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Published byPatience Eaton Modified over 9 years ago
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If E and F are two independent events with P(E)=.2 and P(F)=.4 find: 1) P(E|F) 2) P(F|E) 3) P(E∩F) 4) P(EUF) 1).22..4 3).083).52 WARM UP:
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SWBAT compute a z-score, use the standard normal curve, and approximate the binomial distribution. 9.6 THE NORMAL DISTRIBUTION
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Bell shaped and symmetric with respect to mean. Mean, median and mode are equal. Area enclosed by x-axis and curve’s = 1sq unit. Probability that an outcome of a normally distributed curve is between b and a equals the area associated w the curve from x=a to x = b. Standard deviation plays a major role in describing the area under the curve. PROPERTIES OF NORMAL DISTRIBUTION:
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STANDARD DEVIATION RELATED TO AREA UNDER A NORMAL CURVE: µ-3σ µ-2σ µ-σµ+σ µ+2σ µ+3σ µ 2.14% 13.59% 34.135%
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Z-SCORE: (A GROUP MEAN) Z- score transforms any normal value with a mean and standard deviation to a normal value with mean 0 and standard deviation 1.
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ON A TEST, 80 IS THE MEAN AND 6 IS THE STANDARD DEVIATION.
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See the Z-Score Table. FIND THE AREA, THAT IS FIND THE PROPORTION OF CASES INCLUDED BETWEEN THE GIVEN VALUES: 1.2 1.940
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At 1.2: 0.3849 At 1.94: 0.4738 So we will subtract the two since.3849 is the area from 0 to 1.2 and.4738 is the area from 0 to 1.94. .4738 -.3849 =.0889 FIND TWO VALUES: SCORE AT 1.2 AND THE SCORE AT 1.94.
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SCORES ON A TEST ARE NORMALLY DISTRIBUTED WITH A MEAN OF 75 AND A STANDARD DEVIATION OF 8. WHAT IS THE PROBABILITY THAT A TEST CHOSEN AT RANDOM IS BETWEEN 80 AND 90?
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*Keep your Z- score chart to use on your test!! HW WS 9.6: 1,3, 5A-C, 7A-C, 9,11,13, 15A-C, 19
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