1. Jim Smith JCHS Section 7-2 spi.3.2.N http://sid.at/hs-strassburg/images/pythagoras.jpg

2. If You Have A Right Triangle, Then a² + b² = c² a b c

3. Find The Value Of X x 3 5 7 8 x 2 x 6

4. x 3 5 x² + 3² = 5² x ² + 9 = 25 x² = 16 x = 4 This is our 1 st special right Triangle 3,4,5

5. 7 8 x 7² + 8² = x² 49 + 64 = x² 113 = x² 113 = x 113 = x 10.6 = x Find The Value Of X

6. 2 x 6 2² + x² = 6² 4 + x² = 36 x² = 32 x² = 32 x = 32 = 4 2 x = 32 = 4 2 x = 5.7 x = 5.7

7. The Converse Of The Pythagorean Theorem If a² + b² = c², Then You Have A Right Triangle

8. Do These Lengths Form Right Triangles ? 5, 6, 10 6, 8, 10 5² + 6² ?? 10² 25 + 36 100 61 ≠ 100 61 ≠ 100 NO NO 6² + 8² ?? 10² 36 + 64 100 100 = 100 100 = 100 YES YES

9. If the c² = a² + b², then right If the c² is greater, then obtuse If the c² is smaller, then acute What Kind Of Triangle ? a² + b² ?? c² a² + b² ?? c²

10. 4,7,9 4,7,9 4² + 7² ?? 9² 16 + 49 ?? 81 65 81 65 81 OBTUSE OBTUSE greater

11. 5,5,7 5² + 5² ?? 7² 25 +25 ?? 49 50 ?? 49 50 ?? 49 ACUTE ACUTE SMALLER

12. A Pythagorean Triple Is Any 3 Integers That Form A Right Triangle 3, 4, 5 Family6,8,1030,40,5015,20,25 5, 12, 13 Family10,24,2625,60,6535,84,91