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Published byMeghan Brenda Jefferson Modified over 9 years ago
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Fourier Concepts ES3
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© 2001 KEDMI Scientific Computing. All Rights Reserved. Square wave example: V(t)= 4/ sin(t) + 4/3 sin(3t) + 4/5 sin(5t) + 4/7 sin(7t) + 4/9 sin(9t) + … time Any periodic waveform can be constructed by adding sine and cosine waves with frequencies that are integer multiples of the waveform’s frequency. added frequency total signal … frequency |v| fofo 5f o 7f o 9f o 11f o 3f o Frequency spectrum of a square wave
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Flute
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Piano 4, 5, 6 f o = 260 Hz 2f o = 520 Hz 3f o = 780 Hz
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Acoustic Bass fofo 2f o fofo
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Hearing and the Ear a simplified explanation “unwound” cochlea (3.5cm) ear drum 030,000 Hair cell number amplitude of vibration = sin(2 200t) + 0.2sin(2 5000t) 200Hz 5kHz 1961 Nobel Prize, Georg von Bekesy
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Hearing and the Ear (cont.)
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FFT demonstration A microphone creates a voltage that is proportional to the pressure of a sound wave. This voltage is converted to a sequence of numbers that are stored in the computer’s memory The Fast Fourier Transform (FFT) is used to extract the amplitude of each sinusoid from the sound signal.
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Filters
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Filters are usually represented as two-port networks Two-port Network V in (t) + V out (t) - +-+- Input PortOutput Port
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Filters are usually represented as two-port networks Transfer Function: H( ) V IN + V OUT - +-+- Input PortOutput Port
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Transfer Function Example INPUT Signal, v in (t)
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FFT of the INPUT Signal: V IN ( ) Transfer Function Example
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H( ) 1 Transfer Function Example The Transfer Function, H( ) …a low-pass filter
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Transfer Function Example H( ) 1 At 530 Hz: V OUT = V IN x 1 At 1060 Hz: V OUT = V IN x 1 At 1590 Hz: V OUT = V IN x 0.25 At 2120 Hz: V OUT = V IN x 0.0
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Transfer Function Example FFT of the OUTPUT Signal: V OUT ( )
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A real low-pass filter R 1 / j C V in V out
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The Transfer Function of a low-pass filter R=1000 C=1 uF =1/RC is the cut-off frequency |H( )|=1/√2 1000 rad/s = 159 Hz
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The Transfer Function of a low-pass filter 45 o phase shift @ = 1/RC
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