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1 Types of Reactions Precipitation reactions l When aqueous solutions of ionic compounds are poured together a solid forms. l A solid that forms from mixed solutions is a precipitate l If you’re not a part of the solution, your part of the precipitate
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2 Precipitation reactions NaOH(aq) + FeCl 3 (aq) NaCl(aq) + Fe(OH) 3 (s) l is really Na + (aq)+OH - (aq) + Fe +3 + Cl - (aq) Na + (aq) + Cl - (aq) + Fe(OH) 3 (s) l So all that really happens is OH - (aq) + Fe +3 Fe(OH) 3 (s) l Double replacement reaction
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3 Precipitation reaction l We can predict the products l Can only be certain by experimenting l The anion and cation switch partners AgNO 3 (aq) + KCl(aq) Zn(NO 3 ) 2 (aq) + BaCr 2 O 7 (aq) CdCl 2 (aq) + Na 2 S(aq)
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4 Precipitations Reactions l Only happen if one of the products is insoluble l Otherwise all the ions stay in solution- nothing has happened. l Need to memorize the rules for solubility (pg 145)
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5 Solubility Rules All nitrates are soluble Alkali metals ions and NH 4 + ions are soluble Halides are soluble except Ag +, Pb +2, and Hg 2 +2 Most sulfates are soluble, except Pb +2, Ba +2, Hg +2,and Ca +2
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6 Solubility Rules Most hydroxides are slightly soluble (insoluble) except NaOH and KOH Sulfides, carbonates, chromates, and phosphates are insoluble Lower number rules supersede so Na 2 S is soluble
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7 Three Types of Equations l Molecular Equation- written as whole formulas, not the ions. K 2 CrO 4 (aq) + Ba(NO 3 ) 2 (aq) l Complete Ionic equation show dissolved electrolytes as the ions. 2K + + CrO 4 -2 + Ba +2 + 2 NO 3 - BaCrO 4 (s) + 2K + + 2 NO 3 - l Spectator ions are those that don’t react.
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8 Three Type of Equations l Net Ionic equations show only those ions that react, not the spectator ions Ba +2 + CrO 4 -2 BaCrO 4 (s) l Write the three types of equations for the reactions when these solutions are mixed. l iron (III) sulfate and potassium sulfide Lead (II) nitrate and sulfuric acid.
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9 Stoichiometry of Precipitation l Exactly the same, except you may have to figure out what the pieces are. l What mass of solid is formed when 100.00 mL of 0.100 M Barium chloride is mixed with 100.00 mL of 0.100 M sodium hydroxide? l What volume of 0.204 M HCl is needed to precipitate the silver from 50.ml of 0.0500 M silver nitrate solution ?
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10 Types of Reactions Acid-Base l For our purposes an acid is a proton donor. l a base is a proton acceptor usually OH - l What is the net ionic equation for the reaction of HCl(aq) and KOH(aq)? Acid + Base salt + water H + + OH - H 2 O
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11 Acid - Base Reactions l Often called a neutralization reaction Because the acid neutralizes the base. l Often titrate to determine concentrations. l Solution of known concentration (titrant), l is added to the unknown (analyte), l until the equivalence point is reached where enough titrant has been added to neutralize it.
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12 Titration l Where the indicator changes color is the endpoint. l Not always at the equivalence point. l A 50.00 mL sample of aqueous Ca(OH) 2 requires 34.66 mL of 0.0980 M Nitric acid for neutralization. What is [Ca(OH) 2 ]? l # of H + x M A x V A = # of OH - x M B x V B
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13 Acid-Base Reaction l 75 mL of 0.25M HCl is mixed with 225 mL of 0.055 M Ba(OH) 2. What is the concentration of the excess H + or OH - ?
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14 Types of Reaction Oxidation-Reduction called Redox l Ionic compounds are formed through the transfer of electrons. l An Oxidation-reduction reaction involves the transfer of electrons. l We need a way of keeping track.
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15 Oxidation States l A way of keeping track of the electrons. l Not necessarily true of what is in nature, but it works. l need the rules for assigning (memorize). The oxidation state of elements in their standard states is zero. Oxidation state for monoatomic ions are the same as their charge.
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16 Oxidation states Oxygen is assigned an oxidation state of - 2 in its covalent compounds except as a peroxide. In compounds with nonmetals hydrogen is assigned the oxidation state +1. In its compounds fluorine is always –1. The sum of the oxidation states must be zero in compounds or equal the charge of the ion.
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17 Oxidation States l Assign the oxidation states to each element in the following. l CO 2 l NO 3 - l H 2 SO 4 l Fe 2 O 3 l Fe 3 O 4
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18 Oxidation-Reduction l Transfer electrons, so the oxidation states change. Na + 2Cl 2 2NaCl CH 4 + 2O 2 CO 2 + 2H 2 O l Oxidation is the loss of electrons. l Reduction is the gain of electrons. l OIL RIG l LEO GER
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19 Oxidation-Reduction l Oxidation means an increase in oxidation state - lose electrons. l Reduction means a decrease in oxidation state - gain electrons. l The substance that is oxidized is called the reducing agent. l The substance that is reduced is called the oxidizing agent.
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20 Redox Reactions
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21 Agents l Oxidizing agent gets reduced. l Gains electrons. l More negative oxidation state. l Reducing agent gets oxidized. l Loses electrons. l More positive oxidation state.
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22 Identify the l Oxidizing agent l Reducing agent l Substance oxidized l Substance reduced l in the following reactions Fe (s) + O 2 (g) Fe 2 O 3 (s) Fe 2 O 3 (s)+ 3 CO(g) 2 Fe(l) + 3 CO 2 (g) SO 3 2- + H + + MnO 4 - SO 4 2- + H 2 O + Mn 2+
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23 Half-Reactions l All redox reactions can be thought of as happening in two halves. l One produces electrons - Oxidation half. l The other requires electrons - Reduction half. l Write the half reactions for the following. Na + Cl 2 Na + + Cl - SO 3 2- + H + + MnO 4 - SO 4 2- + H 2 O + Mn +2
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24 Balancing Redox Equations l In aqueous solutions the key is the number of electrons produced must be the same as those required. l For reactions in acidic solution an 8 step procedure. Write separate half reactions For each half reaction balance all reactants except H and O Balance O using H 2 O
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25 Acidic Solution Balance H using H + Balance charge using e - Multiply equations to make electrons equal Add equations and cancel identical species Check that charges and elements are balanced.
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26 Practice l The following reactions occur in aqueous solution. Balance them MnO 4 - + Fe +2 Mn +2 + Fe +3 Cu + NO 3 - Cu +2 + NO(g) Pb + PbO 2 + SO 4 -2 PbSO 4 Mn +2 + NaBiO 3 Bi +3 + MnO 4 -
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27 Now for a tough one Fe(CN) 6 -4 + MnO 4 - Mn +2 + Fe +3 + CO 2 + NO 3 -
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28 Basic Solution l Do everything you would with acid, but add one more step. l Add enough OH - to both sides to neutralize the H + l Makes water CrI 3 + Cl 2 CrO 4 2- + IO 4 - + Cl - Fe(OH) 2 + H 2 O 2 Fe(OH) - Cr(OH) 3 + OCl - + OH - CrO 4 2- + Cl - + H 2 O
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29 Redox Titrations l Same as any other titration. l the permanganate ion is used often because it is its own indicator. MnO 4 - is purple, Mn +2 is colorless. When reaction solution remains clear, MnO 4 - is gone. l Chromate ion is also useful, but color change, orangish yellow to green, is harder to detect.
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30 Example l The iron content of iron ore can be determined by titration with standard KMnO 4 solution. The iron ore is dissolved in excess HCl, and the iron reduced to Fe +2 ions. This solution is then titrated with KMnO 4 solution, producing Fe +3 and Mn +2 ions in acidic solution. If it requires 41.95 mL of 0.205 M KMnO 4 to titrate a solution made with 0.6128 g of iron ore, what percent of the ore was iron?
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31 Extra Credit l Nuclear Power l Write a paper that describes l 1. How does it work? l 2. What are the advantages? l 3. What are the disadvantages? l 4. Using your information to support your conclusion, answer the question, “What role should nuclear power play in future energy generation for the United States?” l 5-7 pages l Researched using MLA style with in text citations. l Due Oct. 26- no exceptions.
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