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Published byDestiny Greer Modified over 11 years ago
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Indicate what effect the change will have on the acceleration.
The mass of the cart is increased to 2 kg.
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For 100 points The acceleration decreases
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Indicate what effect the change will have on the acceleration.
The towing force is increased to 1.0 N.
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For 500 points The acceleration increases
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Indicate what effect the change will have on the acceleration.
Both the mass of the cart and the towing force are doubled.
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For 300 points The acceleration remains the same
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Indicate what effect the change will have on the acceleration.
The 0.5 N towing force is applied at an angle as shown at right.
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For 1000 points The acceleration decreases
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Indicate what effect the change will have on the acceleration.
The track is inclined as shown below at right.
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For 2500 points The acceleration decreases
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Indicate what effect the change will have on the acceleration.
The 0.5 N force is applied to two 500 g carts hooked together as shown below right.
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For 400 points The acceleration remains the same
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Draw the position vs. time and acceleration vs
Draw the position vs. time and acceleration vs. time graphs corresponding to the velocity graph between points c and d
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For 100 points
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For the interval from a to b the train is: a. speeding up.
b. slowing down. c. moving at constant speed. d. moving in the negative direction.
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For points b. slowing down
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Is the net force on the train equal to zero at any time? Explain.
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For points From b to c because the train is moving at a constant speed
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Where is the net force on the train the largest? Explain.
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For 1000 points From c to d because the acceleration is the greatest between those two points
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A 700. kg Yugo can go from rest to a speed of 45 m/s in 9. 0s
A 700. kg Yugo can go from rest to a speed of 45 m/s in 9.0s. What average net force acts on the car?
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For 100 points 3500 N
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Consider the block on a surface below
Consider the block on a surface below. The coefficient of friction, µ, is 0.20. If a 10. N force is applied to the block, what is its acceleration?
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For 8000 points 3 m/s2
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Consider the block on a surface below
Consider the block on a surface below. The coefficient of friction, µ, is 0.20. How fast will the block be moving if the force of 10 N is applied for 5.0s?
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For 200 points 15 m/s
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Consider the block on a surface below
Consider the block on a surface below. The coefficient of friction, µ, is 0.20. How far will the block travel if the force of 10 N is applied for 5.0s?
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For 300 points 38 m
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The diagram below depicts a frictionless apparatus similar to that used for your Newton's 2nd Law experiment. Block A has a mass of 25 kg and block B has a mass of 5.0 kg. Determine the acceleration of the system and the tension in the string.
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For 3000 points 1.6 m/s2 41 N
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A 70. 0 kg box is pulled across a frictionless surface by a 300
A 70.0 kg box is pulled across a frictionless surface by a 300. N force at an angle of 30.° to the horizontal. What is the acceleration of the box in the x-direction?
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For 400 points 3.7 m/s2
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A 70. 0 kg box is pulled across a frictionless surface by a 300
A 70.0 kg box is pulled across a frictionless surface by a 300. N force at an angle of 30.° to the horizontal. What is the normal force on the box?
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For 500 points 536 N
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A 20.0 kg block is allowed to accelerate down a ramp with negligible friction.
Determine the acceleration of the block.
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For 200 points 3.2 m/s2
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A 20.0 kg block is allowed to accelerate down a ramp with negligible friction.
Would the acceleration be different if the mass of the block were 10kg? Explain.
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For 600 points No, because it is gravity that is pulling the block down the ramp. Only changing the incline changes the acceleration, as long as the ramp is frictionless.
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For 300 points
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