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Physics Vectors Javid.

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Presentation on theme: "Physics Vectors Javid."— Presentation transcript:

1 Physics Vectors Javid

2 Scalars and Vectors Temperature = Scalar
Quantity is specified by a single number giving its magnitude. Velocity = Vector Quantity is specified by three numbers that give its magnitude and direction (or its components in three perpendicular directions).

3 Properties of Vectors Two vectors are equal if they have the same magnitude and direction.

4 Adding Vectors

5 Subtracting Vectors

6 Combining Vectors

7 Using the Tip-to-Tail Rule

8 Question to think about
Question: Which vector shows the sum of A1 + A2 + A3 ?

9 Multiplication by a Scalar

10 Coordinate Systems and Vector Components
Determining the Components of a Vector The absolute value |Ax| of the x-component Ax is the magnitude of the component vector . The sign of Ax is positive if points in the positive x-direction, negative if points in the negative x-direction. The y- and z-components, Ay and Az, are determined similarly. Knight’s Terminology: The “x-component” Ax is a scalar. The “component vector” is a vector that always points along the x axis. The “vector” is , and it can point in any direction.

11 Determining Components

12 Cartesian and Polar Coordinate Representations

13 Unit Vectors Example:

14 Working with Vectors ^ A = 100 i m
B = (-200 Cos 450 i Cos 450 j ) m = (-141 i j ) m ^ ^ ^ ^ C = A + B = (100 i m) + (-141 i j ) m = (-41 i j ) m ^ ^ ^ ^ C = [Cx2 + Cy2]½ = [(-41 m)2 + (141 m)2]½ = 147 m q = Tan-1[Cy/|Cx|] = Tan-1[141/41] = 740 Note: Tan-1 Þ ATan = arc-tangent = the angle whose tangent is …

15 Tilted Axes Cx = C Cos q Cy = C Sin q

16 Arbitrary Directions

17 Perpendicular to a Surface

18 Multiplying Vectors* Given two vectors: Dot Product (Scalar Product)
Cross Product (Vector Product) A·B is B times the projection of A on B, or vice versa. (determinant)

19 Spherical Coordinates*
q R x y z f Ax Ay Az 0 £ q £ p 0 £ f £ 2p Ax= R Sin q Cos f Ay= R Sin q Sin f Az= R Cos q R = [Ax2 + Ay2 + Az2]½ = |A| = Tan-1{[Ax2 + Ay2]½/Az} f = Tan-1[Ay/Ax]

20 Cylindrical Coordinates*
q r x y z Ax Ay Az 0 £ q £ 2p Ax= r Cos q Ay= r Sin q Az= z r = [Ax2 + Ay2]½ = Tan-1[Ay/Ax] z = Az

21 Summary

22 Summary


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