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Five-Minute Check (over Lesson 8–6) Then/Now New Vocabulary
Key Concept: Natural Base Functions Example 1: Write Equivalent Expressions Example 2: Write Equivalent Expressions Example 3: Simplify Expressions with e and the Natural Log Example 4: Solve Base e Equations Example 5: Solve Natural Log Equations and Inequalities Key Concept: Continuously Compounded Interest Example 6: Real-World Example: Solve Base e Inequalities Lesson Menu
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Use a calculator to evaluate log 3.4 to the nearest ten-thousandth.
B C D A B C D 5-Minute Check 1
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A B C D Solve 2x – 4 = 14. Round to the nearest ten-thousandth.
5-Minute Check 2
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A B C D Solve 42p – 1 > 11p. Round to the nearest ten-thousandth.
A. {p | p = 4} B. {p | p > } C. {p | p < } D. {p | p > } A B C D 5-Minute Check 3
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Express log4 (2. 2)3 in terms of common logarithms
Express log4 (2.2)3 in terms of common logarithms. Then approximate its value to four decimal places. A. –3.4829 B. 1.5 C D A B C D 5-Minute Check 4
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A B C D Solve for x: 92x = 45. A. B. C. D. x = 2 log 5
5-Minute Check 5
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You worked with common logarithms. (Lesson 8–6)
Evaluate expressions involving the natural base and natural logarithm. Solve exponential equations and inequalities using natural logarithms. Then/Now
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natural base exponential function natural logarithm
Vocabulary
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Concept
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A. Write an equivalent logarithmic equation for ex = 23.
Write Equivalent Expressions A. Write an equivalent logarithmic equation for ex = 23. ex = 23 → loge 23 = x ln 23 = x Answer: ln 23 = x Example 1
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B. Write an equivalent logarithmic equation for e4 = x.
Write Equivalent Expressions B. Write an equivalent logarithmic equation for e4 = x. e4 = x → loge x = 4 ln x = 4 Answer: ln x = 4 Example 1
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A B C D A. What is ex = 15 in logarithmic form? A. ln e = 15
B. ln 15 = e C. ln x = 15 D. ln 15 = x A B C D Example 1
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A B C D B. What is e4 = x in logarithmic form? A. ln e = 4 B. ln x = 4
C. ln x = e D. ln 4 = x A B C D Example 1
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A. Write ln x ≈ 1.2528 in exponential form.
Write Equivalent Expressions A. Write ln x ≈ in exponential form. ln x ≈ → loge x = x ≈ e1.2528 Answer: x ≈ e1.2528 Example 2
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B. Write ln 25 ≈ x in exponential form.
Write Equivalent Expressions B. Write ln 25 ≈ x in exponential form. ln 25 ≈ x → loge 25 = x 25 ≈ ex Answer: 25 ≈ ex Example 2
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A B C D A. Write ln x ≈ 1.5763 in exponential form. A. x ≈ 1.5763e
B. x ≈ e1.5763 C. e ≈ x1.5763 D. e ≈ x A B C D Example 2
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A B C D B. Write ln 47 = x in exponential form. A. 47 = ex B. e = 47x
C. x = 47e D. 47 = xe A B C D Example 2
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A. Write 4 ln 3 + ln 6 as a single algorithm.
Simplify Expressions with e and the Natural Log A. Write 4 ln 3 + ln 6 as a single algorithm. 4 ln 3 + ln 6 = ln 34 + ln 6 Power Property of Logarithms = ln (34 ● 6) Product Property of Logarithms = ln 486 Simplify. Answer: ln 486 Example 3
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Check Use a calculator to verify the solution.
Simplify Expressions with e and the Natural Log Check Use a calculator to verify the solution. LN ENTER ) + Keystrokes: LN ENTER ) Keystrokes: Example 3
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B. Write 2 ln 3 + ln 4 + ln y as a single algorithm.
Simplify Expressions with e and the Natural Log B. Write 2 ln 3 + ln 4 + ln y as a single algorithm. 2 ln 3 + ln 4 + ln y = ln 32 + ln 4 + ln y Power Property of Logarithms = ln (32 ● 4 ● y) Product Property of Logarithms = ln 36y Simplify. Answer: ln 36y Example 3
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A B C D A. Write 4 ln 2 + In 3 as a single logarithm. A. ln 6 B. ln 24
C. ln 32 D. ln 48 A B C D Example 3
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A B C D 1 B. Write 3 ln 3 + ln + ln x as a single logarithm. 3
__ 1 3 A. ln 3x B. ln 9x C. ln 18x D. ln 27x A B C D Example 3
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Solve 3e–2x + 4 = 10. Round to the nearest ten-thousandth.
Solve Base e Equations Solve 3e–2x + 4 = 10. Round to the nearest ten-thousandth. 3e–2x + 4 = 10 Original equation 3e–2x = 6 Subtract 4 from each side. e–2x = 2 Divide each side by 3. ln e–2x = ln 2 Property of Equality for Logarithms –2x = ln 2 Inverse Property of Exponents and Logarithms Divide each side by –2. Example 4
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Answer: The solution is about –0.3466.
Solve Base e Equations x ≈ – Use a calculator. Answer: The solution is about – Example 4
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A B C D What is the solution to the equation 2e–2x + 5 = 15?
Example 4
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A. Solve 2 ln 5x = 6. Round to the nearest ten-thousandth.
Solve Natural Log Equations and Inequalities A. Solve 2 ln 5x = 6. Round to the nearest ten-thousandth. 2 ln 5x = 6 Original equation ln 5x = 3 Divide each side by 2. eln 5x = e3 Property of Equality for Exponential Functions 5x = e3 eln x = x Divide each side by 5. x ≈ Use a calculator. Answer: about Example 5
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ln (3x + 1)2 > 8 Original equation
Solve Natural Log Equations and Inequalities B. Solve the inequality ln (3x + 1)2 > 8. Round to the nearest ten-thousandth. ln (3x + 1)2 > 8 Original equation eln (3x + 1)2 > e8 Write each side using exponents and base e. (3x + 1)2 > (e4)2 eln x = x and Power of of Power 3x + 1 > e4 Property of Inequality for Exponential Functions 3x > e4 – 1 Subtract 1 from each side. Example 5
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Divide each side by 3. x > 17.8661 Use a calculator.
Solve Natural Log Equations and Inequalities Divide each side by 3. x > Use a calculator. Answer: x > Example 5
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A. Solve the equation 3 ln 6x = 12. Round to the nearest ten-thousandth.
B C D A B C D Example 5
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B. Solve the inequality ln (4x –2) > 7
B. Solve the inequality ln (4x –2) > 7. Round to the nearest ten-thousandth. A. x > B. x > C. x > D. x < A B C D Example 5
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Concept
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A = Pert Continuously Compounded Interest formula
Solve Base e Inequalities A. SAVINGS Suppose you deposit $700 into an account paying 3% annual interest, compounded continuously. What is the balance after 8 years? A = Pert Continuously Compounded Interest formula = 700e(0.03)(8) Replace P with 700, r with 0.03 and t with 8. = 700e0.24 Simplify. ≈ Use a calculator. Answer: The balance after 8 years will be $ Example 6
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The balance is at least $1200.
Solve Base e Inequalities B. SAVINGS Suppose you deposit $700 into an account paying 3% annual interest, compounded continuously. How long will it take for the balance in your account to reach at least $1200? The balance is at least $1200. A ≥ 1200 Write an inequality. Replace A with 700e(0.03)t. Divide each side by 700. Example 6
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Property of Inequality for Logarithms
Solve Base e Inequalities Property of Inequality for Logarithms Inverse Property of Exponents and Logarithms Divide each side by 0.03. t ≥ Use a calculator. Answer: It will take about 18 years for the balance to reach at least $1200. Example 6
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A = Pert Continuously Compounded Interest formula
Solve Base e Inequalities C. SAVINGS Suppose you deposit $700 into an account paying 3% annual interest, compounded continuously. How much would have to be deposited in order to reach a balance of $1500 after 12 years? A = Pert Continuously Compounded Interest formula 1500 = P ● e0.03 ● 12 A = 1500, r = 0.003, and t = 12 Divide each side by e0.36. Example 6
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Answer: You need to deposit $1046.51.
Solve Base e Inequalities ≈ P Use a calculator. Answer: You need to deposit $ Example 6
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A. SAVINGS Suppose you deposit $700 into an account paying 6% annual interest, compounded continuously. What is the balance after 7 years? A. $46,058.59 B. $46,680.43 C. $ D. $365.37 A B C D Example 6
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B. SAVINGS Suppose you deposit $700 into an account paying 6% annual interest, compounded continuously. How long will it take for the balance in your account to reach at least $2500? A. at least 1.27 years B. at least 7.50 years C. at least years D. at least years A B C D Example 6
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C. SAVINGS Suppose you deposit money into an account paying 3% annual interest, compounded continuously. How much would have to be deposited in order to reach a balance of $1950 after 10 years? A. $ B. $ C. $ D. $ A B C D Example 6
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