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Published byErick Andrews Modified over 9 years ago
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At the beginning, there was a couple of rabbits (one male and one female) in the farm.
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A female rabbit would give birth to one male and one female rabbits monthly.
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In the next month, the young couple would give birth to one male and one female rabbits too.
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1:2:3:
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4: 5……………………….
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After n months….
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How many pairs of rabbits are in the farm?
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Firstly!
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For every natural number (1, 2, 3, 4,.....) Let a be the number of the rabbits in the farm at the beginning of the nth month[or the end of the (n-1)th month].
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Then !
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a =1 a =2 a = sum of the pairs of rabbits in the beginning of the second month a and the first pair of rabbits at the beginning of the first month a [i.e., in the 2nd month, the number of baby pairs a ] + ++ 2 + 1 = = 3 pairs
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a = sum up the pairs of rabbits in the beginning of the third month a and, he first pair of rabbits at the beginning of the second month a [i.e., in the 3rd month, the number of baby pairs a ] =3 + 2 = 5 pairs a : 4 +
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a = sum up the pairs of rabbits in the beginning of the (n-1) month a(n-1) and the first pair of rabbits at the beginning of the (n-2) month a(n-2) [ i.e., in the (n-1)th month, the number of baby pairs a ] a = a + a Therefore! a = a + a n a :
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Solve (1) and (2) simultaneously,
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Month (n) 123456789101112 Number of old rabbits 1123581321345589144 Number of baby rabbits01123581321345589 Total number of rabbits 123581321345589144233 Let’s see the data !
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At last!
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We can substitute the number of months (n) in to the equation a n = ( ) n+1 - ( ) n+1. to know how many pairs of rabbits in the farm!
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!!BYE!!
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Done by : Chu Shun Leung 6C(13) Done by : Chu Shun Leung 6C(13)
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