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Radial gravity inversion constrained by total anomalous mass excess for retrieving 3D bodies Vanderlei Coelho Oliveira Junior Valéria C. F. Barbosa Observatório Nacional www.on.br
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Contents Objective Methodology Real Data Inversion Result Conclusions Synthetic Data Inversion Result 3D Gravity inversion method Do the gravity data have resolution to retrieve the 3D source?
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y x N E z Depth 3D source Objective Estimate from gravity data the geometry of an isolated 3D source Gravity data Source’s top
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Methodology
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y x z y x Gravity observations g o N R 3D Source Depth S The 3D source has an unknown closed surface S. Methodology
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x z y x Gravity observations g o N R 3D Source Depth Approximate the 3D source by a set of 3D juxtaposed prisms in the vertical direction. S y Methodology
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x z y x Gravity observations g o N R 3D Source Depth We set the thicknesses and density contrasts of all prisms y Methodology
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x z y x Gravity observations g o N R 3D Source Depth y Methodology The horizontal cross-section of each prism is described by an unknown polygon The polygon sides approximately describe the edges of a horizontal depth slice of the 3D source.
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y x Gravity observations g o N R Methodology The polygon sides of an ensemble of vertically stacked prisms represent a set of juxtaposed horizontal depth slices of the 3D source. x z 3D Source Depth S y
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y x Gravity observations g o N R Methodology The polygon sides of an ensemble of vertically stacked prisms represent a set of juxtaposed horizontal depth slices of the 3D source. x z Depth y
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x z Depth y Methodology We expect that a set of juxtaposed estimated horizontal depth slices defines the geometry of a 3D source
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x z The horizontal coordinates of the polygon vertices represent the edges of horizontal depth slices of the 3D source. MethodologyDepth y jj yx, jj yx,
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The polygon vertices of each prism are described by polar coordinates Methodology x z Depth y with an arbitrary origin within the top of each prism. Arbitrary origin 1 1 r, () 2 2 r, () 3 3 r, () ( 4 4 r, ) ( 5 5 r, ) ( 6 6 r, ) ( 7 7 r, ) ( 8 8 r, )
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x z Depth y 1 1 r, () 2 2 r, () 3 3 r, () ( 4 4 r, ) ( 5 5 r, ) ( 6 6 r, ) ( 7 7 r, ) ( 8 8 r, ) The vertical component of the gravity field produced by the k th prism at the Methodology ),,,,, ( k 1 k z dz k m,, i z i y i x f k 1 k z i th observation point ( x i, y i, z i ) is given by (Plouff, 1976) dz T M k M kk 11 ][ Tkkk M k k yxrr m 001 ][ M)2(1 i g =
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The gravity data produced by the set of L vertically stacked prisms at the i th observation point ( x i, y i, z i ) is given by Methodology L k k f 1 i g = ),,,,, ( 1 k z dz k m,, i z i y i x k x z Depth y
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Methodology THE INVERSE PROBLEM Estimate the radii associated with polygon vertices x z Depth y Arbitrary origin 1 r 2 r 3 r 4 r 5 r 6 r 7 r 8 r and the horizontal Cartesian coordinates of the origin. ( x o, y o )
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y x Gravity observations Methodology By estimating the radii associated with polygon vertices and the horizontal Cartesian coordinates of the arbitrary origin from gravity data, x z 3D Source Depth y (x o, y o ) we retrieve a set of vertically stacked prisms
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The Inverse Problem )(m Parameter vector The data-misfit function The constrained inversion obtains the geometry of 3D source by minimizing : )( m 2 )( m g g o 2 The constrained function )( m = The constrained function ( m ) is defined as a sum of several constraints:
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Smoothness constraint on the adjacent radii defining the horizontal section of each vertical prism The Inverse Problem The first-order Tikhonov regularization on the radii of horizontally adjacent prisms x z Depth y 2 r 3 r 4 r 5 r 6 r 7 r 8 r 1 r This constraint favors solutions composed by vertical prisms defined by approximately circular cross-sections. 1 r 2 r
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k j r 1 k j r Inverse Problem Smoothness constraint on the adjacent radii of the vertically adjacent prisms x z Depth y The first-order Tikhonov regularization on the radii of vertically adjacent prisms This constraint favors solutions with a vertically cylindrical shape. j r j r k k+1
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Inverse Problem Smoothness constraint on the horizontal position of the arbitrary origins of the vertically adjacent prisms It imposes smooth horizontal displacement between all vertically adjacent prisms. x z Depth y ), ( 00 kk yx ), ( 0 0 k +1 y x ), ( 00 kk yx ), ( 0 0 y x
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Inverse Problem The estimation of the depth of the bottom of the geologic body x z Depth y dz zozo The interpretation model implicitly defines the maximum depth to the bottom (z max ) of the estimated body by 1...... L L. dz z max o z z How do we choose z max ? Do the gravity data have resolution to retrieve the 3D source?
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Inverse Problem The depth-to-the-bottom estimate of the geologic body 1) We assign a small value to z max, setting up the first interpretation model. g Observed gravity data zozo z max 1 z x 2) We run our inversion method to estimate a stable solution Fitted gravity data s mt z max 1 mt X s-curve 5) We repeat this procedure for increasingly larger values of z max of the interpretation model z max 2 g Observed gravity data zozo z max 2 z x Fitted gravity data g Observed gravity data zozo z max 3 z x Fitted gravity data z max 3 g Observed gravity data zozo z max 4 z x Fitted gravity data 4) We plot a point of the mt X s - curve 3) We compute the L1-norm of the data misfit ( s ) and the estimated total-anomalous mass ( mt ) z max 4 Optimum depth-to-bottom estimate
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Inverse Problem Do the gravity data have resolution to retrieve the 3D source? Correct depth-to-bottom estimate mt X s-curve L1-norm of the data misfit Estimated total-anomalous mass s ( mGal ) mt g Observed gravity data zozo z z x Fitted gravity data The gravity data are able to resolve the source’s bottom. z
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Inverse Problem Do the gravity data have resolution to retrieve the 3D source? Minimum depth-to-bottom estimate s ( mGal ) mt mt X s-curve L1-norm of the data misfit Estimated total-anomalous mass g Observed gravity data zozo z z x Fitted gravity data The gravity data are unable to resolve the source’s bottom. z
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INVERSION OF SYNTHETIC GRAVITY DATA
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Synthetic Tests Two outcropping dipping bodies with density contrast of 0.5 g/cm³. Simulated shallow-bottomed body Simulated deep-bottomed body Maximum bottom depth of 3 km Maximum bottom depth of 9 km
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Synthetic Tests Shallow-bottomed dipping body (true depth to the bottom is 3 km) The estimated total-anomalous mass ( mt ) x the L1-norm of the data misfit ( s ) s (mGal) L1-norm of the data misfit mt (kg x 10 12 ) Estimated total-anomalous mass mt X s - curve 0 0.2 0.4 0 5 10 z max = 1.0 km z max = 11.0 km z max = 2.0 km z max = 3.0 km
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s (mGal) L1-norm of the data misfit mt (kg x 10 12 ) Estimated total-anomalous mass 0 0.2 0.4 z max = 1.0 km z max = 11.0 km z max = 2.0 km z max = 3.0 km 0 5 10 Synthetic Tests Shallow-bottomed dipping body (true depth to the bottom is 3 km) Depth (km) y( km ) x( km ) Initial guess True Body mt X s - curve
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Synthetic Tests Shallow-bottomed dipping body (true depth to the bottom is 3 km) True Body Estimated body Depth (km) x( km ) y( km )
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Synthetic Tests Deep-bottomed dipping body ( true depth to the bottom is 9.0 km ) The estimated total-anomalous mass ( mt ) x the L1-norm of the data misfit ( s ) s (mGal) L1-norm of the data misfit mt (kg x 10 12 ) Estimated total-anomalous mass 0.00.20.40.60.81.01.21.4 0 5 10 15 20 25 z max = 6.0 km mt X s - curve True depth to the bottom Lower bound estimate of the depth to the bottom z max = 9.0 km
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Depth (km) x( km ) y( km ) True Body Synthetic Tests Deep-bottomed dipping body ( true depth to the bottom is 9.0 km ) 0 4.9 9.9 y( km ) x( km ) 0 4.9 9.9 By assuming two interpretation models with maximum bottom depths of 6 km and 9 km Initial guess (6 km)Initial guess (9 km) True Body Depth (km) Lower bound estimate of the depth to the bottom (6 km)True depth to the bottom (9 km) 6 km 9 km
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Synthetic Tests Deep-bottomed dipping body ( true depth to the bottom is 9.0 km ) By assuming two interpretation models with maximum bottom depths of 6 km and 9 km 0 4.9 9.9 Depth (km) y( km ) x( km ) True Body x( km ) y( km ) 0 4.9 9.9 True Body Estimated body 6 km Lower bound estimate of the depth to the bottom (6 km)True depth to the bottom (9 km) 9 km 6 km
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INVERSION OF REAL GRAVITY DATA
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Application to Real Data Real gravity-data set over greenstone rocks in Matsitama, Botswana. Study area
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Simplified geologic map of greenstone rocks in Matsitama, Botswana. (see Reeves, 1985) Application to Real Data
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20 4060 40 60 80100120 80 100 120 140 160 Northing (km) Easting (km) Gravity-data set over greenstone rocks in Matsitama (Botswana). Application to Real Data A B
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The estimated total-anomalous mass ( mt ) x the L1-norm of the data misfit ( s ) Application to Real Data s (mGal) L1-norm of the data misfit mt (kg x 10 12 ) Estimated total-anomalous mass mt X s - curve z max = 3.0 km z max = 10 km z max = 8 km
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Estimated greenstone rocks in Matsitama (Botswana). Application to Real Data Depth (km) Estimated Body Initial guess Northing (km) N Easting (km)
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Application to Real Data Northing (km) Easting (km) Northing (km) Easting (km) Estimated greenstone rocks in Matsitama (Botswana).
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Application to Real Data Northing (km) Easting (km) The fitted gravity anomaly produced by the estimated greenstone rock in Matisitama
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Conclusions
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Conclusions The proposed gravity-inversion method Estimates the 3D geometry of isolated source Introduces homogeneity and compactness constraints via the interpretation model To reduce the class of possible solutions, we use a criterion based on the curve of the estimated total-anomalous mass (mt) versus data-misfit measure (s). The solution depends on the maximum depth to the bottom assumed for the interpretation model. The correct depth-to-bottom estimate of the source is obtained if the minimum of s on the mt × s curve is well defined Otherwise this criterion provides just a lower bound estimate of the source’s depth to the bottom. Depth (km) s (mGal) L1-norm of the data misfit mt X s - curve mt (kg x 10 12 ) Estimated total-anomalous mass 0 z max = 3.0 km 0 5 10 0.2 0.4 0 4.9 9.9 Depth (km) mt (kg x 10 12 ) Estimated total-anomalous mass 0.00.20.40.60.81.01.21.4 0 5 10 15 20 25 s (mGal) L1-norm of the data misfit z max = 6 km Lower bound estimate of the depth to the bottom mt X s - curve
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Thank you for your attention
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