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Published byHollie Short Modified over 9 years ago
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38° z SohCah Toa 10’ y
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β SohCah Toa 15cm x 24cm
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37˚ SohCah Toa x 15.5cm y
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13.5° x SohCah Toa 22.3” y
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15.5 m SohCah Toa 31 m x
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28 Given regular square pyramid with slant height of 50ft. The perimeter of the Base is 112ft Find the altitude. 14 x 50 Family! (7 – 24 – 25) x = 48ft
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12 9 20 Find the diagonal of a regular rectangular prism with dimensions of 9, 12, and 20 Find the altitude. 20 2 + 15 2 = x 2 Family! (3 – 4 – 5) x = 25
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√2 = 42√2 2 21√2 42 21√2 45 I have the hyp, so to get the legs, divide by √2 42 √2 = 21√2 45 Answers in simplified radical form Use special right ∆ rules to solve the triangle. Answers in simplified radical form
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12√3 60 18 6√3 30 I have the long leg, so get short leg first by dividing by √3 Then, from the short leg to get the hyp, multiply by 2 √3 = 18√3 3 18 √3 = 6√3 Answers in simplified radical form Use special right ∆ rules to solve the triangle. Answers in simplified radical form
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