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Chapter 6 Test Review
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State the values of θ for which each equation is true:
1.) sin θ = ) sec θ = ) tan θ = 0 270° + 360°k 180° + 360°k 180°k 4.) Sin θ = ) Sec θ = ) Tan θ = 0 180° 0° -90°
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State the amplitude, period, and phase shift of each function.
y = -2sin θ y = 10sec θ y = -3sin4θ y = 2.5cos(θ + 180°) A = 2 P = 360° PS = 0° A = 10 P = 360° PS = 0° A = 3 P = 90° or π/2 PS = 0° A = 0.5 P = 360° or 2π PS = 60° π/3 RIGHT A = 2.5 P = 360° or 2π PS = 180° π LEFT A = 1.5 P = 90° or π/2 PS = π/16 RIGHT
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y = ±0.75cos(θ – 30°) y = ±4cos(120θ + 3600°)
Write an equation of the cosine function with amplitude, period, and phase shift given. 1. A = 0.75, P = 360°, PS = 30° 2. A = 4, P = 3°, PS = -30° y = ±0.75cos(θ – 30°) y = ±4cos(120θ °)
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Graph: ° ≤ x ≤ 360°, scale 45° 1. y = 2cos (2x – 45°) y = 2sin x + cos x X 2sinx Cosx SUM 1 90 2 180 -1 270 -2 360
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Find the values of x (0°≤x≤360°) that satisfy each equation.
1. x = arccos 1 2. arccos = x 3. arcsin ½ = x 4. sin-1 (-1) = x 5. sin-1 = x 6. cot-1 1 = x cos x = 1 0°, 360° cos x = 45°, 315° sin x = ½ 30°, 150° sin x = -1 270° cot x = 1 45°, 225° sin x = 45°, 135°
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Evaluate. Assume all angles are in quadrant I
cos (cos-1 ½) sin (cos-1 ½) cos (sin-1 ½) 4. 1/2 √3/2 √3/2 tan (45° - 45°) = tan 0° = 0
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Evaluate.
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State the domain and range of each function:
y = Cos x 2. y = Sin x 3. y = Tan x 4. y = Arccos x 5. y = Sin-1 x 6. y = Arctan x Domain: 0° ≤ x ≤ 180° Range: -1 ≤ y ≤ 1 Domain: -90° ≤ x ≤ 90° Range: -1 ≤ y ≤ 1 Domain: -90° < x < 90° Range: all reals Domain: -1 ≤ x ≤ 1 Range: 0° ≤ y ≤ 180° Domain: -1 ≤ x ≤ 1 Range: -90° ≤ y ≤ 90° Domain: all reals Range: -90° < y < 90°
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Graph y = Arccos x
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Graph y = Arcsin x
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Graph the inverse of: y = Sin (x + 90°)
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Graph the inverse of: y = Arctan x + π/4
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Determine a counterexample for the following statement:
1. Cos-1 x = Cos-1 (-x) Sin-1 x = -Sin-1 x x = 1 x = 1 x = π/2 or 90° x = 0°
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Find the inverse of each function:
1.) y = Cos (x + π) 2.) y = Sin x 3.) y = Sin θ + π/2 4.) y = Sin (x + π/2)
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Determine a value for x that would NOT produce a counterexample to the equation:
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Write an equation with a phase shift 0 to represent a simple harmonic motion under each set of circumstances. 1.) Initial pos. 12, amplitude 12, period 8 2.) Initial pos. 0, amplitude 2, period 8π 3.) Initial pos. -24, amplitude 24, period 6
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The paddle wheel of a boat measures 16 feet in diameter and is revolving at a rate of 20 rpm. If the lowest point of the wheel is 1 foot under water, write an equation in terms of cosine to describe the height of the initial point after “t” seconds.
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State the amplitude, period, frequency, and phase shift for the function:
PS =
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Write an equation with phase shift 0 to represent simple harmonic motion with initial position 0, amplitude 5, and period 3 Initial position 0 means it is a sine function. Period = 2π / k = 3 k = 2π/3
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Write an equation with phase shift 0 to represent simple harmonic motion with initial position -12, amplitude 12, and period ½ Initial position -12 means it is a cosine function. Period = 2π / k = ½ k = 4π
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The paddle wheel of a boat measures 16 feet in diameter and is revolving at a rate of
20 rpm. If the lowest point of the wheel is 1 foot under water, write an equation in terms of cosine to describe the height of the initial point after t seconds.
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Evaluate. 1/2 √3 tan (120° + 60°) = cos 180° = -1
sin (Sin-1 ½) tan (Arccos ½) Cos (tan π/4) 4. 1/2 √3 tan (120° + 60°) = cos 180° = -1
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