1. An introduction to integration Thursday 22 nd September 2011 Newton Project

2. How to find the area under the curve In this presentation we are going to look at how we can find the area under a curve. In this case the area we are looking to find is the area bounded by both the x – axis and the y-axis. We will then consider how integration might help us do this.

3. Using rectangles to estimate the area Maybe we could divide the area into rectangles?

4. Can we make the approximation better? Insert YouTube Mr Barton’s Maths – Area under a curve

5. Is there a better way? Hint.....Area of a trapezium A trapezium is a quadrilateral that has only one pair of parallel sides.trapeziumquadrilateralparallel Consider the area of the following trapezium. Area of a Trapezium = (a+b) x h 2 h a b

6. Deriving the Formula Area of a Trapezium: ½ h( a+b) T1 = ½ h(y 0 +y 1 ) T2 = ½ h(y 1 +y 2 ) T3 = ½ h(y 2 +y 3 ) … T4 = ½ h(y n-1 +y n ) Whole Area is the addition All of the Trapeziums: A= ½ h(y 0 +y 1 +y 1 +y 2 +y 2 +y 3 + y n-1 +y n ) A = ½ h(y 0 + 2(y 1 +y 2 +y 3 +y n-1 )+ y n )

7. Now some examples!

8. The next part of this presentation explains the concept of integration, and how we can use integration to find the area under a curve instead of using the trapezium rule.

9. Consider a typical element bounded on the left by the ordinate through a general point P(x,y). The width of the element represents a small increase in the value of x and can be called and so can be called Also, if A represents the area up to the ordinate through P, then the area of the element represents a small increase in the value of x and so can be called A typical strip is approximately a rectangle of height y and width Therefore, for any element The required area can now be found by adding the areas of all the strips from x=a to x=b x=ax=b P(x,y)

10. Therefore, for any element The required area can now be found by adding the areas of all the strips from x=a to x=b The notation for the Total Areas is so as gets smaller the accuracy of the results increases Until in the limiting case Total Area =

11. can also be written as As gets smaller But so Therefore The boundary values of x defining the total area are x=a and x=b so this is more correctly written as