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Chapter 15 Energy
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Energy: The ability to do work.
Energy and Work Energy: The ability to do work.
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Work = Force x distance W = F x d The transfer of energy as
the result of motion. (Unit of Work is the Joule) Work = Force x distance W = F x d
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Joule (J) Unit of Energy and Work. W = F • d Joule = Newton • meter
J = (kg • m/s²) • m
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Energy that appears in the
Kinetic Energy (KE) Energy that appears in the form of motion.
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Kinetic Energy (KE) m KE = ½ mv2
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A 70. 0-kilogram daemon is walking at a speed of 2. 0 m/s
A 70.0-kilogram daemon is walking at a speed of 2.0 m/s. What is his kinetic energy?
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KE = 140J Given: m = 70.0kg v = 2 m/s Find: KE = ?
Equation: KE = ½ mv2 Solve: KE = ½ (70.0kg)(2 m/s)2 KE = 140J
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Energy that an object has as the result of its position or condition.
Potential Energy (PE) Energy that an object has as the result of its position or condition.
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Gravitational Potential Energy (GPE)
An object's gravitational potential energy depends on its mass, its height, and the acceleration due to gravity.
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g = acceleration due to gravity(9.8m/s2)
h PE = mgh m = mass h = height g = acceleration due to gravity(9.8m/s2)
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Suppose the diver at the top of a 10
Suppose the diver at the top of a 10.0-meter-high diving platform has a mass of 50.0 kilograms.
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GPE = 4900J Given: m = 50.0 kg h = 10 m g = 9.8 m/s2 Find: GPE = ?
Equation: GPE = mgh Solve: GPE = (50.0kg)(9.8 m/s2)(10m) GPE = 4900J
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Elastic Potential Energy
The potential energy of an object that is stretched or compressed.
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Forms of Energy The major forms of energy are mechanical energy, thermal energy, chemical energy, electrical energy, electromagnetic energy, and nuclear energy.
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Kinetic Energy and Potential Energy ME = KE + PE
Mechanical Energy Kinetic Energy and Potential Energy ME = KE + PE
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Thermal Energy The total potential and kinetic energy of all the microscopic particles in an object
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Chemical Energy The energy stored in chemical bonds.
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Energy associated with electric charges.
Electrical Energy Energy associated with electric charges.
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Electromagnetic Energy
Form of energy that travels through space in the form of waves.
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The energy stored in atomic nuclei.
Nuclear Energy The energy stored in atomic nuclei.
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Nuclear Fission
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Nuclear Fusion
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Nuclear Fusion
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Math Practice Page 448, Probs:1-3
Homework Math Practice Page 448, Probs:1-3 Section 15.1 Worksheet Due: 4/29/10
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Example #1: Mr. Clune weighs 100N. He walks up some stairs 5m high
Example #1: Mr. Clune weighs 100N. He walks up some stairs 5m high. How much work does he do??? Given: F = 100N d = 5m Find: W = ? Equation: W = F x d Solve: W = ( 100N ) x ( 5m ) W = 500J
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Example #2: Amy picks up her physical science book, that has a mass of 2.0kg, to a height of 1.5m. How much work did Amy do???? Given: m = 2.0kg d = 1.5m a = 9.8 m/s² Find: F = ?? W = ?? Equations: W = F x d F = m x a W = ( m x a ) x d Solve: W = {( 2.0kg) x (9.8 m/s²)} x (1.5m) W = 29.4J
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Law of Conservation of Energy
Can change from one form to another. Can never be created or destroyed. Total energy of the universe remains the same.
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Potential Energy + Kinetic Energy
Mechanical Energy = Potential Energy + Kinetic Energy E = PE + KE KE = 0 PE = max KE = 0 PE = max KE = max PE = 0
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Pole Vault Kinetic Energy
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Elastic Potential Energy
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Kinetic Energy
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Gravitational Potential Energy
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E - Energy m - mass c – speed of light
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PE Work KE + PE KE + PE
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One Calorie = 4180 joules One hour of running 1000 calories
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Homework 15-2 Section 15-2 Worksheet Due: 4/7/09
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Nonrenewable Energy A source of energy that exists in limited quantities and, once used, cannot be replaced except over the course of millions of years.
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Nonrenewable Energy Nonrenewable energy resources include oil, natural gas, coal, and uranium
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Renewable Energy A source of energy that can be replaced in a relatively short period of time.
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Renewable Energy Renewable energy resources include hydroelectric, solar, geothermal, wind, biomass, and, possibly in the future, nuclear fusion.
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Hydroelectric
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Solar
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Geothermal
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Wind
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Biomass
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Homework 15-3 Section 15-3 Worksheet D: Due: 4/8/09
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Homework 15-3 Section 15-3 Worksheet D: Due: 4/8/09 F: Due: 4/7/07
D Test: 4/9/08 F Test: 4/11/08
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Homework 15 -3 Section 15-3 Word-wise/Math Worksheets Due: 5/5/10 D Test: 5/6/10 E Test: 5/7/10
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Temperature and Heat Temperature: The measure of the average kinetic energy of the particles in a sample of matter.
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The total energy of the particles
Thermal Energy The total energy of the particles in a material. 25ºC 25ºC
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The flow of Thermal Energy.
Heat The flow of Thermal Energy.
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Heat is the flow of Thermal Energy from an area of
High Temperature to one of Low Temperature.
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Thermal Pollution Waste you can’t see!!!
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Thermal Pollution: Occurs when waste heat significantly changes the temperature of the environment.
Adding warm water to lakes, rivers and oceans can change the environment. How?
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Homework 5-2 Section Wrap-up Page: 137 Page: 140 Due: 11/7/05
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Projects Due Tomorrow 11/04/05
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Homework 5-3 Section Wrap-up Page: 140 Due: 10/17/02
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Measuring Thermal Energy
Type of Material Mass of Material · Temperature
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Material Water Metal
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Specific Heat [C, J / (kg • K)]
The amount of energy it takes to it takes to raise the temperature of 1 kg of material 1 Kelvin. ( K = C ) It takes 4184 joules of energy to raise the temperature of 1 kg of water, 1C.
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Material Specific Heat Water 4184 J / (kg • K) Alcohol
Material Specific Heat Water J / (kg • K) Alcohol J / (kg • K) Aluminum 920 J / (kg • K) Graphite(Carbon) 710 J / (kg • K) Sand 664 J / (kg • K) Iron 450 J / (kg • K) Copper 380 J / (kg • K) Silver 235 J / (kg • K)
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Calculating Thermal Changes
Change in Thermal Energy - Q Mass - m Change in Temperature - T Specific Heat - C Q = m • T • C T = Tfinal - Tinitial
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Example: Mr. Clune wants to bring 1 kg of water to boiling for his afternoon tea. The temperature of the water out of the tap is 10C. How much Thermal Energy does he have to add to the water?
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Q = 377,000 J or 377 kJ Given: m = 1 kg Find: Q = ? Tinitial = 10C
Tfinal = 100C C = 4184 (J / (kg • C ) ) Equation: Q = m • T • C Q = m • (Tfinal - Tinitial) • C Solve: Q = (1 kg) • (100C -10C) • 4184(J/(kg • C) Q = (1 kg) • (90C) • 4184 (J/(kg • C) Q = 377,000 J or 377 kJ
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Example: Do the same problem as the one above but use sand instead.
Given: m = 1 kg Find: Q = ? Tinitial = 10C Tfinal = 100C C = 664 (J / (kg • C ) ) Equation: Q = m • T • C Q = m • (Tfinal - Tinitial) • C Solve: Q = (1 kg) · (100C -10C) · 664(J/(kg.C) Q = 60,000 J or 60 kJ
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Homework 5-4 Practice Problem: 1-2 Page:143 Section Wrap-up Page: 144 Due: 11/09/05 Test on 11/15/05
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Homework 5-5 Vocabulary: 1-10 Page:147 Review Questions:1-25 Page: Due: 11/22/04 Test: 11/23/04
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