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STOICHIOMETRY Calculations Based on Chemical Equations
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Iron (III) oxide reacts with carbon monoxide to form iron and carbon dioxide. Fe 2 O 3 +CO Fe+CO 2 323 How many CO molecules are required to react with 25 particles of Fe 2 O 3 ?
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Iron (III) Oxide reacts with carbon monoxide to form iron and carbon dioxide. Fe 2 O 3 +CO Fe+CO 2 32 3 How many iron atoms can be produced by the reaction of 2.5 x 10 5 particles of Fe 2 O 3 ?
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STOICHIOMETRIC RELATIONSHIPS Formulas can also represent MOLES of substances involved in chemical reactions. Equations define reaction ratios, i.e. the molar ratios of reactants and products
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What mass of CO is required to react with 146 grams of iron (III) oxide? Fe 2 O 3 +3CO 2Fe+3CO 2
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What mass of iron (III) oxide is required to produce 8.65 grams of carbon dioxide? Fe 2 O 3 +3CO 2Fe+3CO 2
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Limiting Reactants (Reagents) and Percent Yield
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Calculations need to be based on the limiting reactant. Example 1: Suppose a box contains 87 bolts, 110 washers and 99 nails. How many sets of 1 bolt, 2 washers and 1 nail can you use to create? What is the limiting factor? 55 sets; washers limit the amount
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Calculations need to be based on the limiting reactant. Example 2: What is the maximum mass of sulfur dioxide that can be produced by the reaction of 95.6 g carbon disulfide with 100. g oxygen? CS 2 + O 2 CO 2 + SO 2 Start by balancing the equation…
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Calculations need to be based on the limiting reactant. Example 2: What is the maximum mass of sulfur dioxide that can be produced by the reaction of 95.6 g carbon disulfide with 100. g oxygen? CS 2 + 3O 2 CO 2 + 2SO 2 Now solve the problem…
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Example 2: What is the maximum mass of sulfur dioxide that can be produced by the reaction of 95.6 g carbon disulfide with 100. g oxygen? CS 2 + 3O 2 CO 2 + 2SO 2 Which reactant is LIMITING?
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Example 2: What is the mass of sulfur dioxide that can be produced by the reaction of 95.6 g carbon disulfide with 100. g oxygen? CS 2 + 3O 2 CO 2 + 2SO 2 O 2 limits the amount of SO 2 that can be produced. CS 2 is in excess.
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Example 2: What is the mass of sulfur dioxide that can be produced by the reaction of 95.6 g carbon disulfide with 100. g oxygen? CS 2 + 3O 2 CO 2 + 2SO 2 134 g of SO 2 can be produced in this reaction.
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Calculations need to be based on the limiting reactant. Example 3: What mass of CO 2 could be formed by the reaction of 8.0 g CH 4 with 48 g O 2 ? CH 4 + O 2 CO 2 + H 2 O Start by balancing the equation…
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Calculations need to be based on the limiting reactant. Example 3: What mass of CO 2 could be formed by the reaction of 8.0 g CH 4 with 48 g O 2 ? CH 4 + 2O 2 CO 2 + 2H 2 O Now solve the problem…
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Example 3: What mass of CO 2 could be formed by the reaction of 8.0 g CH 4 with 48 g O 2 ? CH 4 + 2O 2 CO 2 + 2H 2 O Which reactant is LIMITING?
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Example 3: What mass of CO 2 could be formed by the reaction of 8.0 g CH 4 with 48 g O 2 ? CH 4 + 2O 2 CO 2 + 2H 2 O CH 4 limits the amount of CO 2 that can be produced. O 2 is in excess.
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Many chemical reactions do not go to completion (reactants are not completely converted to products). Percent Yield: indicates what percentage of a desired product is obtained.
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So far, the masses we have calculated from chemical equations were based on the assumption that each reaction occurred 100%. The THEORETICAL YIELD is the yield calculated from the balance equation. The ACTUAL YIELD is the amount “actually” obtained in an experiment.
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Look back at Example 2. We found that 134 g of SO 2 could be formed from the reactants. In an experiment, you formed 130 g of SO 2. What is your percent yield?
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Example: A 10.0 g sample of ethanol, C 2 H 5 OH, was boiled with excess acetic acid, CH 3 COOH, to produce 14.8 g of ethyl acetate, CH 3 COOC 2 H 5. What percent yield of ethyl acetate is this? CH 3 COOH + C 2 H 5 OH CH 3 COOC 2 H 5 + H 2 O
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Example: A 10.0 g sample of ethanol, C 2 H 5 OH, was boiled with excess acetic acid, CH 3 COOH, to produce 14.8 g of ethyl acetate, CH 3 COOC 2 H 5. What percent yield of ethyl acetate is this?
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