1. Algebra 2 Week #1A Review

2. It’s Friday!

3. Week #1A – Section 4 Classwork – –He is decomposing –Buoy meets gull –Bushed Homework 1. x = 5 2. x = - 2 3. x = - 1 4. x = 1 5. x = 4 6. x = 0 7. x = - 4 8. x = 7 Extra credit ⅜a - ⅞b + ⅛a + ⅜b = ⅜a + ⅛a - ⅞b + ⅜b = ½a - ½b

4. STANDARD STUDIED THIS WEEK: (leading to) CA STANDARD: 1 – To be able to solve equations and inequalities involving absolute value.

5. Vocabulary to Know coefficient: the number in front of a variable (like the 2 in 2x) combining like terms: adding terms with the same variable and exponent distributive property: a(b + c) = ab + ac equation: an algebraic expression with a = in it integers: whole numbers (positive, negative, and zero) like terms: terms with same variable and exponent PEMDAS: order of operations true/false statements: an equation that is true/not true

6. How to: A. Do arithmetic with integers (or positive and negative numbers) 1.Multiplication or division Same signs? Answer is positive. Different signs? Answer is negative. 2.Addition or subtraction Same signs? ADD and keep the sign. Different signs? SUBTRACT and keep the sign of the larger number.

7. How to: A. Do arithmetic with integers (or positive and negative numbers) EXAMPLES: - 20 ÷ - 4 =

8. How to: A. Do arithmetic with integers (or positive and negative numbers) EXAMPLES: - 20 ÷ - 4 = 5 - 20 – 4 = - 24

9. How to: B. Use the order of operations (PEMDAS). 1.parentheses 2.exponents 3.multiplication/division 4.addition/subtraction EXAMPLE: 5 – 3(2 + 1) 2 + 16 =

10. How to: B. Use the order of operations (PEMDAS). 1.parentheses 2.exponents 3.multiplication/division 4.addition/subtraction EXAMPLE: 5 – 3(2 + 1) 2 + 16 = 5 – 3(3) 2 + 16

11. How to: B. Use the order of operations (PEMDAS). 1.parentheses 2.exponents 3.multiplication/division 4.addition/subtraction EXAMPLE: 5 – 3(2 + 1) 2 + 16 = 5 – 3(3) 2 + 16 = 5 – 3(9) + 16

12. How to: B. Use the order of operations (PEMDAS). 1.parentheses 2.exponents 3.multiplication/division 4.addition/subtraction EXAMPLE: 5 – 3(2 + 1) 2 + 16 = 5 – 3(3) 2 + 16 = 5 – 3(9) + 16 = 5 – 27 + 16

13. How to: B. Use the order of operations (PEMDAS). 1.parentheses 2.exponents 3.multiplication/division 4.addition/subtraction EXAMPLE: 5 – 3(2 + 1) 2 + 16 = 5 – 3(3) 2 + 16 = 5 – 3(9) + 16 = 5 – 27 + 16 = 21 – 27

14. How to: B. Use the order of operations (PEMDAS). 1.parentheses 2.exponents 3.multiplication/division 4.addition/subtraction EXAMPLE: 5 – 3(2 + 1) 2 + 16 = 5 – 3(3) 2 + 16 = 5 – 3(9) + 16 = 5 – 27 + 16 = 21 – 27 = - 6

15. How to: C. Solve one variable equations. 1.Variable on each side of the =? Move smaller variable to the same side of the = (don’t forget to change the sign) and add it to the variable that’s already there. 2.Number on the same side of the = as the variable? Move it to the other side of the = (don’t forget to change the sign) and add it with any number that’s already there. 3. Divide both sides if the variable has a coefficient.

16. How to: C. Solve one variable equations. EXAMPLES 2x – 5 = 10

17. How to: C. Solve one variable equations. EXAMPLES 2x – 5 = 10 2x = 15

18. How to: C. Solve one variable equations. EXAMPLES 2x – 5 = 10 2x = 15 x = 15/2

19. How to: C. Solve one variable equations. EXAMPLES - 6x – 4 = 3x - 67

20. How to: C. Solve one variable equations. EXAMPLES 6x – 4 = 3x – 67 3x – 4 = - 67

21. How to: C. Solve one variable equations. EXAMPLES 6x – 4 = 3x – 67 3x – 4 = - 67 3x = - 63

22. How to: C. Solve one variable equations. EXAMPLES 6x – 4 = 3x – 67 3x – 4 = - 67 3x = - 63 x = - 21

23. How to: D. Get an equation ready to be solved (should be done FIRST). 1. If you see ( )s, multiply. 2.Combine any like terms on each side of the = sign. (Do NOT use opposite operations.) 3.Get rid of fractions. Multiply the whole equation by the number in the denominator. OR use the least common denominator.

24. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES - 6x – 4 + 2x = 24 + 3(x – 21)

25. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES - 6x – 4 + 2x = 24 + 3(x – 21) - 6x – 4 + 2x = 24 + 3x - 63

26. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES - 6x – 4 + 2x = 24 + 3(x – 21) - 6x – 4 + 2x = 24 + 3x – 63 - 4x – 4 = - 39 + 3x

27. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES - 6x – 4 + 2x = 24 + 3(x – 21) - 6x – 4 + 2x = 24 + 3x – 63 - 4x – 4 = - 39 + 3x - 4 = - 39 + 7x

28. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES - 6x – 4 + 2x = 24 + 3(x – 21) - 6x – 4 + 2x = 24 + 3x – 63 - 4x – 4 = - 39 + 3x - 4 = - 39 + 7x 35 = 7x

29. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES - 6x – 4 + 2x = 24 + 3(x – 21) - 6x – 4 + 2x = 24 + 3x – 63 - 4x – 4 = - 39 + 3x - 4 = - 39 + 7x 35 = 7x x = 5

30. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES 4x + 3 = ¾x

31. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES 4x + 3 = ¾x 4(4x) + 4(3) = 4(¾x)

32. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES 4x + 3 = ¾x 4(4x) + 4(3) = 4(¾x) 16x + 12 = 3x

33. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES 4x + 3 = ¾x 4(4x) + 4(3) = 4(¾x) 16x + 12 = 3x 13x + 12 = 0

34. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES 4x + 3 = ¾x 4(4x) + 4(3) = 4(¾x) 16x + 12 = 3x 13x + 12 = 0 13x = - 12

35. How to: D. Get an equation ready to be solved (should be done FIRST). EXAMPLES 4x + 3 = ¾x 4(4x) + 4(3) = 4(¾x) 16x + 12 = 3x 13x + 12 = 0 13x = - 12 x = - 12/13