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Lecture 2: Economics and Optimization AGEC 352 Fall 2012 – August 27 R. Keeney
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Review Last Wednesday ◦ 2 equations, 3 unknowns ◦ Overcome this problem by making an assumption about the value of one of the unknowns Assumption: Maximize Revenue Doesn’t always work but it will for problems you see in this course Today: Similar issue but the equations are more familiar
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Functions A function f(.) takes numerical input and evaluates to a single value ◦ This is just a different notation ◦ Y = aX + bZ … is no different than ◦ f(X,Z) = aX + bZ For some higher mathematics, the distinction may be more important An implicit function like G(X,Y,Z)=0
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Basic Calculus y=f(x)= x 2 -2x + 4 ◦ This can be evaluated for any value of x f(1) = 3 f(2) = 4 We might be concerned with how y changes when x is changed ◦ When ∆X = 1, ∆Y = 1, starting from the point (1,3)
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Marginal economics In general, economic decision making focuses on changes in functions… ◦ E.g. The change in revenue vs. the change in cost If the revenue change is greater than cost, continue expanding production because the next unit will be profitable
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An Example Units SoldTotal Revenue Total CostChange in Revenue Change in Cost 155.0-- 2106.55.01.5 3159.05.02.5 42013.05.04.0 52518.55.05.5 63026.05.07.5 735405.014.0
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An Example Units Sold Total Revenue Total Cost Change in Revenue Change in Cost Profit TR-TC 155.0-- 0 2106.55.01.53.5 3159.05.02.56.0 42013.05.04.07.0 52518.55.05.56.5 63026.05.07.54 735405.014.0-5
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Graphical Analysis
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Issue Why is the peak (maximum) of the profit graph not directly above the point where Marginal Revenue = Marginal Cost ◦ Incomplete information used to generate the graph ◦ We are only considering production of whole units
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Differentiation (Derivative) Instead of the average change from x=1 to x=2 Exact change from a tiny move away from the point x = 1 ◦ We call this an instantaneous rate of change ◦ Infinitesimal change in x leads to what change in y?
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Power rule for derivatives (the only rule you need in 352) Basic rule ◦ Lower the exponent by 1 ◦ Multiply the term by the original exponent ◦ Let f’() be the 1 st derivative of f() If f(x) = ax b Then f’(x) = bax (b-1) E.g. ◦ If f(x) = 6x 3 ◦ Then f’(x) = 18x 2
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Examples f(x) = 5x 3 + 3x 2 + 9x – 18 f(x) = 2x 3 + 3y f(x) = √x
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Applied Calculus: Optimization If we have an objective of maximizing profits Knowing the instantaneous rate of change means we know for any choice ◦ If profits are increasing ◦ If profits are decreasing ◦ If profits are neither increasing nor decreasing
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Profit function p Profits
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A Decision Maker’s Information Objective is to maximize profits by sales of product represented by Q and sold at a price P that set by the producer 1. Demand is linear 2. P and Q are inversely related 3. Consumers buy 10 units when P=0 4. Consumers buy 5 units when P=5
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More information **Demand must be Q = 10 – P The producer has fixed costs of 5 The constant marginal cost of producing Q is 3
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More information Cost of producing Q (labeled C) **C = 5 + 3Q So ◦ 1) maximizing: profits ◦ 2) choice: price level ◦ 3) demand: Q = 10-P ◦ 4) costs: C= 5+3Q What next?
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We need some economics and algebra Definition of ‘Profit’? How do we simplify these equations into something like the graph below where we search for the price that delivers peak profits?
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Graphically the producer’s profit function looks like this
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Applied calculus So, calculus will let us identify the exact price to charge to make profits as large as possible Take a derivative of the profit function Solve it for zero (i.e. a flat tangent) That’s the price to charge given the function
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Relating this back to what you have learned We wrote a polynomial function for profits and took its derivative Our rule: Profits are maximized when marginal profits are equal to zero Profits = Revenue – Costs 0 = Marginal Profits = MR – MC ◦ Rewrite this and you have MR = MC
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Lab this week Will be posted to ◦ www.agecon.purdue.edu/academic/agec352 www.agecon.purdue.edu/academic/agec352 ◦ Consists of Part 1 and Part II ◦ Part I must be completed before the next class meeting ◦ Questions at the end of Part II are due the following Monday Wednesday this week due to the Labor Day Holiday
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