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Similar Triangles.  To solve a proportions  Cross multiply  Solve.

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Presentation on theme: "Similar Triangles.  To solve a proportions  Cross multiply  Solve."— Presentation transcript:

1 Similar Triangles

2  To solve a proportions  Cross multiply  Solve

3

4 1. Write the proportions for corresponding sides 2. Solve the proportion

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6

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8 The geometric mean of two numbers is the square root of the product of the numbers.

9 Find the geometric mean of the two numbers. Simplify your answer. 1.7 and 35

10 Right Triangles

11 a 2 + b 2 = c 2 c a b

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13 Sin A = Cos A = Tan A =

14 Find the value of sine, cosine, and tangent ratios to the nearest hundredth.

15 If you know two sides and one angle:  To find the missing side use Pythagorean theorem: a 2 + b 2 = c 2  To find the two angles use inverse trigonometric functions: Angle = Sin -1 Angle = Cos -1 Angle = Tan -1

16 If you know two angles and one side:  To find the missing angle: Add the two angles and subtract from 180 0  To find the two missing sides use the trigonometric ratios. Sin angle = Cos angle = Tan angle =

17 Solve each triangle for all the missing information. Round your answer to the nearest tenth.

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19 Circles

20  Central Angle Angle = Arc  Inscribed Angle Angle = ½ Arc  Inside the circle Angle = ½ (sum of the arcs)  Outside the circle Angle = ½ (difference of the arcs)

21 Find the measure of the missing angle or arc.

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24  Inside the circle Part ∙ Part = Part ∙ Part  Outside the circle Outside ∙ Whole = Outside ∙ Whole E C A B D

25 Solve for x.

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27  C = 2  r B A

28 Find the length of arc BC. Leave your answer in terms of  7 in 40 o

29  A =  r 2 P D C

30 Find the area of the shaded region. Leave your answer in terms of  7 in 30 0

31 Area of Polygons

32  Circle  C = 2  r  A =  r 2  Squares  P = 4s  A = s 2  Rectangles  P = 2L + 2W  A = L W r s L W

33  Parallelograms  P = 2b + 2 l  A = b h  Trapezoids  P = add up all 4 sides  A = ½ (b 1 + b 2 ) h  Triangles  P = a + b + c  A = ½ b h b l h b2b2 b1b1 h a c b

34  P = 3s  A = ¼ s 2 √3 s

35  Given side length and apothem  P = n s  A = n [ ½ (s)(a)] as

36  Given side length only  P = n s  To find a   n 2. x = s/2 3. a = x/tan  4. A = n [ ½ (s)(a)] s 

37 Find the perimeter and area of each polygon. 1.

38 2.

39 Find the area of the regular polygons. 1. 2 ft

40 Surface Area & Volume

41  B = Area of the Base  Base is the shape not like the others Base does not mean the bottom shape Base is not one number it is an area (use the previous chapter)  P = Perimeter of the Base  h = height of the polyhedron  l = slant height of the polyhedron

42  Prism  SA = 2B + Ph  V = Bh  Pyramid  SA = B + ½ P l  V = 1/3 B h l

43  Cylinder  SA = 2  r 2 + 2  r h  V =  r 2 h  Cone  SA =  r 2 +  r l  V = 1/3  r 2 h r h l h r

44  Sphere  SA = 4  r 2  V = 4/3  r 3 r

45 Find the surface area and volume of the right prism. 1. 5 in 9 in 2 in

46 Find the surface area and volume of the right pyramid. 1. 7 in 9 in


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