2. Aim: Percent Course: Math Literacy Aim: How to Solve Problems Containing Percents Do Now: Convert: Fraction to Decimal to Percent

3. Aim: Percent Course: Math Literacy Expressing a Fraction as a Percent 1.Divide the numerator by the denominator. 2.Multiply the quotient by 100. This is done by moving the decimal point in the quotient two places to the right. 3.Add a percent sign. Expressing a Decimal as a Percent 1.Move the decimal point two places to the right. 2.Add a percent sign.

4. Aim: Percent Course: Math Literacy P x N = R P ercent N umber R esult 50% of 200 is 100 x=.50 x 200 = 100

5. Aim: Percent Course: Math Literacy 50 x 200 = ? To find the Percent of a Number, change the Percent to a decimal then multiply by the Number to get the Result. What is 50% of 200? = 100 (.50)200 = R Percent x Number = Result % of number = result What is 6% of 200? What is 2.3% of 50? What is 42% of 80?.06.023.42 x x x 200 50 80 = = = 12 1.15 33.6 Finding Result Given Percent and Number

6. Aim: Percent Course: Math Literacy 5% of a Number is 12. Find the Number. Percent x Number = Result 5%12Nofis.0512N x = Model Problem

7. Aim: Percent Course: Math Literacy To find the Percent when given the Number and Result, divide the Result by the Number and change the fraction to a Percent. What percent of 200 is 100? Number x Percent = Result.50 5010 1215 4213 6015 2518 200P = 100 P = 100/200 ? ? ? ? ?.20.80.31.25.647 Finding Percent Given Number & Result 200 x = 100 ?

8. Aim: Percent Course: Math Literacy Convert the Percent to a decimal, divide Percent into the Result to find Number 100 is 50% of what Number? Number x Percent = Result x. 50 = 100 200 N(.50) = 100 ? 6.05 45 ? ? 8 ? 30 ? 8.30.10.16.15 N = 100/.50 120 150 80 200 50 Finding Number Given Percent & Result ?

9. Aim: Percent Course: Math Literacy Of the 560 seniors in Village High School, 476 attended the senior prom. What percent of the senior class attended the prom? P ercent N umber R esult x= N = 560R = 476 What percent of the senior class.. P = ? Model Problem

10. Aim: Percent Course: Math Literacy A dealer sold a radio for $39.20, which was 40% above its cost to him. Find the cost of the radio to the dealer. $39.20.40xx Cost + + Markup = = Selling Price += 1.40x = 39.20 1.40 x = 28.00 Model Problem 1.40

11. Aim: Percent Course: Math Literacy In a school, there are 60 pupils who participate in a certain activity. If this is 12% of the student body, How many students are there in the school? P ercent N umber R esult x= 12%60 x N Student Body =.12(N) = 60.12 N = 500 Student Body Model Problem.12

12. Aim: Percent Course: Math Literacy A jacket regularly sells for $135. The sale price is $60.75. Find the percent decrease of the sale price from the regular price. Finding Percent Increase or Decrease 1)Find the fraction for the percent increase or decrease. 1)Find the percent increase or decrease by expressing the fraction in step 1 as a percent

13. Aim: Percent Course: Math Literacy At a Forest Service Youth Camp many of the workers ate some meals away from the base camp. In the dining hall at the base camp, 5% of the workers had breakfast only, 3% had lunch only, and 2% had supper only. Just 10% of the workers ate all three meals in camp. There were 5000 meals served at the base camp dining hall. No worker missed all three meals. How many workers were assigned to the Youth Camp? Let x = the number of workers (.05) x = # eating breakfast only (.03) x = # eating lunch only (.02) x = # eating supper only (.10) x = # eating 3 meals (.80) x = # eating 2 meals 2x = 5000 x = 2500 Model Problem 1(.10x)+ 3(.10x)+ 2(.80x) = 5000 1 meal2 meals3 meals

14. Aim: Percent Course: Math Literacy Venn Diagram U 0% B L Model Problem S 5% 3% 10% 2% B & L L & SB & S 250150 100 11 1 22 2 3 250 + 150 + 100 = 500 workers  500 meals 2 or more 4500 meals = 10xx = 45