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Physics 121
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9. Equilibrium and Elasticity
9.1 Statics: Forces in Equilibrium 9.2 Conditions for Equilibrium 9.3 Solving Statics Problems 9.4 Measurement and Uncertainty 9.5 Stability and Balance 9.6 Elasticity: Stress and Strain
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What is the tension in the string?
Example The String What is the tension in the string? 300 2 kg W = 1 kg
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The Conditions for Equilibrium
Fx = 0 Fy = 0 = 0 300 2 kg W = 1 kg
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(2)(10)(L) + (1)(10)(L/2) = (T sin 30)(L)
Solution The String = 0 (2)(10)(L) + (1)(10)(L/2) = (T sin 30)(L) T = 50 N
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Are there any (reaction) forces at the hinge?
Example The Hinge Are there any (reaction) forces at the hinge? 300 2 kg W = 1 kg
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All the forces on the beam are shown
Solution The Hinge All the forces on the beam are shown Solution continues on the next slide 20 N 10 N H V T sin 30 T cos 30
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Fx = 0 So H = T cos 300 or H = 50 * 0.87 or H = 44 N
Solution The Hinge Fx = 0 So H = T cos 300 or H = 50 * 0.87 or H = 44 N Fy = 0 So V + 50 sin 300 = or V = 5 N 20 N 10 N H V T sin 30 T cos 30
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Young’s Modulus = Stress / Strain
Elasticity Stress = Force / Area Strain = L / L Young’s Modulus = Stress / Strain
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Example The Piano A 1.6 m long steel piano wire has a diameter of 0.20 cm. How great is the tension in the wire if it stretches 0.30 cm when tightened. [ Young’s Modulus for steel is E = 2.0 x N / m2 ]
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Solution The Piano strain = L / L = 0.003/1.6 = x m stress = F / A = F/ r2 = F /3 .1 x m2 E = stress / strain 2.0 x = F /(3 .1 x )(1.875 x ) F = 1200 N
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That’s all folks!
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