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Prof. David R. Jackson ECE Dept. Spring 2014 Notes 34 ECE 6341 1
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Example By using a Fourier-transform method, the solution is where, for y > 0, (Please see the appendix.) Line current 2
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Example (cont.) The vertical wavenumber is The wavenumber k y is interpreted as A convenient change of variables is the “steepest-descent transformation” 3 (This follows from the radiation condition at infinity.)
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Example (cont.) Then The path C in the complex -plane is not unique until we choose either + or – here. This is because the path is not uniquely determined by only To see this in more detail, write 4
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Example (cont.) Because k x is real, Hence or 5
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Example (cont.) There are four possible paths. 6
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Example (cont.) k x will vary from - to along each of these paths. The path must be chosen so that along the path Assume we choose the + sign (an arbitrary choice): 7
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Example (cont.) Correct path C : 8 C
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Example (cont.) Now proceed with the change of variables: Hence, we have 9
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Example (cont.) Next, let 10
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Example (cont.) The integral then becomes Ignoring the constant in front, we can identify Hence 11
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Example (cont.) SDP: so (SDP or SAP) Hence 12
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Example (cont.) Using 13 we also see that This will help us determine which curve is the SDP and which is the SAP.
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Example (cont.) (SDP or SAP) SDP SAP 14
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Example (cont.) Examination of the original path allows us to determine the direction of integration along the SDP. 15 SDP
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Example (cont.) Calculate : From the figure we see that the correct choice is so or 16
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Example (cont.) We then have 17 or Recipe:
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Example (cont.) It can easily be verified that The exact solution is: for 18
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Appendix Derivation of formula TM z : 19
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Appendix (cont.) We then have Define: 20
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Appendix (cont.) Choose - sign for Boundary Conditions at y = 0 : (satisfied automatically) 21
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Appendix (cont.) Hence We then have 22
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Appendix (cont.) Hence And then 23
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