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Gene Expression Chapter 13
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Learning Objective 1 What early evidence indicated that most genes specify the structure of proteins?
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Garrod’s Work Inborn errors of metabolism Alkaptonuria Gene mutation
evidence that genes specify proteins Alkaptonuria rare genetic disease lacks enzyme to oxidize homogentisic acid Gene mutation associated with absence of specific enzyme
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Alkaptonuria
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Learning Objective 2 Describe Beadle and Tatum’s experiments with Neurospora
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Beadle and Tatum Exposed Neurospora spores Each mutant strain
to X-rays or ultraviolet radiation induced mutations prevented metabolic production of essential molecules Each mutant strain had mutation in only one gene each gene affected only one enzyme
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Beadle-Tatum Experiments
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Learning Objective 3 How does genetic information in cells flow from DNA to RNA to polypeptide?
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DNA to Protein Information encoded in DNA 2-step process:
codes sequences of amino acids in proteins 2-step process: 1. Transcription 2. Translation
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Transcription Synthesizes messenger RNA (mRNA)
complementary to template DNA strand specifies amino acid sequences of polypeptide chains
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Translation Synthesizes polypeptide chain Codon specified by mRNA
also requires tRNA and ribosomes Codon sequence of 3 mRNA nucleotide bases specifies one amino acid or a start or stop signal
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DNA to Protein
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Learning Objective 4 What is the difference between the structures of DNA and RNA?
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RNA RNA nucleotides RNA subunits ribose (sugar)
bases (uracil, adenine, guanine, or cytosine) 3 phosphates RNA subunits covalently joined by 5′ – 3′ linkages form alternating sugar-phosphate backbone
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RNA Structure
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Learning Objective 5 Why is genetic code said to be redundant and virtually universal? How may these features reflect its evolutionary history?
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Genetic Code mRNA codons 64 codons specify a sequence of amino acids
61 code for amino acids 3 codons are stop signals
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Codons
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Genetic Code Is redundant Is virtually universal
some amino acids have more than one codon Is virtually universal suggesting all organisms have a common ancestor few minor exceptions to standard code found in all organisms
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Learning Objective 6 What are the similarities and differences between the processes of transcription and DNA replication?
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Enzymes Similar enzymes Carry out synthesis in 5′ → 3′ direction
RNA polymerases (RNA synthesis) DNA polymerases (DNA replication) Carry out synthesis in 5′ → 3′ direction Use nucleotides with 3 phosphate groups
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Antiparallel Synthesis
Strands of DNA are antiparallel Template DNA strand and complementary RNA strand are antiparallel DNA template read in 3′ → 5′ direction RNA synthesized in 5′ → 3′ direction
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Antiparallel Synthesis
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Base-Pairing Rules In RNA synthesis and DNA replication are the same
except uracil is substituted for thymine
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Transcription
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Learning Objective 7 What features of tRNA are important in decoding genetic information and converting it into “protein language”?
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Transfer RNA (tRNA) “Decoding” molecule in translation Anticodon
complementary to mRNA codon specific for 1 amino acid
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tRNA
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Transfer RNA (tRNA) tRNA attaches to specific amino acid
covalently bound by aminoacyl-tRNA synthetase enzymes
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Aminoacyl-tRNA
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Learning Objective 8 How do ribosomes function in polypeptide synthesis?
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Ribosomes Bring together all machinery for translation
Couple tRNAs to mRNA codons Catalyze peptide bonds between amino acids Translocate mRNA to read next codon
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Ribosomal Subunits Each ribosome is made of Each subunit contains
1 large ribosomal subunit 1 small ribosomal subunit Each subunit contains ribosomal RNA (rRNA) many proteins
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Ribosome Structure
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Animation: Structure of a Ribosome
CLICK TO PLAY
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Learning Objective 9 Describe the processes of initiation, elongation, and termination in polypeptide synthesis
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Initiation 1st stage of translation Initiation factors Initiator tRNA
bind to small ribosomal subunit which binds to mRNA at start codon (AUG) Initiator tRNA binds to start codon then binds large ribosomal subunit
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Elongation A cyclic process Proceeds in 5′ → 3′ direction along mRNA
adds amino acids to polypeptide chain Proceeds in 5′ → 3′ direction along mRNA Polypeptide chain grows from amino end to carboxyl end
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Termination Final stage of translation A site binds to release factor
when ribosome reaches stop codon A site binds to release factor triggers release of polypeptide chain dissociation of translation complex
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Stages of Transcription
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Learning Objective 10 What is the functional significance of the structural differences between bacterial and eukaryotic mRNAs?
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Eukaryotes Genes and mRNA molecules
are more complicated than those of bacteria
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Eukaryotic mRNA After transcription
5′ cap (modified guanosine triphosphate) is added to 5′ end of mRNA molecule Poly-A tail (adenine-containing nucleotides) may be added at 3′ end of mRNA molecule
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Posttranscriptional Modification
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Introns and Exons Introns Exons noncoding regions (interrupt exons)
removed from original pre-mRNA Exons coding regions in eukaryotic genes spliced to produce continuous polypeptide coding sequence
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Learning Objective 11 What is the difference between translation in bacterial and eukaryotic cells?
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Bacterial Cells Transcription and translation are coupled
Bacterial ribosomes bind to 5′ end of growing mRNA initiate translation before message is fully synthesized
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Bacterial mRNA
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Initiation
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Elongation
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Termination
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Polyribosome Many ribosomes bound to a single mRNA
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Learning Objective 12 Describe retroviruses and the enzyme reverse transcriptase
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Retroviruses Synthesize DNA from an RNA template
HIV-1 (virus that causes AIDS) Enzyme reverse transcriptase reverses flow of genetic information
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Reverse Transcription
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Learning Objective 13 Give examples of the different classes of mutations that affect the base sequence of DNA What effects does each have on the polypeptide produced?
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Base Substitution May alter or destroy protein function
missense mutation codon change specifies a different amino acid nonsense mutation codon becomes a stop codon May have minimal effects if amino acid is not altered if codon change specifies a similar amino acid
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BASE-SUBSTITUTION MUTATIONS
Normal DNA sequence Normal mRNA sequence Normal protein sequence (Stop) BASE-SUBSTITUTION MUTATIONS Missense mutation (Stop) Figure 13.20: Mutations. (a) Missense and nonsense mutations are types of base-substitution mutations. A missense mutation results in a polypeptide of normal length, but with an amino acid substitution. A nonsense mutation results in the production of a truncated (shortened) polypeptide, which is usually not functional. Nonsense mutation (Stop) Fig a, p. 299
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Animation: Base-Pair Substitution
CLICK TO PLAY
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Frameshift Mutations Insertion or deletion of one or two base pairs in a gene destroys protein function changes codon sequences downstream from the mutation
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Normal protein sequence
Normal DNA sequence Normal mRNA sequence Normal protein sequence (Stop) FRAMESHIFT MUTATIONS Deletion causing nonsense Figure 13.20: Mutations. (b) A frameshift mutation results from the deletion (shown) or insertion of one or two bases, causing the base sequence following the mutation to shift to a new reading frame. A frame shift may produce a stop codon downstream of the mutation (which would have the same effect as a nonsense mutation caused by base substitution), or it may produce an entirely new amino acid sequence. (Stop) Deletion causing altered amino acid sequence Fig b, p. 299
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Animation: Frameshift Mutation
CLICK TO PLAY
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Transposons Movable DNA sequences Retrotransposons
“jump” into the middle of a gene Retrotransposons replicate by forming RNA intermediate reverse transcriptase converts to original DNA sequence before jumping into gene
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Animation: Protein Synthesis Summary
CLICK TO PLAY
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