Presentation is loading. Please wait.

Presentation is loading. Please wait.

Gas Laws Practice Problems 1) Work out each problem on scratch paper. 2) Click ANSWER to check your answer. 3) Click NEXT to go on to the next problem.

Similar presentations


Presentation on theme: "Gas Laws Practice Problems 1) Work out each problem on scratch paper. 2) Click ANSWER to check your answer. 3) Click NEXT to go on to the next problem."— Presentation transcript:

1 Gas Laws Practice Problems 1) Work out each problem on scratch paper. 2) Click ANSWER to check your answer. 3) Click NEXT to go on to the next problem. P 1 V 1 T 2 = P 2 V 2 T 1 CLICK TO START

2 1 2 3 4 5 6 7 8 9 10 Helium occupies 3.8 L at -45°C. What volume will it occupy at 45°C? ANSWER QUESTION #1

3 1 2 3 4 5 6 7 8 9 10 ANSWER #1 V 1 = 3.8 L T 1 = -45°C = 228 K V 2 = ? T 2 = 45°C = 318 K NEXT CHARLES’ LAW P 1 V 1 T 2 = P 2 V 2 T 1 V 2 = 5.3 L BACK TO PROBLEM

4 1 2 3 4 5 6 7 8 9 10 Ammonia gas occupies a volume of 450. mL at 720. mm Hg. What volume will it occupy at standard pressure? ANSWER QUESTION #2

5 1 2 3 4 5 6 7 8 9 10 ANSWER #2 V 1 = 450. mL P 1 = 720. mm Hg V 2 = ? P 2 = 760. mm Hg NEXT BOYLE’S LAW P 1 V 1 T 2 = P 2 V 2 T 1 V 2 = 426 mL BACK TO PROBLEM

6 1 2 3 4 5 6 7 8 9 10 A gas at STP is cooled to -185°C. What pressure in atmospheres will it have at this temperature (volume remains constant)? ANSWER QUESTION #3

7 1 2 3 4 5 6 7 8 9 10 ANSWER #3 P 1 = 1 atm T 1 = 273 K P 2 = ? T 2 = -185°C = 88 K NEXT GAY-LUSSAC’S LAW P 1 V 1 T 2 = P 2 V 2 T 1 P 2 = 0.32 atm BACK TO PROBLEM

8 1 2 3 4 5 6 7 8 9 10 A gas occupies 1.5 L at 850 mm Hg and 15°C. At what pressure will this gas occupy 2.5 L at 30.0°C? ANSWER QUESTION #4

9 1 2 3 4 5 6 7 8 9 10 ANSWER #4 V 1 = 1.5 L P 1 = 850 mm Hg T 1 = 15°C = 288 K P 2 = ? V 2 = 2.5 L T 2 = 30.0°C = 303 K NEXT COMBINED GAS LAW P 1 V 1 T 2 = P 2 V 2 T 1 P 2 = 540 mm Hg BACK TO PROBLEM

10 1 2 3 4 5 6 7 8 9 10 Chlorine gas has a pressure of 1.05 atm at 25°C. What pressure will it exert at 75°C? ANSWER QUESTION #5

11 1 2 3 4 5 6 7 8 9 10 ANSWER #5 P 1 = 1.05 atm T 1 = 25°C = 298 K P 2 = ? T 2 = 75°C = 348 K NEXT GAY-LUSSAC’S LAW P 1 V 1 T 2 = P 2 V 2 T 1 P 2 = 1.23 atm BACK TO PROBLEM

12 1 2 3 4 5 6 7 8 9 10 A gas occupies 256 mL at 720 torr and 25°C. What will its volume be at STP? ANSWER QUESTION #6

13 1 2 3 4 5 6 7 8 9 10 ANSWER #6 V 1 = 256 mL P 1 = 720 torr T 1 = 25°C = 298 K V 2 = ? P 2 = 760. torr T 2 = 273 K NEXT COMBINED GAS LAW P 1 V 1 T 2 = P 2 V 2 T 1 V 2 = 220 mL BACK TO PROBLEM

14 1 2 3 4 5 6 7 8 9 10 At 27°C, fluorine occupies a volume of 0.500 dm 3. To what temperature in degrees Celsius should it be lowered to bring the volume to 200. mL? ANSWER QUESTION #7

15 1 2 3 4 5 6 7 8 9 10 ANSWER #7 T 1 = 27ºC = 300. K V 1 = 0.500 dm 3 T 2 = ?°C V 2 = 200. mL = 0.200 dm 3 NEXT CHARLES’ LAW P 1 V 1 T 2 = P 2 V 2 T 1 T 2 = -153°C (120 K) BACK TO PROBLEM

16 1 2 3 4 5 6 7 8 9 10 A gas occupies 125 mL at 125 kPa. After being heated to 75°C and depressurized to 100.0 kPa, it occupies 0.100 L. What was the original temperature of the gas? ANSWER QUESTION #8

17 1 2 3 4 5 6 7 8 9 10 ANSWER #8 V 1 = 125 mL P 1 = 125 kPa T 2 = 75°C = 348 K P 2 = 100.0 kPa V 2 = 0.100 L = 100. mL T 1 = ? NEXT COMBINED GAS LAW P 1 V 1 T 2 = P 2 V 2 T 1 T 1 = 544 K (271°C) BACK TO PROBLEM

18 1 2 3 4 5 6 7 8 9 10 ANSWER QUESTION #9 A 3.2-L sample of gas has a pressure of 102 kPa. If the volume is reduced to 0.65 L, what pressure will the gas exert?

19 1 2 3 4 5 6 7 8 9 10 ANSWER #9 V 1 = 3.2 L P 1 = 102 kPa V 2 = 0.65 L P 2 = ? NEXT BOYLE’S LAW P 1 V 1 T 2 = P 2 V 2 T 1 P 2 = 502 kPa BACK TO PROBLEM

20 1 2 3 4 5 6 7 8 9 10 A gas at 2.5 atm and 25°C expands to 750 mL after being cooled to 0.0°C and depressurized to 122 kPa. What was the original volume of the gas? ANSWER QUESTION #10

21 1 2 3 4 5 6 7 8 9 10 ANSWER #10 P 1 = 2.5 atm T 1 = 25°C = 298 K V 2 = 750 mL T 2 = 0.0°C = 273 K P 2 = 122 kPa = 1.20 atm V 1 = ? EXIT COMBINED GAS LAW P 1 V 1 T 2 = P 2 V 2 T 1 V 1 = 390 mL BACK TO PROBLEM

22 Ideal Gas Law & Gas Stoichiometry 1) Work out each problem on scratch paper. 2) Click ANSWER to check your answer. 3) Click NEXT to go on to the next problem. PV = nRT R = 0.0821 L  atm/mol  K = 8.315 dm 3  kPa/mol  K CLICK TO START

23 1 2 3 4 5 6 7 8 9 10 Tire of car contains nitrogen, oxygen, carbon dioxide and argon. The total pressure of the tire is 93.6 kPa. The partial pressures of nitrogen, oxygen & carbon dioxide are 15.4 kPa, 90 mmHg and.356 atm. resp. What is the partial pressure exerted by argon? Given P- total = 93.6KPa P N = 15.4 kPa P O = 90 mmHg P CO2 =.356 atm Solve : P total = P 1 + P 2 + P 3 + P 4

24 1 2 3 4 5 6 7 8 9 10 How many grams of CO 2 are produced from 75 L of CO at 35°C and 96.2 kPa? 2CO + O 2  2CO 2 ANSWER QUESTION #1

25 1 2 3 4 5 6 7 8 9 10 Find the new molar volume: n = 1 mol V = ? P = 96.2 kPa T = 35°C = 308 K R = 8.315 dm 3  kPa/mol  K CONTINUE... PV = nRT V = 26.6 L/mol BACK TO PROBLEM ANSWER #1

26 1 2 3 4 5 6 7 8 9 10 NEXTBACK TO PROBLEM ANSWER #1 (con’t) 75 L CO 1 mol CO 26.6 L CO = 120 g CO 2 2 mol CO 2 2 mol CO 44.01 g CO 2 1 mol CO 2 2CO + O 2  2CO 2 75 L? g

27 1 2 3 4 5 6 7 8 9 10 How many moles of oxygen will occupy a volume of 2.5 L at 1.2 atm and 25°C? ANSWER QUESTION #2

28 1 2 3 4 5 6 7 8 9 10 n = ? V = 2.5 L P = 1.2 atm T = 25°C = 298 K R = 0.0821 L  atm/mol  K NEXT PV = nRT n = 0.12 mol BACK TO PROBLEM ANSWER #2

29 1 2 3 4 5 6 7 8 9 10 What volume will 56.0 grams of nitrogen (N 2 ) occupy at 96.0 kPa and 21°C? ANSWER QUESTION #3

30 1 2 3 4 5 6 7 8 9 10 V = ? n = 56.0 g = 2.00 mol P = 96.0 kPa T = 21°C = 294 K R = 8.315 dm 3  kPa/mol  K NEXT PV = nRT V = 50.9 dm 3 BACK TO PROBLEM ANSWER #3

31 1 2 3 4 5 6 7 8 9 10 What volume of NH 3 at STP is produced if 25.0 g of N 2 is reacted with excess H 2 ? N 2 + 3H 2  2NH 3 ANSWER QUESTION #4

32 1 2 3 4 5 6 7 8 9 10 25.0 g N 2 NEXTBACK TO PROBLEM ANSWER #4 1 mol N 2 28.02 g N 2 = 40.0 L NH 3 N 2 + 3H 2  NH 3 2 mol NH 3 1 mol N 2 22.4 L NH 3 1 mol NH 3 25.0 g? L

33 1 2 3 4 5 6 7 8 9 10 What volume of hydrogen is produced from 25.0 g of water at 27°C and 1.16 atm? 2H 2 O  2H 2 + O 2 ANSWER QUESTION #5

34 1 2 3 4 5 6 7 8 9 10 Find the new molar volume: n = 1 mol V = ? P = 1.16 atm T = 27°C = 300. K R = 0.0821 L  atm/mol  K CONTINUE... PV = nRT V = 21.2 L/mol BACK TO PROBLEM ANSWER #5

35 1 2 3 4 5 6 7 8 9 10 NEXTBACK TO PROBLEM ANSWER #5 (con’t) 25.0 g H 2 O 1 mol H 2 O 18.02 g H 2 O = 29.4 L H 2 2 mol H 2 2 mol H 2 O 21.2 L H 2 1 mol H 2 2H 2 O  2H 2 + O 2 25.0 g? L

36 1 2 3 4 5 6 7 8 9 10 How many atmospheres of pressure will be exerted by 25 g of CO 2 at 25°C and 0.500 L? ANSWER QUESTION #6

37 1 2 3 4 5 6 7 8 9 10 P = ? n = 25 g = 0.57 mol T = 25°C = 298 K V = 0.500 L R = 0.0821 L  atm/mol  K NEXT PV = nRT P = 28 atm BACK TO PROBLEM ANSWER #6

38 1 2 3 4 5 6 7 8 9 10 How many grams of CaCO 3 are required to produce 45.0 L of CO 2 at 25°C and 2.3 atm? CaCO 3 + 2HCl  CO 2 + H 2 O + CaCl 2 ANSWER QUESTION #7

39 1 2 3 4 5 6 7 8 9 10 Find the new molar volume: n = 1 mol V = ? P = 2.3 atm T = 25°C = 298 K R = 0.0821 L  atm/mol  K CONTINUE... PV = nRT V = 11 L/mol BACK TO PROBLEM ANSWER #7

40 1 2 3 4 5 6 7 8 9 10 NEXTBACK TO PROBLEM ANSWER #7 45.0dm 3 CO 2 1 mol CO 2 11 dm 3 CO 2 = 410 g CaCO 3 CaCO 3 + 2HCl  CO 2 + H 2 O + CaCl 2 1 mol CaCO 3 1 mol CO 2 100.09 g CaCO 3 1 mol CaCO 3 ? g45.0 dm 3

41 1 2 3 4 5 6 7 8 9 10 Find the number of grams of CO 2 that exert a pressure of 785 torr at 32.5 L and 32°C. ANSWER QUESTION #8

42 1 2 3 4 5 6 7 8 9 10 n = ? P = 785 torr = 1.03 atm V = 32.5 L T = 32°C = 305 K R = 0.0821 L  atm/mol  K NEXT PV = nRT n = 1.34 mol  59.0 g CO 2 BACK TO PROBLEM ANSWER #8


Download ppt "Gas Laws Practice Problems 1) Work out each problem on scratch paper. 2) Click ANSWER to check your answer. 3) Click NEXT to go on to the next problem."

Similar presentations


Ads by Google