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Published byAnthony May Modified over 9 years ago
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Design Example: Inductor Design Specs L=100 H I DC = 5 A I = 0.75 A p-p B max = 0.25 T = 0.25 x 10 -6 wb/mm 2 J max = 6.0A/mm 2 f s = 100kHz k w = 0.5 Catalog Link
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This would be 18 gauge wire, which is pretty stiff. The author suggests 5 strands of 25 gauge (0.162 mm 2 )
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Design Example: Transformer Design Specs v 1 = v 2 = v 3 = 30 v I RMS = 2.5 A B max = 0.25 T = 0.25 x 10 -6 wb/mm 2 J max = 5.0A/mm 2 f s = 100kHz k w = 0.5 k c = 0.5
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This would be 20 gauge wire. The author suggests 3 strands of 25 gauge (0.162 mm 2 )
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Design Example: Transformer Design Specs Primary : 28 v, Secondary A: 5 v @ 6 A, Secondary B: 12 v @ 2.75 A Primary current: I p = 6(5/28)+2.75(12/28) = 2.25A B max = 0.25 T = 0.25 x 10 -6 wb/mm 2 J max = 6.0A/mm 2 f s = 50kHz k w = 0.6 k c = 0.5 E Core:
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Wire Cross Section: 21 Gauge 17 Gauge 20 Gauge Check Fill Factor with actual turns and Wire sizes:
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