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Production Reading Varian 17-20 But particularly, All Ch 17 and the Appendices to Chapters 18 & 19. We start with Chapter 17.
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Production Technology: y = f (x 1, x 2, x 3,... x n ) x i ’s = inputs into the production process For simplicity consider the case of 2 inputs e.g. labour and capital, L and K y = f (K, L)
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Last year depicted the relationship between inputs as an isoquant y = f (K, L) K L yoyo y1y1
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L K y=output y0y0 L0L0 K0K0 y=f(K,L) An alternative representation is:
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This year want to analyse isoquants and the firm’s production problem in the same fashion as utility. y = y(K,L) Taking the total derivative dy = dK + dL MP K MP L And along a given isoquant dy = 0
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If dy = 0 then MP k dK+MP L dL=0 MP K dk = - MP L dL Or slope of the isoquant Marginal Rate of Technical Substitution of K per unit of L (Amount of K that must be substituted per unit of L in order to keep output constant) = MRTS KL
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Usually assume that MRTS KL is diminishing Follows from the fact that MP of capital and labour is decreasing. Thus, K L = MP L, gets smaller as we increase L when we substitute L for K, while = MP k gets bigger as K gets smaller.
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So as L gets bigger and K gets smaller, the top of the line goes down while the bottom goes up, so dK/dL gets smaller as L gets bigger That is, Isoquants are Quasi ‘convex’ x2x2 x1x1
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Note MRTS different from diminishing marginal product As we noted above, ‘Law’ of diminishing marginal product says df/dL gets smaller as L gets bigger holding all other inputs constant y xixi
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But in this exercise we are reducing K as we increase L, so all other things are not constant So MRTS is not the same as Diminishing Marginal Product, though they are related. x2x2 x1x1
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So Distinct Concepts 1. Diminishing Marginal Product 2. Diminishing Marginal Rate of … …Technical Substitution 3. Returns to Scale
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Returns to Scale A function is homogenous if degree k iff f (t K, t L) = t k f(K,L,) e.g. if k = 1, i.e. there are C.R.S. then f (4K, 4L) = 4f (K,L) if IRS, e.g. k = 2 then f (4K, 4L) = 4 2 f (K,L)=16f (K,L) if DRS e.g. k = ½ then f (4K,4L) = 4 ½ f (K,L)=2f (K,L)
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Ch 18 Varian Problem 1. The Profit maximisation problem Where x i are inputs w i are the prices of inputs Now we usually know what y is because unlike utility we can get this from engineering studies etc. y = f (K, L) Max w.r.t.K,L = P f (K, L) - rK - wL
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1). 2). So profit maximisation requires that = 0 First Order Conditions: MP L =
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Similarly Or P.MP K = r Or finally i.e. Ratio of the marginal products = Ratio of the Marginal Costs
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So first order conditions (1) + (2) gives us Or in other words it tells us how much K to use given L, and how much L to use given K But not how much k and L to use
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y L MP L = w/p y K MP K = r/p L K y0y0 L0L0 K0K0 y=f(K,L)
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L OR Tells us the slope of the isoquant, but not which isoquant K yoyo y1y1
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So if in the short-run the capital stock is fixed at some amount then we can solve for ideal L and hence y y L MP L = w/p L0L0 y0y0 but what about the long run? We need something more
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2. Alternative View Recall in consumer demand, we derived a demand curve for x without any great problems? E.G.for a Cobb-Douglas utility function: Max U(x,y) s.t. P x x+ P y y=M So why can’t we do the same thing here in production
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Profit Maximisation Problem 2 Appendix to Ch 18 An alternative to first problem Maximising output subject to a cost constraint
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Isoquant Map of f (K, L) Suppose now have a constraint on output e.g. venture capitalist will only lend you £10m K yoyo y1y1 L y2y2 L0L0 K0K0
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Isoquant Map of f(K, L) =Ratio of factor prices constraint K yoyo y1y1 L
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Profit Maximisation Problem 3 Varian Appendix Ch19 Alternative to the Alternative in problem 2 Minimising Cost subject to an Output constraint
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3. Alternative to the alternative representation of the problem! General cost function: C = wL + rK K L c1c1 Iso-cost Lines Intercept will be C/r and slope – w/r For different levels of C we can draw iso-cost lines c3c3
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3. Alternative to the alternative representation of the problem! K L c1c1 Iso-cost Lines Now for a given output target, say, 10,000 units of output (a specific order for Sainsbury’s) we want to minimise costs. c3c3 yoyo Pick K & L to Minimise costs C = wL + rK subject to producing Output y 0 =f(K.L)
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So have 3 Distinct Problems 1) Maximise profits Max x1, x2 = P f (x 1, x 2 ) – w 1 x 1 – w 2 x 2 Gives factor demand functions X 1 = x 1 (w 1, w 2 ) X 2 = x 2 (w 1, w 2 ) May not be well defined if there are constant returns to scale
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2) Maximise subject to a constraint 3) Minimise subject to a constraint Problem 3) is the Dual of 2) Called Duality Theory Essentially allows us to look at problems in reverse and can often give very important insights.
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Take Problem 2: e.g (1) (2) (3)
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From 1 + 2
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Substitute into (3) This is a Cost constrained factor demand function
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Next Consider Problem 3 Minimise cost : wL + w 2 K s.t. f(x 1, x 2 ) =
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3 EQNS – 3 unknowns x 1, x 2, So solve for ‘Quantity Constrained’ Conditional factor demands X 1 = x 1 (w 1, w 2, ) X 2 = x 2 (w 1, w 2, )
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Cobb-Douglas Example (? = w 1 x 1 + w 2 x 2 + [ - x 1 a x 2 b ] FOC
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If we have CRS a + b = 1 [and notes we invert brackets when we bring it to other side] Conditional demand function for x 1
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Similarly we can solve for x 2 Re-arranging the bottom line
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Getting rid of the Power [b] on the RHS [If a+b = 1]
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Now note So conditional factor demand functions always slope down Constant – so no ‘income’ type effect
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Note can now formalise the cost function for the item C = w 1 x 1 + w 2 x 2
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