1. Using Math to Predict the Future  Differential Equation Models

2. Overview Observe systems, model relationships, predict future evolution Observe systems, model relationships, predict future evolution One KEY tool: Differential Equations One KEY tool: Differential Equations Most significant application of calculus Most significant application of calculus Remarkably effective Remarkably effective Unbelievably effective in some applications Unbelievably effective in some applications Some systems inherently unpredictable Some systems inherently unpredictable Weather Weather Chaos Chaos

3. Mars Global Surveyor Launched 11/7/96 Launched 11/7/96 10 month, 435 million mile trip 10 month, 435 million mile trip Final 22 minute rocket firing Final 22 minute rocket firing Stable orbit around Mars Stable orbit around Mars

4. Mars Rover Missions 7 month, 320 million mile trip 7 month, 320 million mile trip 3 stage launch program 3 stage launch program Exit Earth orbit at 23,000 mph Exit Earth orbit at 23,000 mph 3 trajectory corrections en route 3 trajectory corrections en route Final destination: soft landing on Mars Final destination: soft landing on Mars

6. Interplanetary Golf Comparable shot in miniature golf Comparable shot in miniature golf 14,000 miles to the pin more than half way around the equator 14,000 miles to the pin more than half way around the equator Uphill all the way Uphill all the way Hit a moving target Hit a moving target T off from a spinning merry-go-round T off from a spinning merry-go-round

8. Course Corrections 3 corrections in cruise phase 3 corrections in cruise phase Location measurements Location measurements Radio Ranging to Earth Accurate to 30 feet Radio Ranging to Earth Accurate to 30 feet Reference to sun and stars Reference to sun and stars Position accurate to 1 part in 200 million -- 99.9999995% accurate Position accurate to 1 part in 200 million -- 99.9999995% accurate

9. How is this possible? One word answer: Differential Equations (OK, 2 words, so sue me)

10. Reductionism Highly simplified crude approximation Highly simplified crude approximation Refine to microscopic scale Refine to microscopic scale In the limit, answer is exactly right In the limit, answer is exactly right Right in a theoretical sense Right in a theoretical sense Practical Significance: highly effective means for constructing and refining mathematical models Practical Significance: highly effective means for constructing and refining mathematical models

11. Tank Model Example 100 gal water tank 100 gal water tank Initial Condition: 5 pounds of salt dissolved in water Initial Condition: 5 pounds of salt dissolved in water Inflow: pure water 10 gal per minute Inflow: pure water 10 gal per minute Outflow: mixture, 10 gal per minute Outflow: mixture, 10 gal per minute Problem: model the amount of salt in the tank as a function of time Problem: model the amount of salt in the tank as a function of time

12. In one minute … Start with 5 pounds of salt in the water Start with 5 pounds of salt in the water 10 gals of the mixture flows out 10 gals of the mixture flows out That is 1/10 of the tank That is 1/10 of the tank Lose 1/10 of the salt or.5 pounds Lose 1/10 of the salt or.5 pounds Change in amount of salt is –(.1)5 pounds Change in amount of salt is –(.1)5 pounds Summary: t = 1, s = -(.1)(5) Summary: t = 1, s = -(.1)(5)

13. Critique Water flows in and out of the tank continuously, mixing in the process Water flows in and out of the tank continuously, mixing in the process During the minute in question, the amount of salt in the tank will vary During the minute in question, the amount of salt in the tank will vary Water flowing out at the end of the minute is less salty than water flowing out at the start Water flowing out at the end of the minute is less salty than water flowing out at the start Total amount of salt that is removed will be less than.5 pounds Total amount of salt that is removed will be less than.5 pounds

14. Improvement: ½ minute In.5 minutes, water flow is.5(10) = 5 gals In.5 minutes, water flow is.5(10) = 5 gals IOW: in.5 minutes replace.5(1/10) of the tank IOW: in.5 minutes replace.5(1/10) of the tank Lose.5(1/10)(5 pounds) of salt Lose.5(1/10)(5 pounds) of salt Summary: t =.5, s = -.5(.1)(5) Summary: t =.5, s = -.5(.1)(5) This is still approximate, but better This is still approximate, but better

15. Improvement:.01 minute In.01 minutes, water flow is.01(10) =.01(1/10) of full tank In.01 minutes, water flow is.01(10) =.01(1/10) of full tank IOW: in.01 minutes replace.01(1/10) =.001 of the tank IOW: in.01 minutes replace.01(1/10) =.001 of the tank Lose.01(1/10)(5 pounds) of salt Lose.01(1/10)(5 pounds) of salt Summary: t =.01, s = -.01(.1)(5) Summary: t =.01, s = -.01(.1)(5) This is still approximate, but even better This is still approximate, but even better

16. Summarize results t (minutes) s (pounds) 1-1(.1)(5).5-.5(.1)(5).01-.01(.1)(5)

17. Summarize results t (minutes) s (pounds) 1-1(.1)(5).5-.5(.1)(5).01-.01(.1)(5) h-h(.1)(5)

18. Other Times So far, everything is at time 0 So far, everything is at time 0 s = 5 pounds at that time s = 5 pounds at that time What about another time? What about another time? Redo the analysis assuming 3 pounds of salt in the tank Redo the analysis assuming 3 pounds of salt in the tank Final conclusion: Final conclusion:

19. So at any time… If the amount of salt is s, We still don’t know a formula for s(t) But we do know that this unknown function must be related to its own derivative in a particular way.

20. Differential Equation Function s(t) is unknown Function s(t) is unknown It must satisfy s’ (t) = -.1 s(t) It must satisfy s’ (t) = -.1 s(t) Also know s(0) = 5 Also know s(0) = 5 That is enough information to completely determine the function: That is enough information to completely determine the function: s(t) = 5e -.1t s(t) = 5e -.1t

21. Derivation Want an unknown function s(t) with the property that s’ (t) = -.1 s(t) Want an unknown function s(t) with the property that s’ (t) = -.1 s(t) Reformulation: s’ (t) / s(t) = -.1 Reformulation: s’ (t) / s(t) = -.1 Remember that pattern – the derivative divided by the function? Remember that pattern – the derivative divided by the function? (ln s(t))’ = -.1 (ln s(t))’ = -.1 (ln s(t)) = -.1 t + C (ln s(t)) = -.1 t + C s (t) = e -.1t + C = e C e -.1t =Ae -.1t s (t) = e -.1t + C = e C e -.1t =Ae -.1t s (0) =Ae 0 =A s (0) =Ae 0 =A Also know s(0) = 5. So s (t) = 5e -.1t Also know s(0) = 5. So s (t) = 5e -.1t

22. Relative Growth Rate In tank model, s’ (t) / s(t) = -.1 In tank model, s’ (t) / s(t) = -.1 In general f’ (t) / f(t) is called the relative growth rate of f. In general f’ (t) / f(t) is called the relative growth rate of f. AKA the percent growth rate – gives rate of growth as a percentage AKA the percent growth rate – gives rate of growth as a percentage In tank model, relative growth rate is constant In tank model, relative growth rate is constant Constant relative growth r always leads to an exponential function Ae rt Constant relative growth r always leads to an exponential function Ae rt In section 3.8, this is used to model population growth In section 3.8, this is used to model population growth

23. Required Knowledge to set up and solve differential equations Basic concepts of derivative as instantaneous rate of change Basic concepts of derivative as instantaneous rate of change Conceptual or physical model for how something changes over time Conceptual or physical model for how something changes over time Detailed knowledge of patterns of derivatives Detailed knowledge of patterns of derivatives

24. Applications of Tank Model Other substances than salt Other substances than salt Incorporate additions as well as reductions of the substance over time Incorporate additions as well as reductions of the substance over time Pollutants in a lake Pollutants in a lake Chemical reactions Chemical reactions Metabolization of medications Metabolization of medications Heat flow Heat flow

25. Miraculous! Start with simple yet plausible model Start with simple yet plausible model Refine through limit concept to an exact equation about derivative Refine through limit concept to an exact equation about derivative Obtain an exact prediction of the function for all time Obtain an exact prediction of the function for all time This method has been found over years of application to work incredibly, impossibly well This method has been found over years of application to work incredibly, impossibly well

26. On the other hand… In some applications the method does not seem to work at all In some applications the method does not seem to work at all We now know that the form of the differential equation matters a great deal We now know that the form of the differential equation matters a great deal For certain forms of equation, theoretical models can never give accurate predictions of reality For certain forms of equation, theoretical models can never give accurate predictions of reality The study of when this occurs and what (if anything) to do is part of the subject of CHAOS. The study of when this occurs and what (if anything) to do is part of the subject of CHAOS.