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CON 4003 Construction Estimating Prof R. V. Locurcio.

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Presentation on theme: "CON 4003 Construction Estimating Prof R. V. Locurcio."— Presentation transcript:

1 CON 4003 Construction Estimating Prof R. V. Locurcio

2 Consists of a water resistent coat that is sprayed or brushed onto the exterior of the foundation to prevent moisture intrusion into the building

3 Sprayed or rolled-on waterproofing …bid by the square ft. Waterproof membranes and building paper …bid as a sheet or roll good

4 A vapor barrier is often used to refer to any material for damp proofing, typically a plastic or foil sheet, that resists penetration of moisture through the wall, ceiling or floor assemblies of buildings

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6 Where: Behind masonry or siding Under shingles Between insulation and inside finish of exterior walls Must be lapped to be effective

7 Fiberglass Drain boardBuilding paperDrain system Waterproof membrane or building paper used to establish the waterproofing system

8 Problem 9-1 How much waterproofing is needed to cover the foundation walls of a 24-foot by 50-foot basement? The wall is 8 feet high. The wall sits on a footing that is 12 inches high and extends 16 inches beyond the wall on the exterior side. Assume that the waterproofing starts 12 inches below the top of the foundation wall and covers the top surface of the footings. If one gallon of waterproofing material covers 75 square feet, how many gallons of waterproofing material are needed ? Solution: L= 50ft, W= 24ft, Perimeter = (50+24+50+24) = 148 LF The height of the waterproofing = 8ft -1ft+ (16in)/(12 in/ft) = 8.33 LF The area of waterproofing = 148 ft x 8.33ft = 1232.84 SF Add four 16in by 16in corners on the top of the footing Total area = 1232.84 + 4 x((16/12) x(16/12)) = 1240 SF Quantity = = 16.6 gallons Water proofing 1240 SF 75 gal/SF A-A Cross section of foundation

9 Fiberglass Batt Insulation paperbacked so to be installed with the paper on the interior side of wall Blown Insulation fiberglass shredded newspaper spun rock Exterior Insulation Finish System Consists of a rigid insulation layer covered with a synthetic stucco system. The stucco system includes a base coat a reinforcing layer, a brown coat, and a colored finish coat.

10 Fiberglass Batt insulation Paperbacked or Unfaced Common size precut 15” & 23” Blown Insulation Made from Fiberglass shredded newspaper, and blown rock. Spray Foam Insulation Made from Isocyanate & Polyol Resin

11 Problem 9-6 How many rolls of insulation are needed for Problem 5 if the insulation comes in rolls 15 inches wide and 32 feet long? Don’t include the waste factor. The number of rows is one row 8 feet high. The number of columns is calculated using Eq. (4-17) as follows: The stud spacing is 16” Number columns = (25 ft) (12 in/ft) (15in + 1in ) =18.75 Columns 19 number of sheets of 8-foot by 15 in-wide insulation. The length of roll is 32ft, so 4 sheets from each roll: No. of rolls = 19 4 = 4.75 ~ 5 rolls Solution: The length of wall = 25ft, height = 8ft

12 16” 25LF 8LF 16” 25LF X 12”/LF = 300 inches Panels = 300/16 = 18.75 or 19 panels Roll = 32 LF / 8 = 4 panels /roll Rolls = 19 / 4 = 4.75 = 5 rolls

13 Exterior Insulation Finish System “Consists of a rigid insulation layer covered with a synthetic stucco system.” “The stucco system includes a base coat a reinforcing layer, a brown coat, and a colored finish coat.”

14 Asphalt Shingles specified by expected life 20, 25, 30- year three tab or architectural Flashing required at all penetrations vent pipes intersections with wall or chimney Drip Edge required at all edges including gable end Starter Shingles required for all roof edges that are parallel to the rows of shingles. placed on the roof edges then completely covered up by first layer of shingles

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18 Hip Roof is a type of roof where all sides slope downwards to the walls, usually with a fairly gentle slope

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20 Slope greater then 2:12 and less than 4:12  The felt must be lapped 19 in Slope greater than or equal to 4:12  The felt must be lapped 2 in Length sloped = Lenght plan view (1+ Slope^2)^0.5 Area surface = Area plan view (1+ Slope^2)^0.5 Hips and Valleys increase the waste To do a proper takeoff for a roof, each roof surface must be taken off individually

21 Area of roof: 1.Separate into sections 2.Calc flat SF of each 3.Calc roof slope 4.Multiply flat SF by elevation factor Area A = 40’ x 28’ = 1120 SF Area B = 12’ x 6’ = 72 SF Total SF = 1192 SF Roof slope = 4:12 r = (16 + 144) ½ = 12.64 Factor = 12.64/12 = 1.054 Roof Area = (1120 + 72) x 1.054 = 1192 x 1.054 = 1256.36 or 1256 SF or 12.56 or 23 SQ Area A Area B

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24 Vinyl Soffit Aluminum Fascia

25 Soffit

26 Example Problem

27 4.67’ 4 12 Part B 4’ 8’ W 4’X4’ D 6’X6’ 8”

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