate images. Limiting angle D q For small angles, sin q q, and the limiting angle of resolution for a circular opening is: Limiting angle of resolution:
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Resolution and Distance
q so p D Limiting angle qo Limiting Angle of Resolution:
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Example - The tail lights (l = 632 nm) of an auto are 1
Example - The tail lights (l = 632 nm) of an auto are 1.2 m apart and the pupil of the eye is around 2 mm in diameter. How far away can the tail lights be resolved as separate images? q so p Eye D Tail lights p = km
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Summary d sin q q Young’s Experiment:
Monochromatic light falls on two slits, producing interference fringes on a screen. x y d sin q s1 s2 d q p1 p2 Bright fringes: Dark fringes:
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Summary (Cont.) The grating equation: d = slit width (spacing)
l = wavelength of light q = angular deviation n = order of fringe
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Summary (Cont.) Interference from a single slit of width a:
Pattern Exaggerated Relative Intensity
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Summary (cont.) q The resolving power of instruments. p D so
Limiting angle qo Limiting Angle of Resolution:
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diffraction In Young’s experiment, two slits were used to produce an interference pattern. However, interference effects can already occur with a single slit. This is due to diffraction: the capability of light to be “deflected” by edges/small openings. In fact, every point in the slit opening acts as the source of a new wave front
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interference pattern from a single slit
pick two points, 1 and 2, one in the top top half of the slit, one in the bottom half of the slit. Light from these two points interferes destructively if: Δx=(a/2)sinθ=λ/2 so sinθ=λ/a we could also have divided up the slit into 4 pieces: Δx=(a/4)sinθ=λ/2 so sinθ=2λ/a 6 pieces: Δx=(a/6)sinθ=λ/2 so sinθ=3λ/a Minima occur if sinθ=mλ/a m=1,2,3… In between the minima, are maxima: sinθ=(m+1/2)λ/a m=1,2,3… AND sinθ=0 or θ=0
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slit width if λ>a sinθ=λ/a > 1 if λ<<a
λ<a : interference Not possible, so no sinθ=mλ/a is very small pattern is seen patterns diffraction hardly seen
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the diffraction pattern
The intensity is not uniform: I=I0sin2(β)/β2 β=πa(sinθ)/ λ a a a a a a
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question light with a wavelength of 500 nm is used to illuminate a slit of 5μm. At which angle is the 5th minimum in the diffraction pattern seen? sinθ=mλ/a θ=sin-1(5x500x10-9/(5x10-6))=300
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diffraction from a single hair
instead of an slit, we can also use an inverse image, for example a hair! demo
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double slit interference revisited
The total response from a double slit system is a combination of two single-source slits, combined with a diffraction pattern from each of the slit due to diffraction minima asinθ=mλ, m=1,2,3… maxima asinθ=(m+1/2)λ, m=1,2,3… and θ=0 a: width of individual slit due to 2-slit interference maxima dsinθ=mλ, m=0,1,2,3… minima dsinθ=(m+1/2)λ, m=0,1,2,3… d: distance between two slits
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double-slit experiment
a d if λ>d, each slit acts as a single if λ<d the interference spectrum source of light and we get is folded with the diffraction a more or less prefect double-slit pattern. interference spectrum
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question 7th A person has a double slit plate. He measures the distance between the two slits to be d=1 mm. Next he wants to determine the width of each slit by investigating the interference pattern. He finds that the 7th order interference maximum lines up with the first diffraction minimum and thus vanishes. What is the width of the slits? 7th order interference maximum: dsinθ=7λ so sinθ=7λ/d 1st diffraction minimum: asinθ=1λ so sinθ=λ/a sinθ must be equal for both, so λ/a=7λ/d and a=d/7=1/7 mm
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diffraction grating consider a grating with
many slits, each separated by d a distance d. Assume that for each slit λ>d. We saw that for 2 slits maxima appear if: dsinθ=mλ, m=0,1,2,3… This condition is not changed for in the case of n slits. diffraction gratings can be made by scratching lines on glas and are often used to analyze light instead of giving d, one usually gives the number of slits per unit distance: e.g. 300 lines/mm d=1/(300 lines/mm)= mm
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separating colors cd’s can act as a diffraction grating
dsinθ=mλ, m=0,1,2,3… for maxima (same as for double slit) so θ=sin-1(mλ/d) depends on λ, the wavelength. cd’s can act as a diffraction grating
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question ¾ If the interference conditions are the same when using a double slit or a diffraction grating with thousands of slits, what is the advantage of using the grating to analyze light? ¾ a) the more slits, the larger the separation between maxima. ¾ b) the more slits, the narrower each of the bright spots and thus easier to see ¾ c) the more slits, the more light reaches each maximum and the maxima are brighter ¾ d) there is no advantage
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question An diffraction grating has 5000 lines per cm. The angle between the central maximum and the fourth order maximum is What is the wavelength of the light? dsinθ=mλ, m=0,1,2,3… d=1/5000=2x10-4 cm=2x10-6 m m=4, sin(47.2)=0.734 so λ= dsinθ/m=2x10-6x0.734/4=3.67x10-7 m=367 nm
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Reading Question What was the first experiment to show that light is a wave? 1. Young’s double slit experiment 2. Galileo’s observation of Jupiter’s moons 3. The Michelson-Morley interferometer 4. The Pound-Rebka experiment 5. Millikan’s oil drop experiment
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Reading Question What was the first experiment to show that light is a wave? 1. Young’s double slit experiment 2. Galileo’s observation of Jupiter’s moons 3. The Michelson-Morley interferometer 4. The Pound-Rebka experiment 5. Millikan’s oil drop experiment
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Reading Question What is a diffraction grating?
1. A device used to grate cheese and other materials 2. A musical instrument used to direct sound 3. A plaque with a tiny circular aperture 4. An opaque objects with many closely spaced slits 5. Diffraction gratings are not covered in Chapter 22.
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Reading Question What is a diffraction grating?
1. A device used to grate cheese and other materials 2. A musical instrument used to direct sound 3. A plaque with a tiny circular aperture 4. An opaque objects with many closely spaced slits
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Reading Question When laser light shines on a screen after passing through two closely spaced slits, you see 1. a diffraction pattern. 2. interference fringes. 3. two dim, closely spaced points of light. 4. constructive interference.
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Reading Question When laser light shines on a screen after passing through two closely spaced slits, you see 1. a diffraction pattern. 2. interference fringes. 3. two dim, closely spaced points of light. 4. constructive interference.
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