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… constant forces  integrate EOM  parabolic trajectories. … linear restoring force  guess EOM solution  SHM … nonlinear restoring forces  ? linear.

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Presentation on theme: "… constant forces  integrate EOM  parabolic trajectories. … linear restoring force  guess EOM solution  SHM … nonlinear restoring forces  ? linear."— Presentation transcript:

1 … constant forces  integrate EOM  parabolic trajectories. … linear restoring force  guess EOM solution  SHM … nonlinear restoring forces  ? linear spring x F nonlinear spring? x F Real Oscillators

2 The spring of air : P, V m A P atm +x 0 use Ideal Gas Law: P V=NRT chamber volume: V =Ax Stable Equilibrium at x eq = NRT / (mg + AP atm ) 0 0 EOM WTF! (whoa there, fella)

3 Taylor Series Expansions: Turns a function into a polynomial near x = a Example:

4 Expand around x = -3: 0 th order1 st order2 nd order

5 Expand around x = 2: 0 th order 1 st order 2 nd order

6 Expand N RT/x around x eq : Is it safe to linearize it? Better check a unitless ratio. How about: (Yes, excellent choice Dr. Hafner!)

7 Displacement 5% of x eq : 0.05.0025 …. SHM with Perhaps you would prefer…...

8 Simple Pendulum: Length: L Mass: m  m g c o s  T mg cos  sin  mg mg Stable Equilibrium: Displace by   mg cos  -x EOM: Expand it!

9 Derivatives:

10 Now express as a unitless ratio of the dependent variable and some parameter of the system: SHM with Displacement 5% of length: 0.05 0.0000625 …

11 The world is not linear. However, one can use a Taylor expansion to linearize an EOM by assuming only small perturbations around a point of stable equilibrium (which may not be the origin).


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